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1.16 Systems of linear equationsIB Maths: Analysis and Approaches HL: Subtopic test

10 questions, 27 marks

IB Maths: Analysis and Approaches HL

1.16 Systems of linear equations

Total 27 marks

Name

Class

Date

  1. 1
    Consider the system of equations: (1) x+y+z=6x + y + z = 6, (2) 2x−y+z=32x - y + z = 3, (3) x+2y−z=2x + 2y - z = 2.
    (a)
    Which equation in yy and zz only is obtained by eliminating xx from equations (1) and (2)?
    [1 mark]
    • A3y+z=153y + z = 15
    • B3y−z=93y - z = 9
    • C3y+z=93y + z = 9
    • D−3y−z=9-3y - z = 9
    (b)
    Find the solution of the system.
    [1 mark]
    • Ax=3, y=2, z=1x = 3,\ y = 2,\ z = 1
    • Bx=1, y=2, z=3x = 1,\ y = 2,\ z = 3
    • Cx=2, y=1, z=3x = 2,\ y = 1,\ z = 3
    • Dx=1, y=3, z=2x = 1,\ y = 3,\ z = 2
    (c)
    Equation (3) is replaced by x+2y+kz=2x + 2y + kz = 2, where k∈Rk \in \mathbb{R}, and equations (1) and (2) are unchanged. Find the value of kk for which the new system has no solution.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    At a café, a coffee costs cc dirhams, a tea costs tt dirhams and a juice costs jj dirhams. Order P is 2 coffees, 1 tea and 3 juices and costs 62 dirhams. Order Q is 1 coffee, 3 teas and 1 juice and costs 44 dirhams. Order R is 3 coffees, 2 teas and 2 juices and costs 74 dirhams.
    (a)
    Which equation represents order R?
    [1 mark]
    • A7(c+t+j)=747(c + t + j) = 74
    • B2c+3t+2j=742c + 3t + 2j = 74
    • C3c+2t+2j=623c + 2t + 2j = 62
    • D3c+2t+2j=743c + 2t + 2j = 74
    (b)
    Use your graphic display calculator to find the price of one juice, in dirhams.
    [1 mark]
    • A99
    • B77
    • C1414
    • D1010
    (c)
    A group orders 4 coffees, 2 teas and 5 juices and pays with a 150-dirham note. Find the change they receive.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Consider the system of equations: (1) x+2y−z=3x + 2y - z = 3, (2) 2x+5y+z=102x + 5y + z = 10, (3) x+3y+2z=7x + 3y + 2z = 7.
    (a)
    Use row reduction to show that the system has infinitely many solutions.
    [3 marks]
    (b)
    Find the general solution of the system, and interpret it geometrically.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Consider the system of equations x+y+z=2x + y + z = 2, x+2y+3z=5x + 2y + 3z = 5 and 2x+3y+az=b2x + 3y + az = b, where a,b∈Ra, b \in \mathbb{R}.
    (a)
    Find the conditions on aa and bb for which the system has (i) a unique solution; (ii) infinitely many solutions; (iii) no solution.
    [6 marks]
    (b)
    Let a=4a = 4 and b=7b = 7. Find the general solution of the system. Hence find the solution for which x2+y2+z2x^{2} + y^{2} + z^{2} takes its least value.
    [6 marks]

    Total for question 4: 12 marks

End of questions