All mind maps topics

Infrared spectroscopyAQA A-Level Chemistry: Mind map

What this mind map covers

  • Principle
  • Key absorptions
  • Fingerprinting
  • Impurities
  • Global warming

Exam questions on Infrared spectroscopy

  1. A student records the infrared spectrum of an organic liquid with the molecular formula C₃H₆O. The spectrum has a strong absorption at 1715 cm⁻¹ and no broad absorption anywhere between 2500 and 3600 cm⁻¹. Data: C=O 1680–1750 cm⁻¹; O–H (alcohols) 3230–3550 cm⁻¹; O–H (carboxylic acids) 2500–3000 cm⁻¹; C=C 1620–1680 cm⁻¹.
    Explain how the spectrum shows that the compound is neither an alcohol nor a carboxylic acid.2 marks
  2. A pharmaceutical chemist checks the purity of a solid drug product that was made in a reaction using ethanol as the solvent. The drug molecule contains no O–H bond. The chemist compares the infrared spectrum of each batch with the spectrum of a pure reference sample. One batch has an extra broad absorption at 3350 cm⁻¹. Data: C–H 2850–3100 cm⁻¹; O–H (alcohols) 3230–3550 cm⁻¹; O–H (carboxylic acids) 2500–3000 cm⁻¹; C=O 1680–1750 cm⁻¹.
    Explain how the spectrum shows that this batch is impure and what the impurity is likely to be.2 marks
  3. Two isomers, P and Q, both have the molecular formula C₃H₆O₂. The infrared spectrum of P has a very broad absorption from 2500 to 3000 cm⁻¹ and a strong absorption at 1710 cm⁻¹. The spectrum of Q has a strong absorption at 1740 cm⁻¹ and a strong absorption at 1200 cm⁻¹, but no broad absorption above 2500 cm⁻¹. Data: C=O 1680–1750 cm⁻¹; C–O 1000–1300 cm⁻¹; O–H (carboxylic acids) 2500–3000 cm⁻¹; O–H (alcohols) 3230–3550 cm⁻¹.
    Deduce the functional group present in P and in Q, referring to the bonds responsible for the absorptions.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).