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Intermolecular forces and physical propertiesEdexcel International A Level Chemistry: Subtopic test

10 questions, 27 marks

Edexcel International A Level Chemistry

Intermolecular forces and physical properties

Total 27 marks

Name

Class

Date

  1. 1
    Alkanes are used as fuels. The boiling temperatures of the first four straight-chain alkanes are: methane 112 K, ethane 184 K, propane 231 K and butane 273 K.
    (a)
    Which intermolecular forces act between molecules of butane?
    [1 mark]
    • ALondon forces and permanent dipole–permanent dipole attractions
    • BLondon forces and hydrogen bonds
    • CPermanent dipole–permanent dipole attractions only
    • DLondon forces only
    (b)
    Which statement best explains the increase in boiling temperature from methane to butane?
    [1 mark]
    • AThe covalent bonds between carbon atoms get stronger
    • BHydrogen bonds form between the longer molecules
    • CLarger molecules have more electrons, so the London forces between them are stronger
    • DThe molecules become polar as the chain gets longer
    (c)
    Predict whether the boiling temperature of pentane is higher or lower than that of butane. Give a reason.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Pentane, 2-methylbutane and 2,2-dimethylpropane are isomers with the molecular formula C₅H₁₂. Pentane has an unbranched chain, 2-methylbutane has one methyl branch and 2,2-dimethylpropane has two methyl branches on the same carbon atom. Their boiling temperatures are 309 K, 301 K and 283 K respectively.
    (a)
    Which statement about pentane, 2-methylbutane and 2,2-dimethylpropane is correct?
    [1 mark]
    • AThe molecules have different numbers of electrons
    • BEach molecule has the same number of electrons, so the differences in boiling temperature arise from shape
    • CThey have different molecular formulae
    • DThey contain different functional groups
    (b)
    Which statement best explains why 2,2-dimethylpropane has the lowest boiling temperature?
    [1 mark]
    • AIts compact, branched molecules have less surface contact with each other, so the London forces are weaker
    • BIts molecules are polar, which weakens the attractions
    • CIt has fewer electrons per molecule than pentane
    • DIts covalent bonds are weaker than those of pentane
    (c)
    Explain why pentane has a higher boiling temperature than 2-methylbutane.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Methanol, CH₃OH, and ethane, C₂H₆, each have 18 electrons per molecule. Methanol boils at 338 K and ethane boils at 184 K. Propan-1-ol, CH₃CH₂CH₂OH, and butane, C₄H₁₀, each have 34 electrons per molecule, and ethanol, C₂H₅OH, has 26 electrons per molecule.
    (a)
    Explain why methanol has a much higher boiling temperature than ethane.
    [3 marks]
    (b)
    (i) Explain why propan-1-ol is less volatile than butane. (ii) Predict, with a reason, whether propan-1-ol boils at a higher or lower temperature than ethanol.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A data book gives these boiling temperatures. Hydrogen halides: HF 293 K, HCl 188 K, HBr 206 K, HI 238 K. Alkanes: hexane 342 K, octane 399 K and 2,2-dimethylbutane 323 K. Hexane and 2,2-dimethylbutane are isomers with the formula C₆H₁₄.
    (a)
    Explain the trend in boiling temperatures of the hydrogen halides from HF to HI.
    [6 marks]
    (b)
    Explain the order of the boiling temperatures of octane, hexane and 2,2-dimethylbutane.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).