Revision resources

Cambridge IGCSE Physics (0625) equations

The Cambridge IGCSE Physics 0625 syllabus marks every equation below as "recall and use", so you need all of them from memory. Core students need the Core list. Extended students, who sit Papers 2 and 4, need the Core list and the Supplement list.

The last column gives the syllabus section, so you can find each equation in the official syllabus. The equations are as written in the syllabus for exams in 2026, 2027 and 2028.

Practise with marked questions

Core equations (all students)

Cambridge IGCSE Physics Core equations
In wordsEquationSymbols and unitsSyllabus
speed = distance travelled ÷ timev=stv = \dfrac{s}{t}vv m/s; ss m; tt s1.2
average speed = total distance travelled ÷ total time takenNo symbol formm/s1.2
gravitational field strength = weight ÷ massg=Wmg = \dfrac{W}{m}gg N/kg; WW N; mm kg1.3
density = mass ÷ volumeρ=mV\rho = \dfrac{m}{V}ρ\rho kg/m³ or g/cm³; mm kg; VV m³1.4
moment = force × perpendicular distance from the pivotNo symbol formmoment N m1.5.2
work done = force × distance = energy transferredW=Fd=ΔEW = Fd = \Delta EWW J; FF N; dd m1.7.2
power = work done ÷ time, and power = energy transferred ÷ timeP=WtP=ΔEtP = \dfrac{W}{t} \quad P = \dfrac{\Delta E}{t}PP W; W,EW, E J; tt s1.7.4
pressure = force ÷ areap=FAp = \dfrac{F}{A}pp Pa; FF N; AA m²1.8
temperature in kelvin = temperature in °C + 273T (K)=θ (∘C)+273T\,(\text{K}) = \theta\,({}^\circ\text{C}) + 273K and °C2.1.3
wave speed = frequency × wavelengthv=fλv = f\lambdavv m/s; ff Hz; λ\lambda m3.1
angle of incidence = angle of reflectioni=ri = rdegrees3.2.1
resistance = potential difference ÷ currentR=VIR = \dfrac{V}{I}RR Ω; VV V; II A4.2.4
electrical power = current × potential differenceP=IVP = IVPP W; II A; VV V4.2.5
electrical energy = current × potential difference × timeE=IVtE = IVtEE J; II A; VV V; tt s4.2.5
combined resistance of resistors in series (the syllabus asks you to calculate it)R=R1+R2+…R = R_1 + R_2 + \dotsRR Ω4.3.2
transformer: p.d. ratio = turns ratioVpVs=NpNs\dfrac{V_p}{V_s} = \dfrac{N_p}{N_s}VV V4.5.6

Supplement equations (Extended only)

Cambridge IGCSE Physics Supplement equations
In wordsEquationSymbols and unitsSyllabus
acceleration = change in velocity ÷ time takena=ΔvΔta = \dfrac{\Delta v}{\Delta t}aa m/s²; vv m/s; tt s1.2
spring constant = force ÷ extensionk=Fxk = \dfrac{F}{x}kk N/m; FF N; xx m1.5.1
resultant force = mass × accelerationF=maF = maFF N; mm kg; aa m/s²1.5.1
momentum = mass × velocityp=mvp = mvpp kg m/s; mm kg; vv m/s1.6
impulse = force × time = change in momentumimpulse=FΔt=Δ(mv)\text{impulse} = F\Delta t = \Delta(mv)N s (equal to kg m/s)1.6
resultant force = change in momentum ÷ timeF=ΔpΔtF = \dfrac{\Delta p}{\Delta t}FF N; pp kg m/s; tt s1.6
kinetic energyEk=12mv2E_k = \tfrac{1}{2}mv^2EkE_k J; mm kg; vv m/s1.7.1
change in gravitational potential energyΔEp=mgΔh\Delta E_p = mg\Delta hEpE_p J; mm kg; gg N/kg; hh m1.7.1
efficiency = useful energy output ÷ total energy input (× 100%), or useful power output ÷ total power input (× 100%)No symbol formNo unit (a ratio or a percentage)1.7.3
change in pressure beneath the surface of a liquidΔp=ρgΔh\Delta p = \rho g\Delta hpp Pa; ρ\rho kg/m³; gg N/kg; hh m1.8
for a fixed mass of gas at constant temperaturepV=constantpV = \text{constant}pp Pa; VV m³2.1.3
specific heat capacity = energy ÷ (mass × temperature change)c=ΔEmΔθc = \dfrac{\Delta E}{m\Delta\theta}cc J/(kg °C); EE J; mm kg; θ\theta °C2.2.2
refractive indexn=sin⁡isin⁡rn = \dfrac{\sin i}{\sin r}No unit3.2.2
refractive index and the critical anglen=1sin⁡cn = \dfrac{1}{\sin c}No unit3.2.2
current = charge ÷ timeI=QtI = \dfrac{Q}{t}II A; QQ C; tt s4.2.2
e.m.f. = work done ÷ charge, and p.d. = work done ÷ chargeE=WQV=WQE = \dfrac{W}{Q} \quad V = \dfrac{W}{Q}E,VE, V V; WW J; QQ C4.2.3
combined resistance of two resistors in parallel (the syllabus asks you to calculate it)1R=1R1+1R2\dfrac{1}{R} = \dfrac{1}{R_1} + \dfrac{1}{R_2}RR Ω4.3.2
potential divider with two resistorsR1R2=V1V2\dfrac{R_1}{R_2} = \dfrac{V_1}{V_2}RR Ω; VV V4.3.3
transformer at 100% efficiencyIpVp=IsVsI_pV_p = I_sV_sII A; VV V4.5.6
power lost in cablesP=I2RP = I^2RPP W; II A; RR Ω4.5.6
average orbital speedv=2πrTv = \dfrac{2\pi r}{T}vv m/s; rr m; TT s6.1.1
Hubble constant = recession speed ÷ distanceH0=vdH_0 = \dfrac{v}{d}H0H_0 per second; vv m/s; dd m6.2.3
estimate for the age of the Universedv=1H0\dfrac{d}{v} = \dfrac{1}{H_0}s6.2.3

Values the syllabus asks you to know

The acceleration of free fall near the Earth’s surface is about 9.8 m/s². The speed of electromagnetic waves in a vacuum is 3.0×1083.0 \times 10^8 m/s (Supplement). The speed of sound in air is about 330 to 350 m/s. One light-year is 9.5×10159.5 \times 10^{15} m (Supplement). The current estimate for H0H_0 is 2.2×10−182.2 \times 10^{-18} per second (Supplement).

Practise these with marked questions

Exam-style questions for every topic, free to read. Answer them online and Exaim marks each answer against the mark scheme, showing which marks you earned.

More formula sheets