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FP1: Matrix algebraEdexcel International A Level Further Maths: Topic test

20 questions, 54 marks

Edexcel International A Level Further Maths

FP1: Matrix algebra topic test

Total 54 marks

Name

Class

Date

  1. 1
    A=(3−214)\mathbf{A}=\begin{pmatrix}3&-2\\ 1&4\end{pmatrix} and B=(05−12)\mathbf{B}=\begin{pmatrix}0&5\\ -1&2\end{pmatrix}.
    (a)
    Find A−2B\mathbf{A}-2\mathbf{B}.
    [1 mark]
    • A(38−18)\begin{pmatrix}3&8\\ -1&8\end{pmatrix}
    • B(3−1230)\begin{pmatrix}3&-12\\ 3&0\end{pmatrix}
    • C(3−722)\begin{pmatrix}3&-7\\ 2&2\end{pmatrix}
    • D(6−936)\begin{pmatrix}6&-9\\ 3&6\end{pmatrix}
    (b)
    Find det⁡A\det\mathbf{A}.
    [1 mark]
    • A1010
    • B1212
    • C1414
    • D−14-14
    (c)
    Find AB\mathbf{AB}.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A cinema records ticket sales in the matrix T=(1208015095)\mathbf{T}=\begin{pmatrix}120&80\\ 150&95\end{pmatrix}. The rows are Saturday and Sunday and the columns are adult and child tickets. An adult ticket costs £9 and a child ticket costs £5, and these prices are the entries of p=(95)\mathbf{p}=\begin{pmatrix}9\\ 5\end{pmatrix}.
    (a)
    Find Tp\mathbf{Tp}, the total takings in pounds on Saturday and on Sunday.
    [1 mark]
    • A(14801825)\begin{pmatrix}1480\\ 1825\end{pmatrix}
    • B(13201605)\begin{pmatrix}1320\\ 1605\end{pmatrix}
    • C(200245)\begin{pmatrix}200\\ 245\end{pmatrix}
    • D(10804001350475)\begin{pmatrix}1080&400\\ 1350&475\end{pmatrix}
    (b)
    Sales fall by 10%10\% in every category the following weekend. Which matrix shows the new sales?
    [1 mark]
    • A(128159.5)\begin{pmatrix}12&8\\ 15&9.5\end{pmatrix}
    • B(13288165104.5)\begin{pmatrix}132&88\\ 165&104.5\end{pmatrix}
    • C(119.979.9149.994.9)\begin{pmatrix}119.9&79.9\\ 149.9&94.9\end{pmatrix}
    • D(1087213585.5)\begin{pmatrix}108&72\\ 135&85.5\end{pmatrix}
    (c)
    The prices rise to £10 for an adult ticket and £6 for a child ticket. Use a matrix product to find the total takings on each of the two days.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The matrix M=(k23k−1)\mathbf{M}=\begin{pmatrix}k&2\\ 3&k-1\end{pmatrix}, where kk is a real constant.
    (a)
    Given that M\mathbf{M} is singular, find the possible values of kk.
    [3 marks]
    (b)
    Given that k=4k=4, find M−1\mathbf{M}^{-1} and use it to solve M(xy)=(109)\mathbf{M}\begin{pmatrix}x\\ y\end{pmatrix}=\begin{pmatrix}10\\ 9\end{pmatrix}.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    P=(1235)\mathbf{P}=\begin{pmatrix}1&2\\ 3&5\end{pmatrix} and Q=(2111)\mathbf{Q}=\begin{pmatrix}2&1\\ 1&1\end{pmatrix}.
    (a)
    Find PQ\mathbf{PQ} and (PQ)−1(\mathbf{PQ})^{-1}. Verify, by evaluating Q−1P−1\mathbf{Q}^{-1}\mathbf{P}^{-1}, that (PQ)−1=Q−1P−1(\mathbf{PQ})^{-1}=\mathbf{Q}^{-1}\mathbf{P}^{-1}.
    [6 marks]
    (b)
    (i) Show that P2−6P=I\mathbf{P}^2-6\mathbf{P}=\mathbf{I}, where I\mathbf{I} is the 2×22\times2 identity matrix. (ii) Hence express P−1\mathbf{P}^{-1} in terms of P\mathbf{P} and I\mathbf{I}. (iii) Find the matrix X\mathbf{X} such that PX=Q\mathbf{PX}=\mathbf{Q}.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    R=(5−32−1)\mathbf{R}=\begin{pmatrix}5&-3\\ 2&-1\end{pmatrix}.
    (a)
    Find R2\mathbf{R}^2.
    [1 mark]
    • A(25941)\begin{pmatrix}25&9\\ 4&1\end{pmatrix}
    • B(10−64−2)\begin{pmatrix}10&-6\\ 4&-2\end{pmatrix}
    • C(19−1285)\begin{pmatrix}19&-12\\ 8&5\end{pmatrix}
    • D(19−128−5)\begin{pmatrix}19&-12\\ 8&-5\end{pmatrix}
    (b)
    Find R−1\mathbf{R}^{-1}.
    [1 mark]
    • A(−13−25)\begin{pmatrix}-1&3\\ -2&5\end{pmatrix}
    • B(−1−325)\begin{pmatrix}-1&-3\\ 2&5\end{pmatrix}
    • C(53−2−1)\begin{pmatrix}5&3\\ -2&-1\end{pmatrix}
    • D(1−32−5)\begin{pmatrix}1&-3\\ 2&-5\end{pmatrix}
    (c)
    Given that R(xy)=(12)\mathbf{R}\begin{pmatrix}x\\ y\end{pmatrix}=\begin{pmatrix}1\\ 2\end{pmatrix}, use R−1\mathbf{R}^{-1} to find xx and yy.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    A rental company records the number of bikes (first column) and scooters (second column) at depot X (first row) and depot Y (second row) at 8 am in N=(127914)\mathbf{N}=\begin{pmatrix}12&7\\ 9&14\end{pmatrix}. During the day the changes in stock are given by C=(−324−5)\mathbf{C}=\begin{pmatrix}-3&2\\ 4&-5\end{pmatrix}.
    (a)
    Find the matrix showing the stock at the end of the day.
    [1 mark]
    • A(155519)\begin{pmatrix}15&5\\ 5&19\end{pmatrix}
    • B(−8−1129−52)\begin{pmatrix}-8&-11\\ 29&-52\end{pmatrix}
    • C(99139)\begin{pmatrix}9&9\\ 13&9\end{pmatrix}
    • D(−15−5−5−19)\begin{pmatrix}-15&-5\\ -5&-19\end{pmatrix}
    (b)
    A bike earns £8 per day and a scooter earns £15 per day. Which matrix gives the daily earnings of each depot at 8 am?
    [1 mark]
    • A(236247)\begin{pmatrix}236\\ 247\end{pmatrix}
    • B(201282)\begin{pmatrix}201\\ 282\end{pmatrix}
    • C(1923)\begin{pmatrix}19\\ 23\end{pmatrix}
    • D(9610572210)\begin{pmatrix}96&105\\ 72&210\end{pmatrix}
    (c)
    Find the value of kk for which N+kC\mathbf{N}+k\mathbf{C} has top-left entry 66, and write down this matrix.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    H=(2312)\mathbf{H}=\begin{pmatrix}2&3\\ 1&2\end{pmatrix}, and the matrix K\mathbf{K} satisfies HK=(7443)\mathbf{HK}=\begin{pmatrix}7&4\\ 4&3\end{pmatrix}.
    (a)
    Find H−1\mathbf{H}^{-1}, showing your value of det⁡H\det\mathbf{H}.
    [3 marks]
    (b)
    Find K\mathbf{K}, and hence find K−1\mathbf{K}^{-1}.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    L=(2−1−32)\mathbf{L}=\begin{pmatrix}2&-1\\ -3&2\end{pmatrix}.
    (a)
    (i) Show that L2−4L+I=0\mathbf{L}^2-4\mathbf{L}+\mathbf{I}=\mathbf{0}. (ii) Hence find L−1\mathbf{L}^{-1} without using the determinant formula.
    [6 marks]
    (b)
    The matrix T=(1k23)\mathbf{T}=\begin{pmatrix}1&k\\ 2&3\end{pmatrix}, where kk is a constant. (i) Find LT\mathbf{LT} in terms of kk. (ii) Find the value of kk for which LT\mathbf{LT} is singular. (iii) For k=1k=1, find (LT)−1(\mathbf{LT})^{-1}.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).