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1.14 Polynomial roots, De Moivre's theorem, powers and rootsIB Maths: Analysis and Approaches HL: Subtopic test

10 questions, 27 marks

IB Maths: Analysis and Approaches HL

1.14 Polynomial roots, De Moivre's theorem, powers and roots

Total 27 marks

Name

Class

Date

  1. 1
    The cubic equation z3+az2+bz+c=0z^{3} + az^{2} + bz + c = 0, where a,b,c∈Ra, b, c \in \mathbb{R}, has a root z=2−3iz = 2 - 3i. It also has a real root z=1z = 1.
    (a)
    Which of the following must also be a root of the equation?
    [1 mark]
    • A3−2i3 - 2i
    • B−2+3i-2 + 3i
    • C−2−3i-2 - 3i
    • D2+3i2 + 3i
    (b)
    Find the value of aa.
    [1 mark]
    • A55
    • B−5-5
    • C−4-4
    • D44
    (c)
    Find the value of bb and the value of cc.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The complex number ww is given by w=1+3 iw = 1 + \sqrt{3}\,i.
    (a)
    Find w6w^{6}.
    [1 mark]
    • A64i64i
    • B−64-64
    • C6464
    • D1212
    (b)
    Find the smallest positive integer nn for which wnw^{n} is a negative real number.
    [1 mark]
    • A33
    • B66
    • C22
    • D99
    (c)
    Find w−2w^{-2}, giving your answer in the form p+qip + qi, where p,q∈Rp, q \in \mathbb{R}.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Consider the equation z3=42 (−1+i)z^{3} = 4\sqrt{2}\,(-1 + i), where z∈Cz \in \mathbb{C}. The three solutions are represented in the complex plane by the points AA, BB and CC.
    (a)
    Solve the equation, giving your answers in the form reiθre^{i\theta}, where r>0r > 0 and −π<θ≤π-\pi < \theta \le \pi.
    [3 marks]
    (b)
    Find the exact area of triangle ABCABC.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Let z=cos⁡θ+isin⁡θz = \cos\theta + i\sin\theta, where θ∈R\theta \in \mathbb{R}.
    (a)
    Prove by mathematical induction that zn=cos⁡nθ+isin⁡nθz^{n} = \cos n\theta + i\sin n\theta for all n∈Z+n \in \mathbb{Z}^{+}.
    [6 marks]
    (b)
    By considering z3z^{3}, show that cos⁡3θ=4cos⁡3θ−3cos⁡θ\cos 3\theta = 4\cos^{3}\theta - 3\cos\theta. Hence find the exact solutions of the equation 8x3−6x−1=08x^{3} - 6x - 1 = 0.
    [6 marks]

    Total for question 4: 12 marks

End of questions