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FP2: SeriesEdexcel International A Level Further Maths: Topic test

20 questions, 54 marks

Edexcel International A Level Further Maths

FP2: Series topic test

Total 54 marks

Name

Class

Date

  1. 1
    A series has general term ur=1r(r+1)u_r=\frac{1}{r(r+1)} for r≥1r\ge1.
    (a)
    Which of the following is uru_r written in partial fractions?
    [1 mark]
    • A1r−1r+1\frac1r-\frac1{r+1}
    • B1r+1r+1\frac1r+\frac1{r+1}
    • C1r+1−1r\frac1{r+1}-\frac1r
    • D12(1r−1r+1)\frac12\left(\frac1r-\frac1{r+1}\right)
    (b)
    Find ∑r=1nur\sum_{r=1}^{n}u_r.
    [1 mark]
    • A1n+1\frac{1}{n+1}
    • B1+1n+11+\frac{1}{n+1}
    • Cnn+1\frac{n}{n+1}
    • D1−1n1-\frac1n
    (c)
    Find the sum to infinity of the series.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Let f(r)=2rf(r)=2^{r} for positive integers rr.
    (a)
    Find f(r+1)−f(r)f(r+1)-f(r).
    [1 mark]
    • A11
    • B2r2^{r}
    • C2r+12^{r+1}
    • D22
    (b)
    Find ∑r=1n2r\sum_{r=1}^{n}2^{r}.
    [1 mark]
    • A2n+1−12^{n+1}-1
    • B2n−22^{n}-2
    • C2n+12^{n+1}
    • D2n+1−22^{n+1}-2
    (c)
    Hence find ∑r=4102r\sum_{r=4}^{10}2^{r}.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A series has general term ur=1(3r−1)(3r+2)u_r=\frac{1}{(3r-1)(3r+2)} for r≥1r\ge1.
    (a)
    Express uru_r in partial fractions.
    [3 marks]
    (b)
    Hence find ∑r=1nur\sum_{r=1}^{n}u_r, giving your answer as a single fraction in terms of nn.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The general term of a series is ur=r(r+1)!u_r=\frac{r}{(r+1)!} for r≥1r\ge1.
    (a)
    Show that ur=1r!−1(r+1)!u_r=\frac{1}{r!}-\frac{1}{(r+1)!} and hence find ∑r=1nur\sum_{r=1}^{n}u_r in terms of nn.
    [6 marks]
    (b)
    Find the least value of nn for which ∑r=3nur\sum_{r=3}^{n}u_r is within 0.0010.001 of ∑r=3∞ur\sum_{r=3}^{\infty}u_r.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    Let f(r)=r3f(r)=r^3 for positive integers rr.
    (a)
    Find f(r)−f(r−1)f(r)-f(r-1).
    [1 mark]
    • A11
    • B3r2+3r+13r^2+3r+1
    • C3r2−13r^2-1
    • D3r2−3r+13r^2-3r+1
    (b)
    Find ∑r=1n(3r2−3r+1)\sum_{r=1}^{n}\left(3r^2-3r+1\right).
    [1 mark]
    • An3n^3
    • Bn3−1n^3-1
    • Cn3+1n^3+1
    • D(n+1)3(n+1)^3
    (c)
    Hence find ∑r=610(3r2−3r+1)\sum_{r=6}^{10}\left(3r^2-3r+1\right).
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    Let f(r)=1r2f(r)=\frac{1}{r^2} for positive integers rr.
    (a)
    Find f(r)−f(r+1)f(r)-f(r+1) as a single fraction.
    [1 mark]
    • A1r2(r+1)2\frac{1}{r^2(r+1)^2}
    • B2r−1r2(r+1)2\frac{2r-1}{r^2(r+1)^2}
    • C2r+1r2(r+1)2\frac{2r+1}{r^2(r+1)^2}
    • D−2r+1r2(r+1)2-\frac{2r+1}{r^2(r+1)^2}
    (b)
    Find ∑r=1n2r+1r2(r+1)2\sum_{r=1}^{n}\frac{2r+1}{r^2(r+1)^2}.
    [1 mark]
    • A1−1n21-\frac{1}{n^2}
    • B1−1(n+1)21-\frac{1}{(n+1)^2}
    • C1(n+1)2−1\frac{1}{(n+1)^2}-1
    • D1+1(n+1)21+\frac{1}{(n+1)^2}
    (c)
    Hence evaluate ∑r=192r+1r2(r+1)2\sum_{r=1}^{9}\frac{2r+1}{r^2(r+1)^2} exactly.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    A series has general term ur=ln⁡(r(r+2)(r+1)2)u_r=\ln\left(\frac{r(r+2)}{(r+1)^2}\right) for r≥1r\ge1.
    (a)
    Show that ur=f(r)−f(r+1)u_r=f(r)-f(r+1), where f(r)=ln⁡(rr+1)f(r)=\ln\left(\frac{r}{r+1}\right).
    [3 marks]
    (b)
    Hence find ∑r=1nur\sum_{r=1}^{n}u_r, and state the sum to infinity.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    A series has general term ur=2r+3r(r+1)(r+2)u_r=\frac{2r+3}{r(r+1)(r+2)} for r≥1r\ge1.
    (a)
    Express uru_r in partial fractions, and hence show that ∑r=1nur=74−32(n+1)−12(n+2)\sum_{r=1}^{n}u_r=\frac74-\frac{3}{2(n+1)}-\frac{1}{2(n+2)}.
    [6 marks]
    (b)
    Find the sum to infinity of the series, and the least value of nn for which ∑r=1nur\sum_{r=1}^{n}u_r differs from the sum to infinity by less than 0.010.01.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).