Current, Potential Difference and ResistanceAQA GCSE Physics: Revision notes
Section 1
What is electric current and how is it calculated?
Electric current is the rate of flow of electric charge through a circuit. It is measured in amperes (A).
Current is defined by the equation:
Q = It
Where:
- Q = charge in coulombs (C)
- I = current in amperes (A)
- t = time in seconds (s)
This equation tells us that the total charge flowing depends on how much current flows and for how long it flows.
Rearranging the equation:
- To find current: I = Q/t
- To find time: t = Q/I
In a circuit, current is the flow of electrons through a conductor. The larger the current, the more charge passes through a point per second.
A current of 2 A flows for 5 seconds. Calculate the total charge transferred. Using Q = It: Q = 2 × 5 = 10 C. Always check your units and substitute values carefully.
Examiners expect you to show the equation, substitute values with units, and state the final answer with correct units. Do not just give a number.
Section 2
What is potential difference and how does it relate to energy?
Potential difference (p.d.) is the energy transferred per unit charge in a circuit. It is measured in volts (V).
Potential difference is defined by the equation:
V = W/Q
Where:
- V = potential difference in volts (V)
- W = energy transferred in joules (J)
- Q = charge in coulombs (C)
This equation shows that potential difference tells us how much energy is given to (or taken from) each coulomb of charge.
Rearranging the equation:
- To find energy: W = VQ
- To find charge: Q = W/V
Key point: A potential difference of 1 volt means 1 joule of energy is transferred for every coulomb of charge that flows.
Potential difference across a component is often called the voltage across that component.
Think of potential difference like water pressure in a pipe. Higher potential difference (like higher pressure) pushes more energy into the charge, making it do more work—just as higher pressure pushes water faster through a pipe.
A charge of 5 C flows through a potential difference of 12 V. Calculate the energy transferred. Using W = VQ: W = 12 × 5 = 60 J. The potential difference does 60 joules of work on the charge.
Section 3
What is resistance and Ohm's Law?
Resistance is a measure of how much a material opposes the flow of electric current through it. It is measured in ohms (Ω).
The relationship between potential difference, current, and resistance is given by Ohm's Law:
V = IR
Where:
- V = potential difference in volts (V)
- I = current in amperes (A)
- R = resistance in ohms (Ω)
Rearranging the equation:
- To find current: I = V/R
- To find resistance: R = V/I
Key points:
- For a given potential difference, higher resistance means lower current
- For a given current, higher resistance means higher potential difference
- A resistance of 1 ohm means 1 volt produces a current of 1 ampere
Ohmic conductors (like resistors at constant temperature) follow Ohm's Law—the potential difference is directly proportional to the current.
Students often confuse which variable to rearrange for. Remember: V = IR is the standard form. If you need I, divide both sides by R. If you need R, divide both sides by I. Always write the rearrangement step.
A resistor has a resistance of 10 Ω and a current of 0.5 A flows through it. Calculate the potential difference. Using V = IR: V = 0.5 × 10 = 5 V. The resistor has a potential difference of 5 V across it.
Section 4
How does resistance vary with temperature in metals?
At constant temperature, the resistance of a metal conductor remains constant (for an ohmic conductor).
As temperature increases, the resistance of a metal increases.
Explanation in terms of ion vibration (Higher Tier):
- At higher temperatures, the metal ions vibrate more vigorously about their fixed lattice positions
- Free electrons in the metal move through the lattice between these ions
- As ion vibration increases, electrons collide more frequently with the vibrating ions
- Each collision reduces the electron's momentum, slowing down the flow of charge
- More collisions = more opposition to current flow = higher resistance
In summary:
- High temperature → vigorous ion vibration → more frequent electron-ion collisions → higher resistance
- Low temperature → less ion vibration → fewer electron-ion collisions → lower resistance
This is why metal resistors are often temperature-dependent, and why calculations assume constant temperature unless otherwise stated.
For Higher Tier, examiners expect you to explain resistance change using the molecular model: mention ion vibration, electron collisions, and how this reduces electron flow. Do not just say 'resistance increases with temperature'—explain why in terms of particle behaviour.
Imagine free electrons trying to walk through a crowded room. At low temperature (few people), they move easily (low resistance). At high temperature (crowded room with people moving about), they bump into people constantly (more collisions) and struggle to progress (high resistance).
Section 5
How do you solve problems involving current, potential difference, and resistance?
Strategy for multi-step problems:
- Identify what you know – list all given values with their units (V, I, R, Q, t, W)
- Identify what you need to find – the unknown value required by the question
- Choose the correct equation – use one of these:
- Q = It (for charge and current relationships)
- V = W/Q (for potential difference and energy)
- V = IR (for resistance problems)
- Rearrange if necessary – solve for the unknown variable
- Substitute values – include units at each step
- Calculate and state the answer – with correct units
Common equation combinations:
| Problem type | Equations to use |
|---|---|
| Current and time to find charge | Q = It |
| Potential difference and charge to find energy | W = VQ |
| Potential difference and current to find resistance | R = V/I |
| Temperature effect on current | Use V = IR; explain ion vibration (HT) |
| Multi-stage: energy, charge, current involved | Combine Q = It with V = W/Q and/or V = IR |
Always show working – examiners award marks for method, not just the final answer.
A 4 Ω resistor has a potential difference of 12 V across it. (a) Calculate the current: I = V/R = 12/4 = 3 A. (b) If this current flows for 20 seconds, calculate the total charge: Q = It = 3 × 20 = 60 C. Always work through each part separately and use your answer from part (a) in part (b).
Must Know
- Electric current is the rate of flow of charge: Q = It (where Q is in coulombs, I in amperes, t in seconds)
- Potential difference is energy transferred per unit charge: V = W/Q (where W is in joules, Q in coulombs, V in volts)
- Ohm's Law relates potential difference, current, and resistance: V = IR (where R is in ohms)
- Resistance increases with temperature in metals because higher ion vibration causes more frequent collisions between free electrons and ions, reducing current flow
- In all calculations: show the equation, rearrange if needed, substitute values with units, and state the final answer with correct units
- Key units: charge (coulombs, C), current (amperes, A), time (seconds, s), energy (joules, J), potential difference (volts, V), resistance (ohms, Ω)
That's the notes covered.
Carry on to the next subtopic.