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2.1 Equations of straight linesIB Maths: Analysis and Approaches HL: Subtopic test

10 questions, 27 marks

IB Maths: Analysis and Approaches HL

2.1 Equations of straight lines

Total 27 marks

Name

Class

Date

  1. 1
    The line L1L_1 has equation 3x−4y+12=03x - 4y + 12 = 0.
    (a)
    Find the gradient of L1L_1.
    [1 mark]
    • A−34-\frac34
    • B34\frac34
    • C43\frac43
    • D33
    (b)
    Find the yy-intercept of L1L_1.
    [1 mark]
    • A33
    • B−3-3
    • C1212
    • D−4-4
    (c)
    The line L2L_2 is perpendicular to L1L_1 and passes through the point (6,−1)(6, -1). Find the equation of L2L_2, giving your answer in the form ax+by+d=0ax + by + d = 0, where a,b,d∈Za, b, d\in\mathbb{Z}.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The points P(−2,5)P(-2, 5) and Q(4,−7)Q(4, -7) lie on the straight line LL.
    (a)
    Find the gradient of LL.
    [1 mark]
    • A22
    • B−12-\frac12
    • C12\frac12
    • D−2-2
    (b)
    Find the coordinates of the point where LL crosses the xx-axis.
    [1 mark]
    • A(−12,0)\left(-\frac12, 0\right)
    • B(0,1)(0, 1)
    • C(12,0)\left(\frac12, 0\right)
    • D(2,0)(2, 0)
    (c)
    Determine whether the point T(10,−19)T(10, -19) lies on LL.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A straight section of mountain road rises 84 m vertically over a horizontal distance of 1.2 km. The section starts at an altitude of 350 m. Let xx be the horizontal distance in metres from the start of the section and yy the altitude in metres.
    (a)
    Find the gradient of the road, and express it as a percentage.
    [3 marks]
    (b)
    (i) Write down the equation of the road in the form y=mx+cy = mx + c.
    (ii) Find the horizontal distance from the start at which the road reaches an altitude of 500 m. Give your answer to three significant figures.

    (iii) Lorries are banned from roads with a gradient steeper than 8%. State, with a reason, whether lorries may use this road.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The line L1L_1 passes through the points P(1,2)P(1, 2) and Q(7,5)Q(7, 5). The line L2L_2 has equation 2x+y−19=02x + y - 19 = 0.
    (a)
    (i) Find the equation of L1L_1, giving your answer in the form ax+by+d=0ax + by + d = 0, where a,b,d∈Za, b, d\in\mathbb{Z}.
    (ii) Show that
    L1L_1 and L2L_2 are perpendicular.
    [6 marks]
    (b)
    (i) Find the coordinates of the point of intersection of L1L_1 and L2L_2.
    (ii) Hence find the shortest distance from
    PP to L2L_2, justifying your method.
    (iii) The line
    L3L_3 is parallel to L2L_2 and passes through PP. Find the coordinates of the point where L3L_3 meets the xx-axis.
    [6 marks]

    Total for question 4: 12 marks

End of questions