Transferring Electrical EnergyOxford AQA IGCSE Physics: Revision notes
Section 1
How do electrical appliances transfer energy?
Electrical appliances are designed to transfer energy from the electrical supply to other, useful forms.
- A kettle transfers electrical energy to thermal energy (heating the water)
- A lamp transfers electrical energy to light energy (and some wasted thermal energy)
- A motor transfers electrical energy to kinetic energy
- A loudspeaker transfers electrical energy to sound energy
Every appliance is chosen and designed for the specific energy transfer it needs to make.
A hairdryer transfers electrical energy into thermal energy (heating element) and kinetic energy (fan motor).
Section 2
How is electrical power calculated?
Power is the rate at which energy is transferred, and can be calculated in two ways:
P = E ÷ t
where P is power (W), E is energy transferred (J), and t is time (s).
P = I × V
where I is current (A) and V is potential difference (V). This second equation is useful for determining the correct size of fuse needed for an appliance — the fuse rating must be just above the normal operating current.
When asked to determine fuse size, calculate the current using I = P/V, then select the next fuse rating above that value (e.g. 3A, 5A, 13A).
Section 3
How is energy transferred by a charge calculated?
Energy transferred can also be calculated from potential difference and charge:
E = V × Q
where E is energy transferred (J), V is potential difference (V), and Q is charge (C). This equation reflects the definition of potential difference as the energy transferred per unit charge.
A charge of 5 C flows through a 12 V component: energy transferred = 12 × 5 = 60 J.
Section 4
How is mains electricity usage measured and costed?
Energy used by mains electricity is measured in kilowatt-hours (kWh) rather than joules, since household energy use involves very large numbers of joules.
E (kWh) = P (kW) × t (h)
To find the cost of electricity used, multiply the energy used (in kWh) by the cost per kilowatt-hour charged by the electricity supplier.
cost = energy used (kWh) × cost per kWh
A 2 kW heater used for 3 hours transfers 2 × 3 = 6 kWh. At 20p per kWh, this costs 6 × 20 = 120p = £1.20.
Must Know
- Electrical appliances are designed to transfer electrical energy to useful forms (thermal, kinetic, light, sound)
- Power equations: P = E ÷ t and P = I × V
- P = I × V can be used to determine the correct fuse rating for an appliance
- Energy transferred: E = V × Q
- Mains energy use is measured in kilowatt-hours: E (kWh) = P (kW) × t (h)
- Cost of electricity = energy used (kWh) × cost per kWh
That's the notes covered.
Carry on to the next subtopic.