Lattice energy and Born-Haber cyclesEdexcel International A Level Chemistry: Subtopic test
10 questions, 27 marks
Edexcel International A Level Chemistry
Lattice energy and Born-Haber cycles
Total 27 marks
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Class
Date
- 1A student constructs a Born–Haber cycle for sodium chloride using these standard enthalpy changes (kJ mol⁻¹): enthalpy change of formation of NaCl(s) −411; atomisation of sodium +107; first ionisation energy of sodium +496; atomisation of chlorine (per mole of Cl atoms) +122; first electron affinity of chlorine −349.(a)Which equation represents the first electron affinity of chlorine?[1 mark]
- A½Cl₂(g) + e⁻ → Cl⁻(g)
- BCl⁻(g) → Cl(g) + e⁻
- CCl(g) + e⁻ → Cl⁻(g)
- DCl(g) + e⁻ → Cl⁻(aq)
(b)Which equation represents the lattice energy of sodium chloride, as defined by formation of the solid?[1 mark]- ANa⁺(g) + Cl⁻(g) → NaCl(s)
- BNaCl(s) → Na⁺(g) + Cl⁻(g)
- CNa(s) + ½Cl₂(g) → NaCl(s)
- DNaCl(s) → Na(g) + Cl(g)
(c)Calculate the lattice energy of sodium chloride.[2 marks]Total for question 1: 4 marks
- 2Magnesium chloride is used as a de-icing salt. A Born–Haber cycle is constructed for MgCl₂ using these standard enthalpy changes (kJ mol⁻¹): enthalpy change of formation of MgCl₂(s) −641; atomisation of magnesium +148; first ionisation energy of magnesium +738; second ionisation energy of magnesium +1451; atomisation of chlorine (per mole of Cl atoms) +122; first electron affinity of chlorine −349.(a)What is the lattice energy of magnesium chloride?[1 mark]
- A+2524 kJ mol⁻¹
- B−2751 kJ mol⁻¹
- C−1883 kJ mol⁻¹
- D−2524 kJ mol⁻¹
(b)Which step in the cycle is exothermic?[1 mark]- AMg⁺(g) → Mg²⁺(g) + e⁻
- BCl(g) + e⁻ → Cl⁻(g)
- CMg(s) → Mg(g)
- D½Cl₂(g) → Cl(g)
(c)Calculate the total enthalpy change for converting 1 mol of Mg(s) and 1 mol of Cl₂(g) into 1 mol of Mg²⁺(g) and 2 mol of Cl⁻(g).[2 marks]Total for question 2: 4 marks
- 3A student compares two compounds that each contain a 1+ cation and a 1− anion. Lattice energies (kJ mol⁻¹), defined for formation of the solid from gaseous ions, are: sodium chloride, Born–Haber value −787 and value calculated from a purely ionic model −770; silver iodide, Born–Haber value −889 and value calculated from a purely ionic model −778.(a)Calculate the difference between the Born–Haber and ionic-model lattice energies for each compound, and state which compound has the greater covalent character.[3 marks](b)Explain why the Born–Haber lattice energy of silver iodide is more exothermic than the value from the ionic model.[4 marks]
Total for question 3: 7 marks
- 4Calcium oxide is made by heating limestone and is used to line furnaces. A Born–Haber cycle for CaO uses these standard enthalpy changes (kJ mol⁻¹): enthalpy change of formation of CaO(s) −635; atomisation of calcium +178; first ionisation energy of calcium +590; second ionisation energy of calcium +1145; atomisation of oxygen (per mole of O atoms) +249; first electron affinity of oxygen −141; second electron affinity of oxygen +798.(a)Calculate the lattice energy of calcium oxide.[6 marks](b)Define the enthalpy change of atomisation and the first electron affinity. Explain why the second electron affinity of oxygen is endothermic and yet calcium oxide is stable.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).