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Dihybrid inheritance, multiple alleles and sex linkageAQA A-Level Biology: Subtopic test

10 questions, 27 marks

AQA A-Level Biology

Dihybrid inheritance, multiple alleles and sex linkage

Total 27 marks

Name

Class

Date

  1. 1
    In a species of garden pea, round seeds are produced by the dominant allele RR and wrinkled seeds by the recessive allele rr. Yellow seeds are produced by the dominant allele YY and green seeds by the recessive allele yy. The two genes are on different chromosomes. A plant breeder crosses plants that are heterozygous for both genes (RrYyRrYy).
    (a)
    How many genetically different types of gamete can a plant with the genotype RrYyRrYy produce?
    [1 mark]
    • A2
    • B4
    • C8
    • D16
    (b)
    Two RrYyRrYy plants are crossed. What phenotypic ratio of round yellow : round green : wrinkled yellow : wrinkled green is expected in the offspring?
    [1 mark]
    • A9 : 3 : 3 : 1
    • B1 : 1 : 1 : 1
    • C3 : 1 : 3 : 1
    • D1 : 2 : 1 : 2
    (c)
    An RrYyRrYy plant is crossed with a plant that has wrinkled green seeds. State the expected phenotypic ratio in the offspring and explain how it arises.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The ABO blood group in humans is controlled by one gene, II, with three alleles. The alleles IAI^A and IBI^B are codominant, and the allele IOI^O is recessive to both. A woman with blood group A (genotype IAIOI^AI^O) and a man with blood group B (genotype IBIOI^BI^O) have children. In a separate paternity enquiry, a woman of blood group A has a child of blood group O.
    (a)
    Which genotype gives blood group AB?
    [1 mark]
    • AIAIAI^AI^A
    • BIAIOI^AI^O
    • CIBIOI^BI^O
    • DIAIBI^AI^B
    (b)
    Which phenotypes could the children of the woman of group A and the man of group B have?
    [1 mark]
    • AGroup A and group B only
    • BGroup AB only
    • CGroups A, B, AB and O
    • DGroups A, B and O only
    (c)
    A man with blood group AB is named as the father of the child of blood group O. Explain why he cannot be the father.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Haemophilia A is a blood-clotting disorder caused by a recessive allele, hh, on the X chromosome. The dominant allele, HH, codes for a working clotting factor. There is no corresponding gene on the Y chromosome. A woman who is a carrier and a man with normal clotting plan to have children.
    (a)
    Explain why haemophilia is much more common in males than in females.
    [3 marks]
    (b)
    Complete a fully labelled genetic diagram for this cross. State the probability that a child of this couple is a boy with haemophilia.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Fruit flies (Drosophila) are used to study inheritance. Body colour is controlled by a gene with alleles GG (grey, dominant) and gg (ebony). Wing length is controlled by a gene with alleles NN (normal, dominant) and nn (vestigial). These genes are on different autosomes. Eye colour is controlled by a gene on the X chromosome, with alleles XRX^R (red, dominant) and XrX^r (white).
    (a)
    Two flies heterozygous for body colour and wing length (GgNnGgNn) are crossed. Use a fully labelled genetic diagram to show the expected phenotypic ratio, and calculate the number of flies expected in each phenotypic class among 640 offspring.
    [6 marks]
    (b)
    A white-eyed female is crossed with a red-eyed male. Their offspring (F1) are interbred to give an F2. Using genetic diagrams, explain the phenotypes of the F1 and the expected phenotypes in the F2.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).