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NMR spectroscopyEdexcel International A Level Chemistry: Subtopic test

10 questions, 27 marks

Edexcel International A Level Chemistry

NMR spectroscopy

Total 27 marks

Name

Class

Date

  1. 1
    Three structural isomers of formula C₄H₁₀O are examined by ¹³C NMR spectroscopy: butan-1-ol, butan-2-ol and 2-methylpropan-2-ol.
    (a)
    How many peaks are seen in the ¹³C NMR spectrum of butan-2-ol, CH₃CH(OH)CH₂CH₃?
    [1 mark]
    • A1
    • B2
    • C3
    • D4
    (b)
    Which isomer gives a ¹³C NMR spectrum with exactly two peaks?
    [1 mark]
    • AButan-1-ol
    • B2-methylpropan-2-ol
    • CButan-2-ol
    • DAll three isomers
    (c)
    Explain why the ¹³C NMR spectrum of 2-methylpropan-2-ol, (CH₃)₃COH, has only two peaks even though the molecule has four carbon atoms.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The ¹H NMR spectrum of ethyl ethanoate, CH₃COOCH₂CH₃, is recorded in a solvent that contains no hydrogen atoms, using tetramethylsilane (TMS) as a reference standard.
    (a)
    Which statement gives a reason for using TMS as the reference standard?
    [1 mark]
    • AAll 12 hydrogen atoms are in the same environment, giving one sharp peak at a lower chemical shift than most other protons
    • BIt is polar and dissolves in water
    • CIt has the highest chemical shift of any proton
    • DIt splits the peaks of the sample into multiplets
    (b)
    What is the ratio of the peak areas in the ¹H NMR spectrum of ethyl ethanoate?
    [1 mark]
    • A1 : 1 : 1
    • B3 : 5
    • C3 : 2 : 3
    • D2 : 2 : 3
    (c)
    Deduce the splitting patterns of the signals from the CH₂ group and from the CH₃ of the ethyl group in ethyl ethanoate, explaining your answers.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Compound Z has the molecular formula C₄H₈O₂ and is an ester. Its ¹H NMR spectrum has three peaks: δ 3.7 (singlet, relative peak area 3), δ 2.3 (quartet, relative peak area 2) and δ 1.1 (triplet, relative peak area 3). Its ¹³C NMR spectrum has four peaks.
    (a)
    Use the ¹H NMR data to deduce the structure of compound Z. Explain the singlet, the quartet and the triplet.
    [3 marks]
    (b)
    Another isomer of Z is propan-2-yl methanoate, HCOOCH(CH₃)₂. Explain how its ¹³C NMR and ¹H NMR spectra would differ from those of Z.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Two structural isomers of C₃H₇Br, 1-bromopropane (CH₃CH₂CH₂Br) and 2-bromopropane ((CH₃)₂CHBr), are in unlabelled bottles. A technician plans to identify them using NMR spectroscopy.
    (a)
    Explain how the ¹³C NMR spectra and the low-resolution ¹H NMR spectra would allow the technician to tell the two isomers apart.
    [6 marks]
    (b)
    Predict the splitting pattern and relative chemical shift of each signal in the high-resolution ¹H NMR spectrum of 1-bromopropane, and state how the CH and CH₃ signals of 2-bromopropane are split.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).