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Elasticity and Hooke's lawIB MYP Physics: Revision notes

Section 1

Stretching springs and wires

When you apply a force to a spring or wire, it stretches. The extension is how much longer it becomes:

extension = stretched length − natural (original) length

Example: a spring of natural length 20 cm is 26 cm long under a load. Its extension is 26 − 20 = 6 cm.

Always use the extension, not the whole length, in calculations.

Key termsextensionnatural length
Common mistake

The extension is not the total length of the spring. Subtract the natural length first.

Section 2

Hooke's law

For a spring, the extension is directly proportional to the force applied, as long as the spring is not stretched too far.

F = k x

  • F is the force in newtons (N)
  • k is the spring constant in N/m (a stiffer spring has a larger k)
  • x is the extension in metres (m)

Worked example: a spring extends by 5.0 cm (0.050 m) when a 10 N weight is hung from it. k = F ÷ x = 10 ÷ 0.050 = 200 N/m. A 15 N force would give x = 15 ÷ 200 = 0.075 m = 7.5 cm.

Key termsHooke's lawspring constant
Exam tip

Convert centimetres to metres before using F = kx: divide by 100.

Section 3

Force-extension graphs and limits

A force-extension graph has force on the vertical axis and extension on the horizontal axis.

  • The straight line through the origin shows that extension is proportional to force. Its gradient = k, the spring constant.
  • The limit of proportionality is the point where the line starts to curve. Beyond it, Hooke's law no longer works.
  • The elastic limit is the largest force the material can take and still return to its original length when the force is removed. It is at or just beyond the limit of proportionality.

The steeper the straight section, the stiffer the spring.

Key termslimit of proportionalityelastic limitgradient

Section 4

Elastic and plastic deformation

Elastic deformation: the material returns to its original shape and length when the force is removed (a rubber band stretched gently, a spring used within its limit).

Plastic deformation: the material is permanently changed when the force is removed (a spring stretched beyond its elastic limit, a paper clip bent open, modelling clay).

A spring stretched past its elastic limit is weaker and longer afterwards, so it is no longer reliable.

Key termselastic deformationplastic deformation
Common mistake

Stretching something does not make the deformation plastic. It is plastic only if the material stays deformed after the force is removed.

Section 5

Energy stored in a stretched spring

Work is done when you stretch a spring, so energy is stored in it as elastic potential energy. The more you stretch it, the more energy it stores.

When the spring is released, this energy is transferred, for example to kinetic energy of a toy dart or a trampoline user. If a spring is stretched beyond its elastic limit, some of the energy goes into permanently changing the material and is not recovered.

Key termselastic potential energy

Must know

  • Extension = stretched length − natural length.
  • Hooke's law: F = kx, with x in metres and k in N/m.
  • Force-extension graph: straight line, gradient = k.
  • Beyond the limit of proportionality the line curves and F = kx fails.
  • Elastic: returns to shape. Plastic: stays permanently deformed.
  • A stretched spring stores elastic potential energy.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Elasticity and Hooke's law

  1. A trampoline manufacturer in Melbourne joins the mat to the frame with steel springs. Each spring has a natural length of 20 cm. In a test, a weight of 12 N is hung from one spring and its length becomes 26 cm. The spring is not stretched beyond its limit of proportionality.
    The same spring is stretched by a weight of 18 N. Calculate the extension in cm.2 marks
  2. A workshop technician in Kuala Lumpur tests a steel spring by hanging increasing loads from it. Up to 15 N the extension is directly proportional to the load and the spring returns to its original length when the load is removed. A load of 25 N takes the spring beyond its elastic limit.
    Explain what happens to the length of the spring after (i) a 10 N load is removed and (ii) the 25 N load is removed.2 marks
  3. A student in Vancouver hangs loads from a spring and measures the extension each time. A 2.0 N load gives an extension of 4.0 cm, a 4.0 N load gives 8.0 cm, a 6.0 N load gives 12.0 cm, an 8.0 N load gives 16.0 cm and a 10.0 N load gives 22.0 cm.
    Calculate the spring constant of the spring in N/m using the first four results.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).