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2.15 Solving inequalitiesIB Maths: Analysis and Approaches HL: Subtopic test

10 questions, 27 marks

IB Maths: Analysis and Approaches HL

2.15 Solving inequalities

Total 27 marks

Name

Class

Date

  1. 1
    The polynomial pp is defined for x∈Rx\in\mathbb{R} by p(x)=(x+2)(x−1)(x−4)p(x)=(x+2)(x-1)(x-4).
    (a)
    Find the set of values of xx for which p(x)>0p(x)>0.
    [1 mark]
    • Ax<−2x<-2 or 1<x<41<x<4
    • B−2<x<4-2<x<4
    • C−2<x<1-2<x<1 or x>4x>4
    • Dx>4x>4
    (b)
    Find the number of positive integers xx that satisfy p(x)≤0p(x)\le0.
    [1 mark]
    • A2
    • B4
    • C3
    • D5
    (c)
    Solve the inequality p(x−3)<0p(x-3)<0.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The functions ff and gg are defined for x∈Rx\in\mathbb{R} by f(x)=x2−2x−3f(x)=x^{2}-2x-3 and g(x)=x+1g(x)=x+1.
    (a)
    Find the xx-coordinates of the points where the graphs of y=f(x)y=f(x) and y=g(x)y=g(x) meet.
    [1 mark]
    • A−1-1 and 44
    • B11 and −4-4
    • C−1-1 and 33
    • D33 and 44
    (b)
    Solve g(x)≥f(x)g(x)\ge f(x).
    [1 mark]
    • Ax≤−1x\le-1 or x≥4x\ge4
    • B−1<x<4-1<x<4
    • C−1≤x≤3-1\le x\le3
    • D−1≤x≤4-1\le x\le4
    (c)
    Find the number of integers nn for which f(n)≤g(n)f(n)\le g(n) and f(n)<0f(n)<0.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    An open box is made from a square sheet of card of side 1212 cm by cutting a square of side xx cm from each corner and folding up the sides. The volume of the box is V(x)=x(12−2x)2V(x)=x(12-2x)^{2} cm3^{3}, for 0<x<60<x<6.
    (a)
    Show that V(x)≥100V(x)\ge100 is equivalent to (x−1)(x2−11x+25)≥0(x-1)(x^{2}-11x+25)\ge0.
    [3 marks]
    (b)
    Hence find, in exact form, the set of values of xx for which the volume of the box is at least 100100 cm3^{3}.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The functions ff and gg are defined by f(x)=xx−2f(x)=\dfrac{x}{x-2}, for x∈Rx\in\mathbb{R}, x≠2x\neq2, and g(x)=x−4g(x)=x-4, for x∈Rx\in\mathbb{R}.
    (a)
    Solve the inequality f(x)≤g(x)f(x)\le g(x) analytically, giving your answer in exact form.
    [6 marks]
    (b)
    (i) A student multiplies both sides of f(x)≤g(x)f(x)\le g(x) by (x−2)(x-2) and obtains the answer x≤7−172x\le\frac{7-\sqrt{17}}{2} or x≥7+172x\ge\frac{7+\sqrt{17}}{2}. Explain the error in the student's method, and verify that one value of xx in the student's answer does not satisfy f(x)≤g(x)f(x)\le g(x).\n(ii) Use technology to solve f(x)>ex−3f(x)>\mathrm{e}^{x-3} for x>2x>2. Give the boundary value correct to 3 significant figures.
    [6 marks]

    Total for question 4: 12 marks

End of questions