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Series and parallel circuitsIB MYP Physics: Revision notes

Section 1

Series circuits

In a series circuit the components are connected one after another in a single loop.

  • The current is the same at every point.
  • The potential differences add up to equal the supply p.d.
  • The total resistance is the sum: R total = R₁ + R₂

If one component breaks, the loop is broken and every component stops working.

Worked example: a 6.0 V cell is connected to a 4.0 Ω and an 8.0 Ω resistor in series. R total = 12 Ω. I = 6.0 ÷ 12 = 0.50 A. The p.d. across the 8.0 Ω resistor is 0.50 × 8.0 = 4.0 V.

Key termsseries circuittotal resistance
Exam tip

In a series circuit the p.d. is shared in proportion to the resistances: the larger resistor gets the larger share.

Section 2

Parallel circuits

In a parallel circuit the components are connected on separate branches.

  • The p.d. across each branch is the same as the supply p.d.
  • The currents in the branches add up to equal the current from the supply.
  • The total resistance is less than the smallest resistor, because adding another branch gives the current more paths.

If one branch breaks, the other branches keep working.

Worked example: a 6.0 Ω and a 12 Ω lamp are connected in parallel to 12 V. The currents are 12 ÷ 6.0 = 2.0 A and 12 ÷ 12 = 1.0 A, so the total current is 3.0 A. The total resistance is 12 ÷ 3.0 = 4.0 Ω, which is less than 6.0 Ω.

Key termsparallel circuitbranch
Common mistake

The total resistance of resistors in parallel is always smaller than the smallest one, never larger.

Section 3

Calculating missing values

To find missing values in a simple circuit:

  1. Find the total resistance (add the resistances in series; in parallel it is the supply p.d. ÷ the total current).
  2. Use I = V ÷ R to find the current.
  3. Apply the series or parallel rules for p.d. and current: p.d.s add in series; currents add in parallel.
  4. Use V = I × R for each component.

Write each step with the equation, the numbers and the unit.

Key termstotal currentsupply p.d.

Section 4

Cells in series

When cells are connected in series, end to end in the same direction (positive to negative), their potential differences add up. Two 1.5 V cells in series give 3.0 V.

If one cell is turned round the wrong way, it opposes the other and the total p.d. is reduced (1.5 V − 1.5 V = 0 V for two identical cells).

Key termscells in series

Section 5

Why homes use parallel wiring

Lights and sockets in homes are wired in parallel.

  • Every appliance gets the full mains p.d., so it works at its full power.
  • Each appliance has its own switch and can be turned on and off independently.
  • If one appliance or lamp fails, the others keep working.
  • Adding more appliances does not reduce the p.d. across the others.

The disadvantage is that the currents add, so too many appliances on one socket can draw a dangerously large current.

Key termsmainsparallel wiring

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Exam questions on Series and parallel circuits

  1. A student builds a circuit for a model greenhouse. A 6.0 V cell is connected in series with two resistors, one of 4.0 Ω and one of 8.0 Ω. The cell has negligible internal resistance.
    Calculate the potential difference across the 8.0 Ω resistor.2 marks
  2. An electrician connects two lamps in parallel across a 12 V supply. One lamp has a resistance of 6.0 Ω and the other has a resistance of 12 Ω. The supply has negligible internal resistance.
    Calculate the total current drawn from the supply.2 marks
  3. A group of students investigates how the way lamps are connected affects their brightness. They use three identical lamps and a 4.5 V supply. They connect the lamps first in series and then in parallel, and use an ammeter and a voltmeter to take readings in each arrangement.
    Identify the independent variable, the dependent variable and one control variable.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).