Factors affecting equilibrium and KEdexcel International A Level Chemistry: Flashcards
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State Le Chatelier's principle.
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- State Le Chatelier's principle.
- If a system at equilibrium is disturbed, the position of equilibrium moves to oppose the change.
- What is the effect of increasing pressure on the position of N₂ + 3H₂ ⇌ 2NH₃?
- The position moves right, towards the side with fewer moles of gas.
- What does a catalyst do to the equilibrium composition?
- Nothing: it speeds up forward and reverse reactions equally.
- What is the only factor that changes the value of K?
- Temperature.
- Does adding more reactant change K?
- No: the position shifts to restore the same value of K.
- What happens to K for an exothermic reaction when temperature rises?
- K decreases and the equilibrium moves towards the reactants.
- What happens to K for an endothermic reaction when temperature rises?
- K increases and the equilibrium moves towards the products.
- Write the relationship between ΔStotal and K.
- ΔStotal = R ln K, with R = 8.31 J K⁻¹ mol⁻¹.
- Why does K fall for an exothermic reaction as T rises?
- ΔSsurroundings = −ΔH/T becomes smaller, so ΔStotal falls and so does K.
- What does a very large K (e.g. 10⁶) show?
- The reaction goes almost to completion, with mainly products.
- What does a very small K (e.g. 10⁻⁶) show?
- Hardly any reaction occurs, with mainly reactants.
- What is the effect of pressure on a system with equal moles of gas on each side?
- No effect on composition.
- Why are compromise conditions used in industry?
- Low temperature favours the yield of an exothermic reaction but gives a slow rate; high pressure costs more.
- A heterogeneous equilibrium has a pure solid added. What happens to the position?
- Nothing, as a pure solid is not in the K expression.
Exam questions on Factors affecting equilibrium and K
- Ammonia is manufactured by the Haber process: N₂(g) + 3H₂(g) ⇌ 2NH₃(g), ΔH = −92 kJ mol⁻¹. The reaction is carried out at about 450 °C and 200 atm using an iron catalyst.Explain why using the iron catalyst does not change the equilibrium yield of ammonia.2 marks
- Limestone is heated in a sealed kiln in which this equilibrium is established: CaCO₃(s) ⇌ CaO(s) + CO₂(g), ΔH = +178 kJ mol⁻¹. For this equilibrium Kp = p(CO₂).The volume of the sealed kiln is halved at constant temperature. Explain why the equilibrium pressure of carbon dioxide returns to its original value.2 marks
- The Contact process makes sulfur trioxide: 2SO₂(g) + O₂(g) ⇌ 2SO₃(g), ΔH = −196 kJ mol⁻¹. The entropy change of the system is −188 J K⁻¹ mol⁻¹, and both this and ΔH may be assumed constant with temperature. Use R = 8.31 J K⁻¹ mol⁻¹.Calculate ΔStotal at 700 K and hence the value of K at 700 K.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).