NMR spectroscopyEdexcel International A Level Chemistry: Subtopic test
10 questions, 27 marks
Edexcel International A Level Chemistry
NMR spectroscopy
Total 27 marks
Name
Class
Date
- 1Three structural isomers of formula C₄H₁₀O are examined by ¹³C NMR spectroscopy: butan-1-ol, butan-2-ol and 2-methylpropan-2-ol.(a)How many peaks are seen in the ¹³C NMR spectrum of butan-2-ol, CH₃CH(OH)CH₂CH₃?[1 mark]
- A1
- B2
- C3
- D4
(b)Which isomer gives a ¹³C NMR spectrum with exactly two peaks?[1 mark]- AButan-1-ol
- B2-methylpropan-2-ol
- CButan-2-ol
- DAll three isomers
(c)Explain why the ¹³C NMR spectrum of 2-methylpropan-2-ol, (CH₃)₃COH, has only two peaks even though the molecule has four carbon atoms.[2 marks]Total for question 1: 4 marks
- 2The ¹H NMR spectrum of ethyl ethanoate, CH₃COOCH₂CH₃, is recorded in a solvent that contains no hydrogen atoms, using tetramethylsilane (TMS) as a reference standard.(a)Which statement gives a reason for using TMS as the reference standard?[1 mark]
- AAll 12 hydrogen atoms are in the same environment, giving one sharp peak at a lower chemical shift than most other protons
- BIt is polar and dissolves in water
- CIt has the highest chemical shift of any proton
- DIt splits the peaks of the sample into multiplets
(b)What is the ratio of the peak areas in the ¹H NMR spectrum of ethyl ethanoate?[1 mark]- A1 : 1 : 1
- B3 : 5
- C3 : 2 : 3
- D2 : 2 : 3
(c)Deduce the splitting patterns of the signals from the CH₂ group and from the CH₃ of the ethyl group in ethyl ethanoate, explaining your answers.[2 marks]Total for question 2: 4 marks
- 3Compound Z has the molecular formula C₄H₈O₂ and is an ester. Its ¹H NMR spectrum has three peaks: δ 3.7 (singlet, relative peak area 3), δ 2.3 (quartet, relative peak area 2) and δ 1.1 (triplet, relative peak area 3). Its ¹³C NMR spectrum has four peaks.(a)Use the ¹H NMR data to deduce the structure of compound Z. Explain the singlet, the quartet and the triplet.[3 marks](b)Another isomer of Z is propan-2-yl methanoate, HCOOCH(CH₃)₂. Explain how its ¹³C NMR and ¹H NMR spectra would differ from those of Z.[4 marks]
Total for question 3: 7 marks
- 4Two structural isomers of C₃H₇Br, 1-bromopropane (CH₃CH₂CH₂Br) and 2-bromopropane ((CH₃)₂CHBr), are in unlabelled bottles. A technician plans to identify them using NMR spectroscopy.(a)Explain how the ¹³C NMR spectra and the low-resolution ¹H NMR spectra would allow the technician to tell the two isomers apart.[6 marks](b)Predict the splitting pattern and relative chemical shift of each signal in the high-resolution ¹H NMR spectrum of 1-bromopropane, and state how the CH and CH₃ signals of 2-bromopropane are split.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).