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Mechanics 2 (M2): Kinematics of a particle moving in a straight line or planeEdexcel International A Level Further Maths: Topic test

20 questions, 54 marks

Edexcel International A Level Further Maths

Mechanics 2 (M2): Kinematics of a particle moving in a straight line or plane topic test

Total 54 marks

Name

Class

Date

  1. 1
    A pebble is thrown vertically upwards with speed 19.6 m s−119.6\text{ m s}^{-1} from a point on a bridge 24.524.5 m above a river. The pebble is modelled as a particle moving freely under gravity and later falls into the river. Take g=9.8 m s−2g=9.8\text{ m s}^{-2}.
    (a)
    Find the greatest height of the pebble above the bridge.
    [1 mark]
    • A39.239.2 m
    • B19.619.6 m
    • C78.478.4 m
    • D44.144.1 m
    (b)
    Find the time taken for the pebble to reach the river.
    [1 mark]
    • A55 s
    • B44 s
    • C11 s
    • D99 s
    (c)
    Find the speed of the pebble as it reaches the river.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A particle moves on a straight line. At time tt seconds, t≥0t\ge0, its velocity is v m s−1v\text{ m s}^{-1}, where v=t2−6t+5v=t^2-6t+5.
    (a)
    Find the acceleration of the particle when t=4t=4.
    [1 mark]
    • A−3 m s−2-3\text{ m s}^{-2}
    • B8 m s−28\text{ m s}^{-2}
    • C14 m s−214\text{ m s}^{-2}
    • D2 m s−22\text{ m s}^{-2}
    (b)
    Find the displacement of the particle between t=0t=0 and t=3t=3.
    [1 mark]
    • A33 m
    • B−4-4 m
    • C−3-3 m
    • D1515 m
    (c)
    Find the times at which the particle is instantaneously at rest.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A ball is projected from a point OO on horizontal ground with speed 24.5 m s−124.5\text{ m s}^{-1} at an angle α\alpha above the horizontal, where tan⁡α=43\tan\alpha=\frac43. The ball moves freely under gravity. Take g=9.8 m s−2g=9.8\text{ m s}^{-2}.
    (a)
    Find the time for which the ball is in the air before it returns to the ground.
    [3 marks]
    (b)
    Find the speed of the ball when it is 14.714.7 m above the ground.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A ball moves freely under gravity. At time tt seconds its position vector relative to a fixed point OO on horizontal ground is r=12t i+(19.6t−4.9t2) j\mathbf{r}=12t\,\mathbf{i}+(19.6t-4.9t^2)\,\mathbf{j} metres, where i\mathbf{i} is horizontal and j\mathbf{j} is vertically upwards.
    (a)
    Find the greatest height of the ball above the ground, justifying your method using the velocity of the ball.
    [6 marks]
    (b)
    The ball returns to ground level at the point AA. Find the distance OAOA and the speed of the ball at AA.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    A marble leaves the edge of a horizontal table of height 0.7840.784 m with horizontal speed 2 m s−12\text{ m s}^{-1}. It then moves freely under gravity until it hits the horizontal floor. Take g=9.8 m s−2g=9.8\text{ m s}^{-2}.
    (a)
    Find the time taken by the marble to reach the floor.
    [1 mark]
    • A0.160.16 s
    • B0.080.08 s
    • C0.40.4 s
    • D0.80.8 s
    (b)
    Find the horizontal distance from the edge of the table to the point where the marble hits the floor.
    [1 mark]
    • A55 m
    • B0.320.32 m
    • C1.61.6 m
    • D0.80.8 m
    (c)
    Find the vertical component of the velocity of the marble as it hits the floor.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    A particle moves on a straight line and passes through the point OO when t=0t=0 with velocity 12 m s−112\text{ m s}^{-1}. At time tt seconds its acceleration is (12t−18) m s−2(12t-18)\text{ m s}^{-2}.
    (a)
    Find the velocity of the particle when t=3t=3.
    [1 mark]
    • A12 m s−112\text{ m s}^{-1}
    • B18 m s−118\text{ m s}^{-1}
    • C0 m s−10\text{ m s}^{-1}
    • D54 m s−154\text{ m s}^{-1}
    (b)
    Find the displacement of the particle from OO when t=2t=2.
    [1 mark]
    • A00 m
    • B44 m
    • C−20-20 m
    • D1616 m
    (c)
    Find the least velocity of the particle for t≥0t\ge0.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    A particle PP moves in a horizontal plane. At time tt seconds its velocity is v=[(4t−3)i+(6−t2)j] m s−1\mathbf{v}=\left[(4t-3)\mathbf{i}+(6-t^2)\mathbf{j}\right]\text{ m s}^{-1}. When t=0t=0 the position vector of PP relative to a fixed origin OO is (2i−j)(2\mathbf{i}-\mathbf{j}) m.
    (a)
    Find the magnitude of the acceleration of PP when t=2t=2.
    [3 marks]
    (b)
    Find the position vector of PP when t=3t=3.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    A ball is hit from a point OO on horizontal ground with speed 20 m s−120\text{ m s}^{-1} at an angle α\alpha above the horizontal, where tan⁡α=34\tan\alpha=\frac34. A vertical wall of height 55 m stands on the ground at a horizontal distance of 2424 m from OO, in the vertical plane of the motion. The ball is modelled as a particle moving freely under gravity. Take g=9.8 m s−2g=9.8\text{ m s}^{-2}.
    (a)
    Show that the ball passes over the wall and find the vertical distance by which it clears the top of the wall.
    [6 marks]
    (b)
    Find the speed of the ball, and the angle its direction of motion makes with the horizontal, at the instant it passes over the wall.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).