High-resolution mass spectrometry and chromatographyEdexcel International A Level Chemistry: Subtopic test
10 questions, 27 marks
Edexcel International A Level Chemistry
High-resolution mass spectrometry and chromatography
Total 27 marks
Name
Class
Date
- 1Carbon monoxide, nitrogen and ethene all have the same nominal relative molecular mass of 28. A chemist uses a high-resolution mass spectrometer to analyse gases. Accurate relative atomic masses: H = 1.0078, C = 12.0000, N = 14.0031, O = 15.9949.(a)Why can a high-resolution mass spectrometer distinguish between carbon monoxide, nitrogen and ethene?[1 mark]
- AThe three compounds have different numbers of electrons, which changes their peak heights
- BThe compounds have different nominal relative molecular masses
- CThe accurate relative atomic masses of the isotopes are not whole numbers, so the three molecular ions have slightly different accurate masses
- DThe molecular ions have different charges
(b)A molecular ion peak is recorded at m/z 28.0312. Which compound gives this peak?[1 mark]- ACO
- BN₂
- CHCN
- DC₂H₄
(c)Calculate the accurate relative molecular mass of propanone, C₃H₆O, to four decimal places.[2 marks]Total for question 1: 4 marks
- 2A student uses one-way paper chromatography to separate a mixture of two coloured food dyes, X and Y, using water as the solvent. The solvent front moves 8.0 cm from the pencil start line. The centre of the spot for dye X is 3.2 cm from the start line and the centre of the spot for dye Y is 5.6 cm from the start line.(a)What is the stationary phase in paper chromatography?[1 mark]
- AThe water used as the solvent
- BWater bound to the cellulose fibres of the paper
- CThe pencil line
- DThe air above the paper
(b)What is the Rf value of dye Y?[1 mark]- A0.70
- B0.56
- C0.40
- D1.43
(c)Explain why dye Y travels further up the paper than dye X.[2 marks]Total for question 2: 4 marks
- 3A sports laboratory tests an athlete's urine sample for a banned stimulant using gas chromatography combined with mass spectrometry (GC-MS). A peak with retention time 4.2 minutes matches the retention time of a standard sample of the stimulant, which has the formula C₁₀H₁₅N. The mass spectrometer gives a molecular ion peak at m/z 149.1201 for this peak. Accurate relative atomic masses: H = 1.0078, C = 12.0000, N = 14.0031, O = 15.9949.(a)Explain why combining gas chromatography with mass spectrometry gives a more reliable identification of the stimulant than gas chromatography alone.[3 marks](b)Show that the molecular ion peak is consistent with C₁₀H₁₅N and not with C₉H₁₁NO, by calculating the accurate relative molecular mass of each.[4 marks]
Total for question 3: 7 marks
- 4A chemist monitors the formation of an ester from a carboxylic acid by thin-layer chromatography on a silica gel plate, using a non-polar solvent. The solvent front is 7.5 cm above the start line. A pure sample of the acid runs to 1.2 cm above the start line and a pure sample of the ester runs to 5.4 cm. A sample of the reaction mixture gives two spots, at 1.2 cm and 5.4 cm. The chemist then plans to check the purity of the product using gas chromatography or high-performance liquid chromatography, each combined with mass spectrometry.(a)Calculate the Rf value of each spot, deduce what the chromatogram shows about the reaction mixture, and explain why the ester has a higher Rf value than the acid.[6 marks](b)Compare how gas chromatography and high-performance liquid chromatography separate the components of a mixture, and explain how combining either with mass spectrometry identifies the components.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).