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1.13 Modulus–argument and Euler formIB Maths: Analysis and Approaches HL: Subtopic test

10 questions, 27 marks

IB Maths: Analysis and Approaches HL

1.13 Modulus–argument and Euler form

Total 27 marks

Name

Class

Date

  1. 1
    The complex numbers zz and ww are given by z=2 cis(π3)z = 2\,\mathrm{cis}\left(\dfrac{\pi}{3}\right) and w=4 cis(π6)w = 4\,\mathrm{cis}\left(\dfrac{\pi}{6}\right).
    (a)
    Find zwzw.
    [1 mark]
    • A6 cis(π2)6\,\mathrm{cis}\left(\frac{\pi}{2}\right)
    • B8 cis(π2)8\,\mathrm{cis}\left(\frac{\pi}{2}\right)
    • C8 cis(π218)8\,\mathrm{cis}\left(\frac{\pi^2}{18}\right)
    • D8 cis(π6)8\,\mathrm{cis}\left(\frac{\pi}{6}\right)
    (b)
    Find zw\dfrac{z}{w} in Euler form.
    [1 mark]
    • A2e−π6i2\mathrm{e}^{-\frac{\pi}{6}\mathrm{i}}
    • B−2eπ6i-2\mathrm{e}^{\frac{\pi}{6}\mathrm{i}}
    • C12eπ6i\frac{1}{2}\mathrm{e}^{\frac{\pi}{6}\mathrm{i}}
    • D12eπ2i\frac{1}{2}\mathrm{e}^{\frac{\pi}{2}\mathrm{i}}
    (c)
    Write zz in the form a+bia + b\mathrm{i}, where a,b∈Ra, b \in \mathbb{R}, giving exact values.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The complex number uu is given by u=−2−2iu = -2 - 2\mathrm{i}. Arguments are taken in the interval −π<θ≤π-\pi < \theta \le \pi.
    (a)
    Write uu in modulus–argument form.
    [1 mark]
    • A22 cis(−3π4)2\sqrt2\,\mathrm{cis}\left(-\frac{3\pi}{4}\right)
    • B22 cis(π4)2\sqrt2\,\mathrm{cis}\left(\frac{\pi}{4}\right)
    • C8 cis(−3π4)8\,\mathrm{cis}\left(-\frac{3\pi}{4}\right)
    • D22 cis(3π4)2\sqrt2\,\mathrm{cis}\left(\frac{3\pi}{4}\right)
    (b)
    Write u∗u^{*} in Euler form.
    [1 mark]
    • A22 e−3π4i2\sqrt2\,\mathrm{e}^{-\frac{3\pi}{4}\mathrm{i}}
    • B−22 e3π4i-2\sqrt2\,\mathrm{e}^{\frac{3\pi}{4}\mathrm{i}}
    • C22 eπ4i2\sqrt2\,\mathrm{e}^{\frac{\pi}{4}\mathrm{i}}
    • D22 e3π4i2\sqrt2\,\mathrm{e}^{\frac{3\pi}{4}\mathrm{i}}
    (c)
    Use your answer to part (a) to find u2u^{2}, giving your answer in the form a+bia + b\mathrm{i}.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    In an alternating-current circuit, the voltage VV volts, the current II amps and the impedance ZZ ohms are complex numbers related by V=IZV = IZ. A component has impedance Z=43+4iZ = 4\sqrt{3} + 4\mathrm{i} and carries a current I=5eπ4iI = 5\mathrm{e}^{\frac{\pi}{4}\mathrm{i}}. A calculator may be used in part (b).
    (a)
    Write ZZ in the form reiθr\mathrm{e}^{\mathrm{i}\theta}, where r>0r > 0 and −π<θ≤π-\pi < \theta \le \pi.
    [3 marks]
    (b)
    Find VV in Euler form. Hence find VV in the form a+bia + b\mathrm{i}, giving aa and bb correct to three significant figures, and state the angle by which the argument of the voltage exceeds the argument of the current.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Let z=1+eiθz = 1 + \mathrm{e}^{\mathrm{i}\theta} and w=1−eiθw = 1 - \mathrm{e}^{\mathrm{i}\theta}, where 0<θ<π0 < \theta < \pi.
    (a)
    (i) Show that z=2cos⁡(θ2)eiθ2z = 2\cos\left(\dfrac{\theta}{2}\right)\mathrm{e}^{\frac{\mathrm{i}\theta}{2}}.
    (ii) Hence write down
    ∣z∣|z| and arg⁡z\arg z, justifying your value of ∣z∣|z|.
    (iii) Find
    ∣z∣|z| and arg⁡z\arg z when θ=2π3\theta = \dfrac{2\pi}{3}.
    (iv) Give a geometric reason, in the complex plane, why
    arg⁡z=θ2\arg z = \dfrac{\theta}{2}.
    [6 marks]
    (b)
    (i) Show that w=−2isin⁡(θ2)eiθ2w = -2\mathrm{i}\sin\left(\dfrac{\theta}{2}\right)\mathrm{e}^{\frac{\mathrm{i}\theta}{2}}.
    (ii) Hence show that
    zw\dfrac{z}{w} is purely imaginary, and interpret this result geometrically in the complex plane.
    [6 marks]

    Total for question 4: 12 marks

End of questions