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Algebraic Roots & IndicesEdexcel IGCSE Maths: Subtopic test

10 questions, 26 marks

Edexcel IGCSE Maths

Algebraic Roots & Indices

Total 26 marks

Name

Class

Date

  1. 1
    A materials scientist calculates decay factors using fractional and negative indices. She evaluates 823\sqrt[3]{8^2}, then 625−12625^{-\frac{1}{2}}, then (125)32\left(\frac{1}{25}\right)^{\frac{3}{2}}.
    (a)
    Evaluate 823\sqrt[3]{8^2}.
    [1 mark]
    • A44
    • B1616
    • C22
    • D6464
    (b)
    Evaluate 625−12625^{-\frac{1}{2}}.
    [1 mark]
    • A2525
    • B125\frac{1}{25}
    • C−25-25
    • D1625\frac{1}{625}
    (c)
    Evaluate (125)32\left(\frac{1}{25}\right)^{\frac{3}{2}}.
    [1 mark]
    • A125\frac{1}{25}
    • B125125
    • C1125\frac{1}{125}
    • D350\frac{3}{50}

    Total for question 1: 3 marks

  2. 2
    A designer works with surd expressions for a tiling pattern. The first task simplifies 8+332\sqrt{8}+3\sqrt{32}. The second task simplifies 62534625^{\frac{3}{4}} using index laws.
    (a)
    Simplify 8+332\sqrt{8}+3\sqrt{32}, giving your answer in the form k2k\sqrt{2}.
    [2 marks]
    (b)
    Evaluate 62534625^{\frac{3}{4}}, showing your method using index laws.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A physics student rationalises denominators for exam revision. The first task is 28\frac{2}{\sqrt{8}}. The second task rationalises 12−3\frac{1}{2-\sqrt{3}}.
    (a)
    Rationalise the denominator of 28\frac{2}{\sqrt{8}}, giving your answer in its simplest surd form.
    [3 marks]
    (b)
    Rationalise the denominator of 12−3\frac{1}{2-\sqrt{3}}, giving your answer in the form a+b3a+b\sqrt{3}.
    [3 marks]

    Total for question 3: 6 marks

  4. 4
    An electronics engineer models signal decay using index expressions in a base of 2 and 3. The first expression is 23x×2−x+1÷222^{3x} \times 2^{-x+1} \div 2^{2}. A second expression compares surd values: (3+1)2\left(\sqrt{3}+1\right)^2. A third combines both to fully rationalise and simplify a compound fraction 33+13−1\frac{3}{\sqrt{3}}+\frac{1}{\sqrt{3}-1}.
    (a)
    An electronics formula for signal decay uses 23x×2−x+1÷222^{3x} \times 2^{-x+1} \div 2^{2}. Simplify this expression fully, showing every index law step, and give your answer as a single power of 2 in terms of xx.
    [4 marks]
    (b)
    Expand and simplify (3+1)2\left(\sqrt{3}+1\right)^2 fully, giving your answer in the form a+b3a+b\sqrt{3}.
    [4 marks]
    (c)
    Simplify 33+13−1\frac{3}{\sqrt{3}}+\frac{1}{\sqrt{3}-1} fully, rationalising each denominator and giving your final answer in the form a+b3a+b\sqrt{3}.
    [5 marks]

    Total for question 4: 13 marks

End of questions