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Pure: Exponentials and logarithmsEdexcel A-Level Maths: Topic test

20 questions, 54 marks

Edexcel A-Level Maths

Pure: Exponentials and logarithms topic test

Total 54 marks

Name

Class

Date

  1. 1
    A curve has equation y=2e3x−5y=2\mathrm{e}^{3x}-5.
    (a)
    At which value of yy does the curve cross the yy-axis?
    [1 mark]
    • A−5-5
    • B−3-3
    • C22
    • D−7-7
    (b)
    What is the gradient of the curve at the point where x=0x=0?
    [1 mark]
    • A22
    • B33
    • C66
    • D1818
    (c)
    Find the exact value of xx at the point where the curve crosses the xx-axis.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The positive numbers aa and bb satisfy log⁡2a=3\log_2a=3 and log⁡2b=5\log_2b=5.
    (a)
    What is the value of log⁡2(ab)\log_2(ab)?
    [1 mark]
    • A1515
    • B−2-2
    • C256256
    • D88
    (b)
    What is the value of log⁡2(a2b)\log_2\left(\dfrac{a^2}{b}\right)?
    [1 mark]
    • A11
    • B−4-4
    • C1111
    • D95\frac95
    (c)
    Find the value of log⁡2(a3b)\log_2\left(a^3\sqrt{b}\right).
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    In this question give any answer that is not exact to 3 significant figures.
    (a)
    Solve 7x−2=507^{x-2}=50.
    [3 marks]
    (b)
    Solve 2log⁡2x=3+log⁡2(x−2)2\log_2x=3+\log_2(x-2), where x>2x>2.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Variables xx and yy are modelled by y=abxy=ab^x, where aa and bb are constants. Here yy is the number of subscribers, in thousands, to a streaming service xx years after 1 January 2015. The values of log⁡10y\log_{10}y are linear in xx: log⁡10y=0.9\log_{10}y=0.9 when x=1x=1 and log⁡10y=1.5\log_{10}y=1.5 when x=4x=4.
    (a)
    Show that log⁡10y=log⁡10a+xlog⁡10b\log_{10}y=\log_{10}a+x\log_{10}b. Hence find aa and bb to 3 significant figures.
    [6 marks]
    (b)
    Use the model y=abxy=ab^x, with the unrounded values of aa and bb, to answer the following. (i) Find the value of xx for which y=100y=100. (ii) Interpret the value of bb in context. (iii) Predict the number of subscribers when x=10x=10. (iv) State one limitation of the model for large xx.
    [6 marks]

    Total for question 4: 12 marks

  5. 5
    The function ff is defined by f(x)=ln⁡(3x−2)f(x)=\ln(3x-2) for x>23x>\frac23.
    (a)
    For which value of xx is f(x)=0f(x)=0?
    [1 mark]
    • Ax=1x=1
    • Bx=23x=\frac23
    • Cx=e+23x=\frac{\mathrm{e}+2}{3}
    • Dx=0x=0
    (b)
    What is the solution of f(x)=2f(x)=2?
    [1 mark]
    • Ax=e2−23x=\frac{\mathrm{e}^2-2}{3}
    • Bx=e23+2x=\frac{\mathrm{e}^2}{3}+2
    • Cx=2x=2
    • Dx=e2+23x=\frac{\mathrm{e}^2+2}{3}
    (c)
    Find an expression for f−1(x)f^{-1}(x).
    [2 marks]

    Total for question 5: 4 marks

  6. 6
    A cup of tea cools in a room. Its temperature TT degrees Celsius, tt minutes after it is poured, is modelled by T=20+70e−0.08tT=20+70\mathrm{e}^{-0.08t}.
    (a)
    What is the initial temperature of the tea?
    [1 mark]
    • A20∘20^\circC
    • B70∘70^\circC
    • C90∘90^\circC
    • D0∘0^\circC
    (b)
    According to the model, what value does TT approach for large tt?
    [1 mark]
    • A0∘0^\circC
    • B20∘20^\circC
    • C70∘70^\circC
    • D90∘90^\circC
    (c)
    Find the time taken for the tea to cool to 50∘50^\circC, giving your answer in minutes to 3 significant figures.
    [2 marks]

    Total for question 6: 4 marks

  7. 7
    A car is bought new for £18 000\pounds18\,000. Its value, £V\pounds V, after tt years is modelled by V=18 000×0.85tV=18\,000\times0.85^t.
    (a)
    Find the value of the car after 3 years, to the nearest pound. State what happens to VV as tt becomes very large, and explain why the base 0.850.85 means that the model shows decay rather than growth.
    [3 marks]
    (b)
    Find how long it takes for the value of the car to fall to £6000\pounds6000, giving your answer in years to 3 significant figures.
    [4 marks]

    Total for question 7: 7 marks

  8. 8
    A yeast culture contains NN cells tt hours after the start of an experiment. It is modelled by N=N0ektN=N_0\mathrm{e}^{kt}, where N0N_0 and kk are constants. Initially there are 20002000 cells and after 33 hours there are 54005400 cells.
    (a)
    Find N0N_0 and kk, giving kk to 3 significant figures. Hence find, in hours to 3 significant figures, when the culture first reaches 20 00020\,000 cells.
    [6 marks]
    (b)
    A second culture has M=8000e0.1tM=8000\mathrm{e}^{0.1t} cells at time tt hours. (i) Show that the two cultures have equal numbers of cells when t=ln⁡4k−0.1t=\dfrac{\ln4}{k-0.1}, and find this time to 3 significant figures. (ii) Find the rate at which the first culture is increasing at t=0t=0. (iii) State one limitation of using the model N=N0ektN=N_0\mathrm{e}^{kt} for large tt.
    [6 marks]

    Total for question 8: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).