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FP2: Second order differential equationsEdexcel International A Level Further Maths: Topic test

20 questions, 54 marks

Edexcel International A Level Further Maths

FP2: Second order differential equations topic test

Total 54 marks

Name

Class

Date

  1. 1
    The function y(x)y(x) satisfies the differential equation d2ydx2+6dydx+13y=0\frac{d^2y}{dx^2}+6\frac{dy}{dx}+13y=0.
    (a)
    Find the roots of the auxiliary equation.
    [1 mark]
    • A−3±4i-3\pm4\mathrm{i}
    • B3±2i3\pm2\mathrm{i}
    • C−3±2i-3\pm2\mathrm{i}
    • D−6±4i-6\pm4\mathrm{i}
    (b)
    Which expression is the general solution of the differential equation?
    [1 mark]
    • Ay=e−3x(Acos⁡2x+Bsin⁡2x)y=\mathrm{e}^{-3x}(A\cos2x+B\sin2x)
    • By=e3x(Acos⁡2x+Bsin⁡2x)y=\mathrm{e}^{3x}(A\cos2x+B\sin2x)
    • Cy=e−3x(Acos⁡4x+Bsin⁡4x)y=\mathrm{e}^{-3x}(A\cos4x+B\sin4x)
    • Dy=e−2x(Acos⁡3x+Bsin⁡3x)y=\mathrm{e}^{-2x}(A\cos3x+B\sin3x)
    (c)
    Given that y=0y=0 and dydx=4\frac{dy}{dx}=4 when x=0x=0, find yy in terms of xx.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The differential equation d2ydx2+4dydx+5y=8e−2x\frac{d^2y}{dx^2}+4\frac{dy}{dx}+5y=8\mathrm{e}^{-2x} is to be solved using the substitution y=ze−2xy=z\mathrm{e}^{-2x}, where zz is a function of xx.
    (a)
    Find dydx\frac{dy}{dx} in terms of zz and dzdx\frac{dz}{dx}.
    [1 mark]
    • A(dzdx+2z)e−2x\left(\frac{dz}{dx}+2z\right)\mathrm{e}^{-2x}
    • Bdzdxe−2x\frac{dz}{dx}\mathrm{e}^{-2x}
    • C−2dzdxe−2x-2\frac{dz}{dx}\mathrm{e}^{-2x}
    • D(dzdx−2z)e−2x\left(\frac{dz}{dx}-2z\right)\mathrm{e}^{-2x}
    (b)
    The substitution transforms the differential equation into which equation?
    [1 mark]
    • Ad2zdx2+z=8e−2x\frac{d^2z}{dx^2}+z=8\mathrm{e}^{-2x}
    • Bd2zdx2+z=8\frac{d^2z}{dx^2}+z=8
    • Cd2zdx2+4dzdx+z=8\frac{d^2z}{dx^2}+4\frac{dz}{dx}+z=8
    • Dd2zdx2+9z=8\frac{d^2z}{dx^2}+9z=8
    (c)
    Solve the transformed equation and hence find the general solution for yy in terms of xx.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    The differential equation d2ydx2−2dydx+10y=10x−3\frac{d^2y}{dx^2}-2\frac{dy}{dx}+10y=10x-3.
    (a)
    Find the complementary function.
    [3 marks]
    (b)
    Hence find the general solution of the differential equation.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The function y(x)y(x), defined for x>0x>0, satisfies the differential equation x2d2ydx2+xdydx−4y=3x2x^2\frac{d^2y}{dx^2}+x\frac{dy}{dx}-4y=3x^2.
    (a)
    Use the substitution x=etx=\mathrm{e}^t to show that the differential equation can be written as d2ydt2−4y=3e2t\frac{d^2y}{dt^2}-4y=3\mathrm{e}^{2t}, and find the general solution of this equation for yy in terms of tt.
    [6 marks]
    (b)
    Given that y=1y=1 and dydx=3\frac{dy}{dx}=3 when x=1x=1, find yy in terms of xx.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    The differential equation x2d2ydx2−xdydx+5y=0x^2\frac{d^2y}{dx^2}-x\frac{dy}{dx}+5y=0 is to be solved for x>0x>0 using the substitution x=etx=\mathrm{e}^t.
    (a)
    Express x2d2ydx2x^2\frac{d^2y}{dx^2} in terms of derivatives of yy with respect to tt.
    [1 mark]
    • Ad2ydt2\frac{d^2y}{dt^2}
    • Bd2ydt2−dydt\frac{d^2y}{dt^2}-\frac{dy}{dt}
    • Cd2ydt2+dydt\frac{d^2y}{dt^2}+\frac{dy}{dt}
    • De2td2ydt2\mathrm{e}^{2t}\frac{d^2y}{dt^2}
    (b)
    The transformed equation is a constant-coefficient equation in yy and tt. What is its auxiliary equation?
    [1 mark]
    • Am2−m+5=0m^2-m+5=0
    • Bm2+2m+5=0m^2+2m+5=0
    • Cm2−2m−5=0m^2-2m-5=0
    • Dm2−2m+5=0m^2-2m+5=0
    (c)
    Hence find the general solution for yy in terms of xx.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    The function y(x)y(x) satisfies the differential equation d2ydx2+dydx−6y=20e2x\frac{d^2y}{dx^2}+\frac{dy}{dx}-6y=20\mathrm{e}^{2x}.
    (a)
    Which expression is the complementary function?
    [1 mark]
    • Ay=Ae2x+Be−3xy=A\mathrm{e}^{2x}+B\mathrm{e}^{-3x}
    • By=Ae−2x+Be3xy=A\mathrm{e}^{-2x}+B\mathrm{e}^{3x}
    • Cy=Aex+Be−6xy=A\mathrm{e}^{x}+B\mathrm{e}^{-6x}
    • Dy=(A+Bx)e2xy=(A+Bx)\mathrm{e}^{2x}
    (b)
    Which is the correct form to try for a particular integral?
    [1 mark]
    • Ake2xk\mathrm{e}^{2x}
    • Bkx2e2xkx^2\mathrm{e}^{2x}
    • Ckxe2xkx\mathrm{e}^{2x}
    • Dke20xk\mathrm{e}^{20x}
    (c)
    Find the particular integral, using the form from part (b).
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    The differential equation d2ydx2+4dydx+3y=10sin⁡x\frac{d^2y}{dx^2}+4\frac{dy}{dx}+3y=10\sin x.
    (a)
    Find a particular integral.
    [3 marks]
    (b)
    Given that y=0y=0 and dydx=1\frac{dy}{dx}=1 when x=0x=0, find yy in terms of xx.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    A particle moves in a straight line. Its displacement xx metres from a fixed point at time tt seconds satisfies d2xdt2+2dxdt+5x=10\frac{d^2x}{dt^2}+2\frac{dx}{dt}+5x=10, with x=0x=0 and dxdt=0\frac{dx}{dt}=0 when t=0t=0.
    (a)
    Find xx in terms of tt.
    [6 marks]
    (b)
    Show that dxdt=5e−tsin⁡2t\frac{dx}{dt}=5\mathrm{e}^{-t}\sin2t, and hence find the greatest displacement of the particle, giving your answer to 3 significant figures. Justify that this is the greatest value.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).