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Numerical methodsAQA A-Level Maths: Topic test

20 questions, 54 marks

AQA A-Level Maths

Numerical methods topic test

Total 54 marks

Name

Class

Date

  1. 1
    Let f(x)=x3−7x+5f(x)=x^3-7x+5, which is continuous for all real xx. Some values are f(−2)=11f(-2)=11, f(−1)=11f(-1)=11, f(0)=5f(0)=5, f(1)=−1f(1)=-1, f(2)=−1f(2)=-1, f(3)=11f(3)=11 and f(4)=41f(4)=41.
    (a)
    Which of these intervals must contain a root of f(x)=0f(x)=0?
    [1 mark]
    • A0≤x≤10\le x\le1
    • B1≤x≤21\le x\le2
    • C3≤x≤43\le x\le4
    • D−1≤x≤0-1\le x\le0
    (b)
    Given only f(−2)=11f(-2)=11 and f(3)=11f(3)=11, which conclusion about roots in the interval −2≤x≤3-2\le x\le3 is correct?
    [1 mark]
    • AThere are no roots, because f(−2)f(-2) and f(3)f(3) have the same sign
    • BThere is exactly one root, because both values are positive
    • CThe test is inconclusive: there may be no roots or an even number of roots
    • DThere must be a root, because the two values are equal
    (c)
    Show that f(x)=0f(x)=0 has a root between x=2x=2 and x=3x=3.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The equation e−x=x−1e^{-x}=x-1 has a root α\alpha close to 1.31.3. It can be rearranged as x=1+e−xx=1+e^{-x}, giving the iteration xn+1=1+e−xnx_{n+1}=1+e^{-x_n} with x0=1x_0=1.
    (a)
    What is x2x_2, correct to 3 decimal places?
    [1 mark]
    • A1.3681.368
    • B1.2551.255
    • C1.2851.285
    • D1.0001.000
    (b)
    Which statement correctly describes how the iterates approach α\alpha?
    [1 mark]
    • AThey increase steadily towards α\alpha in a staircase pattern, because g′(α)>0g'(\alpha)>0
    • BThey diverge from α\alpha, because ∣g′(α)∣>1|g'(\alpha)|>1
    • CThey decrease steadily towards α\alpha in a staircase pattern, because 0<g′(α)<10<g'(\alpha)<1
    • DThey alternate either side of α\alpha and converge in a cobweb pattern, because −1<g′(α)<0-1<g'(\alpha)<0
    (c)
    Find x4x_4, correct to 4 decimal places.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Let I=∫02ln⁡(1+x2)dxI=\displaystyle\int_0^2\ln\left(1+x^2\right)dx. The function y=ln⁡(1+x2)y=\ln\left(1+x^2\right) is increasing for x≥0x\ge0.
    (a)
    Use the trapezium rule with 4 strips of equal width to estimate II, giving your answer to 3 decimal places.
    [3 marks]
    (b)
    Use rectangles of width 0.50.5 to find a lower bound and an upper bound for II, giving each to 3 significant figures.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    The equation x4−3x−1=0x^4-3x-1=0 has a positive root α\alpha. Let f(x)=x4−3x−1f(x)=x^4-3x-1.
    (a)
    Show that α\alpha lies between 1.51.5 and 1.61.6. Starting with x0=1.5x_0=1.5, use the Newton-Raphson method twice to find x1x_1 and x2x_2 to 4 decimal places.
    [6 marks]
    (b)
    (i) Explain why the Newton-Raphson method fails when x0=(34)1/3x_0=\left(\frac34\right)^{1/3}. (ii) Show that f(x)=0f(x)=0 can be rearranged as x=(3x+1)1/4x=(3x+1)^{1/4}, and use xn+1=(3xn+1)1/4x_{n+1}=(3x_n+1)^{1/4} with x0=1.5x_0=1.5 to find x1x_1 and x2x_2 to 4 decimal places.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    The integral I=∫0310e−x/2 dxI=\displaystyle\int_0^3 10e^{-x/2}\,dx is estimated using the trapezium rule with 3 strips of equal width.
    (a)
    What is the estimate, correct to 3 significant figures?
    [1 mark]
    • A15.515.5
    • B31.731.7
    • C12.212.2
    • D15.915.9
    (b)
    Which statement about the estimate is correct?
    [1 mark]
    • AIt is an overestimate, because the curve is convex so each chord lies above the curve
    • BIt is an underestimate, because the curve is decreasing
    • CIt is an underestimate, because the curve is convex so each chord lies below the curve
    • DIt is exact, because the strips have equal width
    (c)
    Find the exact value of II and hence the percentage error in the estimate, correct to 2 significant figures.
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    Let f(x)=x−1x−3f(x)=\dfrac{x-1}{x-3} for x≠3x\ne3.
    (a)
    In which interval do the values of ff change sign because of a root of f(x)=0f(x)=0?
    [1 mark]
    • A2≤x≤42\le x\le4
    • B4≤x≤64\le x\le6
    • C0≤x≤20\le x\le2
    • D−2≤x≤0-2\le x\le0
    (b)
    Why does the sign change of ff between x=2x=2 and x=4x=4 not indicate a root?
    [1 mark]
    • Af(2)f(2) and f(4)f(4) are both undefined
    • Bff is not continuous at x=3x=3, which lies in the interval
    • Cff has a repeated root in the interval
    • DThe interval is too wide
    (c)
    Show that f(0)f(0) and f(5)f(5) have the same sign, even though the equation f(x)=0f(x)=0 has a root between 00 and 55. Explain how this happens.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    The concentration CC mg per litre of a drug in a patient's blood, tt hours after an injection, is modelled by C=12te−t/2C=12te^{-t/2}. The concentration is 55 mg per litre at two times, and TT is the later of these. Let f(t)=12te−t/2−5f(t)=12te^{-t/2}-5.
    (a)
    Show that TT lies between 4.94.9 and 55.
    [3 marks]
    (b)
    Show that f(t)=0f(t)=0 can be rearranged as t=2ln⁡(12t5)t=2\ln\left(\dfrac{12t}{5}\right). Use the iteration tn+1=2ln⁡(12tn5)t_{n+1}=2\ln\left(\dfrac{12t_n}{5}\right) with t0=5t_0=5 to find t1t_1 and t2t_2 to 3 decimal places.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    Let f(x)=x3−2x+2f(x)=x^3-2x+2. The equation f(x)=0f(x)=0 has exactly one real root α\alpha.
    (a)
    Show that α\alpha lies between −2-2 and −1.5-1.5. A student uses the Newton-Raphson method with x0=0x_0=0. Find x1x_1 and x2x_2 and describe what happens to the sequence.
    [6 marks]
    (b)
    Starting with x0=−1.5x_0=-1.5, use the Newton-Raphson method twice to find x1x_1 and x2x_2 to 4 decimal places. By evaluating f(−1.775)f(-1.775) and f(−1.765)f(-1.765), show that α=−1.77\alpha=-1.77 to 3 significant figures.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).