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Transferring Electrical EnergyOxford AQA IGCSE Physics: Revision notes

Section 1

How do electrical appliances transfer energy?

Electrical appliances are designed to transfer energy from the electrical supply to other, useful forms.

  • A kettle transfers electrical energy to thermal energy (heating the water)
  • A lamp transfers electrical energy to light energy (and some wasted thermal energy)
  • A motor transfers electrical energy to kinetic energy
  • A loudspeaker transfers electrical energy to sound energy

Every appliance is chosen and designed for the specific energy transfer it needs to make.

Example

A hairdryer transfers electrical energy into thermal energy (heating element) and kinetic energy (fan motor).

Section 2

How is electrical power calculated?

Power is the rate at which energy is transferred, and can be calculated in two ways:

P = E ÷ t

where P is power (W), E is energy transferred (J), and t is time (s).

P = I × V

where I is current (A) and V is potential difference (V). This second equation is useful for determining the correct size of fuse needed for an appliance — the fuse rating must be just above the normal operating current.

Key termspower
Exam tip

When asked to determine fuse size, calculate the current using I = P/V, then select the next fuse rating above that value (e.g. 3A, 5A, 13A).

Section 3

How is energy transferred by a charge calculated?

Energy transferred can also be calculated from potential difference and charge:

E = V × Q

where E is energy transferred (J), V is potential difference (V), and Q is charge (C). This equation reflects the definition of potential difference as the energy transferred per unit charge.

Example

A charge of 5 C flows through a 12 V component: energy transferred = 12 × 5 = 60 J.

Section 4

How is mains electricity usage measured and costed?

Energy used by mains electricity is measured in kilowatt-hours (kWh) rather than joules, since household energy use involves very large numbers of joules.

E (kWh) = P (kW) × t (h)

To find the cost of electricity used, multiply the energy used (in kWh) by the cost per kilowatt-hour charged by the electricity supplier.

cost = energy used (kWh) × cost per kWh

Key termskilowatt-hour
Example

A 2 kW heater used for 3 hours transfers 2 × 3 = 6 kWh. At 20p per kWh, this costs 6 × 20 = 120p = £1.20.

Must Know

  • Electrical appliances are designed to transfer electrical energy to useful forms (thermal, kinetic, light, sound)
  • Power equations: P = E ÷ t and P = I × V
  • P = I × V can be used to determine the correct fuse rating for an appliance
  • Energy transferred: E = V × Q
  • Mains energy use is measured in kilowatt-hours: E (kWh) = P (kW) × t (h)
  • Cost of electricity = energy used (kWh) × cost per kWh

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