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2.1 Equations of straight linesIB Maths: Analysis and Approaches HL: Flashcards

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Gradient–intercept form of a line?

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Gradient–intercept form of a line?
y=mx+cy = mx + c
Point–gradient form of a line?
y−y1=m(x−x1)y - y_1 = m(x - x_1)
General form of a line?
ax+by+d=0ax + by + d = 0
Gradient between (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2)?
y2−y1x2−x1\frac{y_2 - y_1}{x_2 - x_1}
Condition for parallel lines?
m1=m2m_1 = m_2
Condition for perpendicular lines?
m1×m2=−1m_1\times m_2 = -1
Gradient of 2x+5y−10=02x + 5y - 10 = 0?
y=−25x+2y = -\frac25x + 2, so −25-\frac25.
Gradient perpendicular to m=−25m = -\frac25?
52\frac52
xx-intercept of y=3x−6y = 3x - 6?
(2,0)(2, 0)
A road rises 30 m over 600 m horizontally. Gradient as a percentage?
30600=0.05=5%\frac{30}{600} = 0.05 = 5\%
Line through (2,3)(2, 3) with gradient 4?
y−3=4(x−2)y - 3 = 4(x - 2), i.e. y=4x−5y = 4x - 5.
How do you check a point lies on a line?
Substitute its coordinates; they must satisfy the equation.
Shortest distance from a point to a line is measured…
Along the perpendicular from the point to the line.