Dihybrid inheritance, multiple alleles and sex linkageAQA A-Level Biology: Subtopic test
10 questions, 27 marks
AQA A-Level Biology
Dihybrid inheritance, multiple alleles and sex linkage
Total 27 marks
Name
Class
Date
- 1In a species of garden pea, round seeds are produced by the dominant allele and wrinkled seeds by the recessive allele . Yellow seeds are produced by the dominant allele and green seeds by the recessive allele . The two genes are on different chromosomes. A plant breeder crosses plants that are heterozygous for both genes ().(a)How many genetically different types of gamete can a plant with the genotype produce?[1 mark]
- A2
- B4
- C8
- D16
(b)Two plants are crossed. What phenotypic ratio of round yellow : round green : wrinkled yellow : wrinkled green is expected in the offspring?[1 mark]- A9 : 3 : 3 : 1
- B1 : 1 : 1 : 1
- C3 : 1 : 3 : 1
- D1 : 2 : 1 : 2
(c)An plant is crossed with a plant that has wrinkled green seeds. State the expected phenotypic ratio in the offspring and explain how it arises.[2 marks]Total for question 1: 4 marks
- 2The ABO blood group in humans is controlled by one gene, , with three alleles. The alleles and are codominant, and the allele is recessive to both. A woman with blood group A (genotype ) and a man with blood group B (genotype ) have children. In a separate paternity enquiry, a woman of blood group A has a child of blood group O.(a)Which genotype gives blood group AB?[1 mark]
- A
- B
- C
- D
(b)Which phenotypes could the children of the woman of group A and the man of group B have?[1 mark]- AGroup A and group B only
- BGroup AB only
- CGroups A, B, AB and O
- DGroups A, B and O only
(c)A man with blood group AB is named as the father of the child of blood group O. Explain why he cannot be the father.[2 marks]Total for question 2: 4 marks
- 3Haemophilia A is a blood-clotting disorder caused by a recessive allele, , on the X chromosome. The dominant allele, , codes for a working clotting factor. There is no corresponding gene on the Y chromosome. A woman who is a carrier and a man with normal clotting plan to have children.(a)Explain why haemophilia is much more common in males than in females.[3 marks](b)Complete a fully labelled genetic diagram for this cross. State the probability that a child of this couple is a boy with haemophilia.[4 marks]
Total for question 3: 7 marks
- 4Fruit flies (Drosophila) are used to study inheritance. Body colour is controlled by a gene with alleles (grey, dominant) and (ebony). Wing length is controlled by a gene with alleles (normal, dominant) and (vestigial). These genes are on different autosomes. Eye colour is controlled by a gene on the X chromosome, with alleles (red, dominant) and (white).(a)Two flies heterozygous for body colour and wing length () are crossed. Use a fully labelled genetic diagram to show the expected phenotypic ratio, and calculate the number of flies expected in each phenotypic class among 640 offspring.[6 marks](b)A white-eyed female is crossed with a red-eyed male. Their offspring (F1) are interbred to give an F2. Using genetic diagrams, explain the phenotypes of the F1 and the expected phenotypes in the F2.[6 marks]
Total for question 4: 12 marks
End of questions
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).