Total entropy change and feasibilityEdexcel International A Level Chemistry: Subtopic test
10 questions, 27 marks
Edexcel International A Level Chemistry
Total entropy change and feasibility
Total 27 marks
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Date
- 1Instant cold packs contain solid ammonium nitrate and a sealed pouch of water. When the pouch is burst, the solid dissolves: NH₄NO₃(s) + aq → NH₄⁺(aq) + NO₃⁻(aq). The enthalpy change of solution is +25.7 kJ mol⁻¹ and the entropy change of the system is +108.5 J K⁻¹ mol⁻¹. The pack is used at 298 K and becomes noticeably cold as the solid dissolves.(a)Which statement best explains why the dissolving is spontaneous at 298 K even though it is endothermic?[1 mark]
- AEvery endothermic process is spontaneous at room temperature
- BThe increase in entropy of the system outweighs the decrease in entropy of the surroundings, so ΔStotal is positive
- CThe entropy of the surroundings increases because heat is taken in from them
- DThe reaction has a low activation energy so it must be thermodynamically feasible
(b)What is the entropy change of the surroundings when the ammonium nitrate dissolves at 298 K?[1 mark]- A+86.2 J K⁻¹ mol⁻¹
- B−0.0862 J K⁻¹ mol⁻¹
- C−7.66 × 10⁶ J K⁻¹ mol⁻¹
- D−86.2 J K⁻¹ mol⁻¹
(c)Calculate the total entropy change for the dissolving at 298 K and state what it shows about feasibility.[2 marks]Total for question 1: 4 marks
- 2In the Haber process, nitrogen and hydrogen react to make ammonia: N₂(g) + 3H₂(g) → 2NH₃(g), ΔH = −92.0 kJ mol⁻¹. Standard molar entropies at 298 K are: N₂(g) 191.6, H₂(g) 130.6 and NH₃(g) 192.3 J K⁻¹ mol⁻¹.(a)What is the entropy change of the system for the reaction as written?[1 mark]
- A−198.8 J K⁻¹ mol⁻¹
- B+198.8 J K⁻¹ mol⁻¹
- C−129.9 J K⁻¹ mol⁻¹
- D+62.4 J K⁻¹ mol⁻¹
(b)Which statement correctly describes the effect of increasing the temperature on ΔSsurroundings for this reaction?[1 mark]- AIt becomes larger because more heat is released at a higher temperature
- BIt becomes negative above a certain temperature
- CIt stays positive but becomes smaller in magnitude, because ΔSsurroundings = −ΔH/T
- DIt is unchanged, because ΔH is a constant
(c)Explain, with a calculation of ΔSsurroundings at 298 K, why this reaction is feasible even though ΔSsystem is negative.[2 marks]Total for question 2: 4 marks
- 3Limestone is heated in a kiln to make quicklime: CaCO₃(s) → CaO(s) + CO₂(g), ΔH = +178 kJ mol⁻¹. Standard molar entropies at 298 K are: CaCO₃(s) 92.9, CaO(s) 39.7 and CO₂(g) 213.6 J K⁻¹ mol⁻¹. Assume that ΔH and the entropy values do not change with temperature.(a)Calculate ΔSsystem and ΔSsurroundings at 298 K for this reaction, and use them to show that the decomposition is not feasible at 298 K.[3 marks](b)Calculate the minimum temperature at which the decomposition becomes feasible, and explain why raising the temperature makes it feasible.[4 marks]
Total for question 3: 7 marks
- 4Methane burns in air: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l), with a standard enthalpy change of combustion of −890 kJ mol⁻¹. Standard molar entropies at 298 K are: CH₄(g) 186.3, O₂(g) 205.0, CO₂(g) 213.6 and H₂O(l) 69.9 J K⁻¹ mol⁻¹. A mixture of methane and air can be stored in a closed vessel at 298 K for years without any reaction.(a)Calculate ΔStotal for the combustion of methane at 298 K and state what the value shows.[6 marks](b)The methane–air mixture does not react at 298 K. Explain why this does not contradict your answer to (a), and explain why a spark makes it burn.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).