All revision notes topics

Base properties of aminesAQA A-Level Chemistry: Revision notes

Section 1

Amines as weak bases

A base is a proton acceptor. Amines are bases because the nitrogen atom has a lone pair of electrons that forms a dative covalent bond to H⁺.

In water: CH₃NH₂ + H₂O ⇌ CH₃NH₃⁺ + OH⁻

The equilibrium lies well to the left, so only a small proportion of molecules are protonated. Amines are therefore weak bases. They also react with acids to form salts:

CH₃CH₂NH₂ + HCl → CH₃CH₂NH₃⁺Cl⁻ (ethylammonium chloride)

Key termsbaselone pairweak base
Common mistake

The amine does not release OH⁻ itself. The OH⁻ comes from water after the amine accepts H⁺ from it.

Section 2

Comparing base strength

For solutions of the same concentration, the stronger the base the higher the pH:

  • primary aliphatic amine (e.g. methylamine, pH about 11.8 at 0.100 mol dm⁻³)
  • ammonia (pH about 11.1)
  • primary aromatic amine (phenylamine, pH about 8.8)

The order of base strength is primary aliphatic amine > ammonia > phenylamine.

Key termsbase strength
Exam tip

Link the order to the pH data when given. A higher pH at the same concentration means a stronger base.

Section 3

Why aliphatic amines are stronger bases than ammonia

Alkyl groups release electron density towards the nitrogen atom (a positive inductive effect).

This increases the electron density on nitrogen, so its lone pair is more available to accept a proton. Aliphatic amines are therefore stronger bases than ammonia, which has only hydrogen atoms attached.

Key termspositive inductive effectavailability of the lone pair
Exam tip

Say 'more available', not 'stronger' or 'more electrons'. The examiner wants the idea of availability of the lone pair.

Section 4

Why phenylamine is a weaker base

In phenylamine the nitrogen's lone pair overlaps with the delocalised π system of the benzene ring and becomes partly delocalised into the ring.

The lone pair is therefore less available to accept a proton, which makes phenylamine a weaker base than ammonia.

Key termsdelocalised
Common mistake

Do not say that the lone pair 'is used up' in the ring. It is partly delocalised, which makes it less available.

Section 5

Reactions with acids and alkalis

Because amines are bases, they react with acids to form ionic salts, which are usually soluble in water even when the amine itself is only slightly soluble. Adding a stronger base such as NaOH then removes H⁺ from the ammonium ion and releases the free amine:

C₆H₅NH₃⁺ + OH⁻ → C₆H₅NH₂ + H₂O

Titrations of amines with acid are 1 : 1 for a primary amine. For example, 25.0 cm³ of 0.100 mol dm⁻³ ethylamine needs 20.0 cm³ of 0.125 mol dm⁻³ HCl.

Key termsammonium ion

Must know

  • Amines are weak bases because the N lone pair accepts H⁺
  • Base strength: primary aliphatic amine > ammonia > phenylamine
  • Alkyl groups push electron density onto N, making the lone pair more available
  • In phenylamine the lone pair is delocalised into the ring, making it less available
  • Amines react with acids to form salts; NaOH releases the free amine

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Base properties of amines

  1. A technician measures the pH of three aqueous solutions, each of concentration 0.100 mol dm⁻³, at 298 K. The solution of methylamine has a pH of 11.8, the solution of ammonia has a pH of 11.1 and the solution of phenylamine has a pH of 8.8.
    Write an equation for the reaction of phenylamine with water and explain why phenylamine is described as a weak base.2 marks
  2. A technician has separate 0.100 mol dm⁻³ solutions of ethylamine, CH₃CH₂NH₂, and phenylamine, C₆H₅NH₂, and plans to titrate samples of each against hydrochloric acid.
    A 25.0 cm³ sample of 0.100 mol dm⁻³ ethylamine reacts with 0.125 mol dm⁻³ hydrochloric acid. Calculate the volume of acid needed to neutralise it.2 marks
  3. A student measures the pH of a 0.100 mol dm⁻³ solution of ammonia at 298 K and finds it is 11.1. At this temperature the ionic product of water, Kw, is 1.00 × 10⁻¹⁴ mol² dm⁻⁶.
    Write an equation for the reaction of ammonia with water, and calculate the concentration of hydroxide ions in the solution.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).