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Kinematics (AS)AQA A-Level Maths: Topic test

20 questions, 54 marks

AQA A-Level Maths

Kinematics (AS) topic test

Total 54 marks

Name

Class

Date

  1. 1
    A skier of mass 7272 kg slides down a straight slope. The resultant force on the skier down the slope is 108108 N. Take g=9.8g=9.8 m s⁻².
    (a)
    Which of the following gives the newton in terms of SI base units?
    [1 mark]
    • Akg m² s⁻²
    • Bkg m s⁻¹
    • Ckg m⁻¹ s⁻²
    • Dkg m s⁻²
    (b)
    What is the acceleration of the skier down the slope?
    [1 mark]
    • A0.670.67 m s⁻²
    • B77767776 m s⁻²
    • C1.51.5 m s⁻²
    • D3636 m s⁻²
    (c)
    Calculate the weight of the skier, stating its unit.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A tram travels along a straight track. Its velocity increases uniformly from 00 to 1010 m s⁻¹ in the first 55 s, stays constant at 1010 m s⁻¹ for the next 2020 s, then decreases uniformly to 00 in the final 1010 s.
    (a)
    What is the acceleration of the tram during the first 55 s?
    [1 mark]
    • A22 m s⁻²
    • B0.50.5 m s⁻²
    • C1010 m s⁻²
    • D5050 m s⁻²
    (b)
    What is the total distance travelled by the tram?
    [1 mark]
    • A250250 m
    • B275275 m
    • C350350 m
    • D550550 m
    (c)
    Find the average speed of the tram for the whole journey.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A car travelling at 2525 m s⁻¹ along a straight road brakes with constant deceleration and comes to rest after travelling 62.562.5 m.
    (a)
    Find the deceleration of the car.
    [3 marks]
    (b)
    A driver sees a hazard and takes 0.80.8 s to react, during which the car continues at 2525 m s⁻¹, before braking as above. Find the total distance travelled and the total time from seeing the hazard to stopping.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A particle PP moves in a straight line. At time tt seconds, t≥0t\ge0, its velocity is v=3t2−18t+24v=3t^2-18t+24 m s⁻¹. At t=0t=0, PP is at a fixed point OO on the line.
    (a)
    Find the times at which PP is instantaneously at rest and the acceleration of PP at each of these times. Explain what happens to the direction of motion of PP at the first of these times.
    [6 marks]
    (b)
    A second particle QQ starts from rest at OO at t=0t=0 and moves along the same line with constant acceleration 44 m s⁻². Find all the times when PP and QQ are at the same point.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    A van of mass 1.21.2 tonnes (where 11 tonne =1000=1000 kg) is travelling along a straight road at 9090 km h⁻¹. A constant resultant force of 30003000 N then acts on the van in its direction of motion.
    (a)
    What is the initial speed of the van in m s⁻¹?
    [1 mark]
    • A9090
    • B2525
    • C324324
    • D1.51.5
    (b)
    What is the acceleration of the van?
    [1 mark]
    • A2.52.5 m s⁻²
    • B0.40.4 m s⁻²
    • C2525 m s⁻²
    • D36003600 m s⁻²
    (c)
    Find the time taken for the speed of the van to reach 126126 km h⁻¹.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    A robot moves along a straight corridor. Its displacement ss metres from its starting point at time tt seconds is described by a graph made up of three straight lines: ss increases uniformly from 00 to 1212 between t=0t=0 and t=6t=6; ss stays at 1212 between t=6t=6 and t=10t=10; and ss decreases uniformly from 1212 to 22 between t=10t=10 and t=15t=15.
    (a)
    What is the velocity of the robot at t=3t=3?
    [1 mark]
    • A1212 m s⁻¹
    • B0.50.5 m s⁻¹
    • C22 m s⁻¹
    • D44 m s⁻¹
    (b)
    What is the total distance travelled by the robot in the 1515 seconds?
    [1 mark]
    • A22 m
    • B1212 m
    • C2424 m
    • D2222 m
    (c)
    Find the average velocity of the robot over the 1515 seconds.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    A ball is thrown vertically upwards from a point 22 m above horizontal ground with speed 1414 m s⁻¹. Take g=9.8g=9.8 m s⁻² and ignore air resistance.
    (a)
    Find the greatest height of the ball above the ground.
    [3 marks]
    (b)
    Find the time taken for the ball to reach the ground.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    A model rocket is launched vertically from the ground at t=0t=0, starting from rest. For 0≤t≤40\le t\le4 (where tt is in seconds) its net upward acceleration is (8−2t)(8-2t) m s⁻². At t=4t=4 the engine cuts out and the rocket then moves freely under gravity, with g=9.8g=9.8 m s⁻².
    (a)
    Find the velocity and the height of the rocket at t=4t=4.
    [6 marks]
    (b)
    (i) Find the further height gained by the rocket after the engine cuts out. (ii) Find the greatest height of the rocket above the ground. (iii) Find the time for which the rocket continues to rise after the engine cuts out. (iv) State one modelling assumption.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).