Electrophilic substitution of benzeneAQA A-Level Chemistry: Revision notes
Section 1
Why benzene reacts with electrophiles
The delocalised π system gives a ring of high electron density above and below the plane of the carbon atoms. This attracts electrophiles, which are electron pair acceptors.
Because benzene is very stable, the reaction must keep the ring intact. An electrophile therefore substitutes a hydrogen atom rather than adding across the ring. This course is limited to monosubstitution, where one hydrogen is replaced.
Section 2
Nitration of benzene
Reagents and conditions: concentrated nitric acid and concentrated sulfuric acid, kept at about 50 °C (a water bath). Above this temperature more than one nitro group can be substituted, giving dinitrobenzene.
Benzene + HNO₃ → nitrobenzene + H₂O, that is C₆H₆ + HNO₃ → C₆H₅NO₂ + H₂O.
Generating the electrophile. Sulfuric acid is the stronger acid and protonates nitric acid, which loses water to form the nitronium ion:
HNO₃ + H₂SO₄ → NO₂⁺ + HSO₄⁻ + H₂O
Always quote both acids as concentrated, and the temperature limit with its reason: it prevents further substitution.
The electrophile is NO₂⁺, not HNO₃ or NO₂.
Section 3
Mechanism of nitration
- The delocalised π electrons attack the NO₂⁺ electrophile, forming a bond from carbon to nitrogen.
- This gives a positively charged intermediate. The delocalised ring is partly broken and the positive charge is spread over the remaining five carbons. The H and NO₂ are on the same carbon.
- The C–H bond breaks and H⁺ is lost, restoring the stable delocalised ring and forming nitrobenzene.
- The H⁺ reacts with HSO₄⁻ to re-form H₂SO₄, so sulfuric acid is a catalyst: H⁺ + HSO₄⁻ → H₂SO₄.
In a mechanism diagram the first curly arrow starts from the ring and points to the N of NO₂⁺. The second arrow starts at the C–H bond and points back into the ring.
In the intermediate the hydrogen is still attached to the same carbon as NO₂, and the positive charge sits inside the partly delocalised ring.
Section 4
Why nitration is useful
Nitration is an important step in synthesis:
- Further nitration of methylbenzene is used in the manufacture of explosives such as TNT
- Nitrobenzene can be reduced to phenylamine, an aromatic amine used to make dyes and other products
The nitro group is therefore a way of putting nitrogen onto an aromatic ring.
Section 5
Friedel–Crafts acylation
Acylation puts an acyl group, RCO–, onto the ring, forming an aromatic ketone. Benzene reacts with an acyl chloride in the presence of anhydrous aluminium chloride, AlCl₃, as catalyst, with warming.
C₆H₆ + CH₃COCl → C₆H₅COCH₃ + HCl (product: phenylethanone)
Generating the electrophile. AlCl₃ accepts a lone pair from the chlorine of the acyl chloride to form the acylium ion:
CH₃COCl + AlCl₃ → CH₃CO⁺ + AlCl₄⁻
Conditions must be anhydrous because AlCl₃ reacts with water.
The only difference from nitration is how the electrophile is made. After that the mechanism is the same.
Section 6
Mechanism of acylation
- The π electrons of benzene attack the carbon of the CH₃CO⁺ ion.
- A positively charged intermediate forms with the H and COCH₃ on the same carbon.
- H⁺ is lost, restoring the delocalised ring and forming phenylethanone.
- H⁺ reacts with AlCl₄⁻ to form HCl and regenerate AlCl₃: H⁺ + AlCl₄⁻ → AlCl₃ + HCl.
Acylation is useful because it forms a new C–C bond to the ring, which makes it a key step in building more complex molecules.
Must know
- Electrophiles attack the delocalised ring and substitute H, keeping the stable ring
- Nitration: concentrated HNO₃ + concentrated H₂SO₄, about 50 °C; electrophile NO₂⁺
- HNO₃ + H₂SO₄ → NO₂⁺ + HSO₄⁻ + H₂O; H₂SO₄ is regenerated
- Acylation: RCOCl + anhydrous AlCl₃; electrophile RCO⁺; AlCl₃ is regenerated
- Mechanism: attack, positive intermediate, loss of H⁺
- Uses: explosives and amines (dyes) from nitration; aromatic ketones from acylation
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Electrophilic substitution of benzene
- In a laboratory preparation of nitrobenzene, a technician adds benzene slowly to a mixture of concentrated nitric acid and concentrated sulfuric acid. The flask is kept in a water bath at about 50 °C and stirred, and the nitrobenzene is later separated from the acids.Write an equation for the formation of the electrophile in this reaction and state the role of sulfuric acid overall.2 marks
- A chemist wants to make phenylethanone, C₆H₅COCH₃, from benzene. The chemist adds ethanoyl chloride, CH₃COCl, to benzene in the presence of anhydrous aluminium chloride, AlCl₃, and warms the mixture. Hydrogen chloride gas is given off.Write an equation for the formation of the electrophile in this reaction and explain why the reagents and apparatus must be anhydrous.2 marks
- A student prepares nitrobenzene, C₆H₅NO₂, from benzene using a mixture of concentrated nitric acid and concentrated sulfuric acid at 50 °C. The student uses 15.6 g of benzene (Mr = 78.0) and obtains 19.7 g of pure nitrobenzene (Mr = 123.0). The reaction is a monosubstitution of the ring.Calculate the percentage yield of nitrobenzene.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).