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1.8 Infinite geometric seriesIB Maths: Analysis and Approaches HL: Subtopic test

10 questions, 27 marks

IB Maths: Analysis and Approaches HL

1.8 Infinite geometric series

Total 27 marks

Name

Class

Date

  1. 1
    A geometric sequence has first term u1=24u_1 = 24 and common ratio r=−12r = -\frac{1}{2}.
    (a)
    Find u4u_4.
    [1 mark]
    • A−3-3
    • B33
    • C66
    • D1.51.5
    (b)
    Find the sum to infinity of the sequence.
    [1 mark]
    • A4848
    • B1616
    • C−16-16
    • D1212
    (c)
    Find the sum to infinity of the odd-numbered terms, u1+u3+u5+⋯u_1 + u_3 + u_5 + \cdots.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Consider the infinite geometric series 1+(2x−1)+(2x−1)2+(2x−1)3+⋯1 + (2x-1) + (2x-1)^2 + (2x-1)^3 + \cdots, where x∈Rx\in\mathbb{R}.
    (a)
    Find the set of values of xx for which the series converges.
    [1 mark]
    • A−1<x<1-1<x<1
    • Bx<1x<1
    • C0<x<10<x<1
    • D−12<x<12-\frac12<x<\frac12
    (b)
    Find the sum to infinity of the series when x=0.3x = 0.3.
    [1 mark]
    • A53\frac{5}{3}
    • B75\frac{7}{5}
    • C107\frac{10}{7}
    • D57\frac{5}{7}
    (c)
    Given that the sum to infinity of the series is 43\frac43, find the value of xx.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A ball is dropped from a height of 3 m onto a hard floor. After each bounce it rises vertically to 60% of the height from which it last fell. Assume the ball continues to bounce indefinitely.
    (a)
    Show that the total vertical distance travelled by the ball is 12 m.
    [3 marks]
    (b)
    A second ball is also dropped from 3 m, but after each bounce it rises to a fraction pp of the height from which it last fell, where 0<p<10<p<1. The total vertical distance it travels is 7 m. Find pp, and justify that your value is consistent with the model.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    An infinite geometric series has first term aa and common ratio rr. The sum to infinity of the series is 45 and the sum of its first two terms is 40.
    (a)
    Show that 1−r2=891 - r^2 = \frac{8}{9}, and hence find the two possible pairs of values of aa and rr.
    [6 marks]
    (b)
    It is now given that every term of the series is positive.
    (i) Write down the values of
    aa and rr.
    (ii) Find the least number of terms that must be added for the sum to exceed 44.

    (iii) Explain why the sum of a finite number of terms can never exceed 45.
    [6 marks]

    Total for question 4: 12 marks

End of questions