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Bronsted-Lowry acids and bases and pHEdexcel A-Level Chemistry: Revision notes

Section 1

Brønsted–Lowry acids and bases

A Brønsted–Lowry acid is a proton donor. A Brønsted–Lowry base is a proton acceptor. A proton is an H⁺ ion.

An acid–base reaction involves the transfer of a proton from the acid to the base. In an aqueous solution of an acid, water acts as the base:

HCl(aq) + H₂O(l) → H₃O⁺(aq) + Cl⁻(aq)

In this reaction HCl is the acid (it donates H⁺) and H₂O is the base (it accepts H⁺). H₃O⁺ is usually written as H⁺(aq).

Key termsBrønsted–Lowry acidBrønsted–Lowry baseproton transfer

Section 2

Conjugate acid–base pairs

When an acid donates a proton, what remains is its conjugate base. When a base accepts a proton, it becomes its conjugate acid. The two species in a pair differ by one H⁺.

CH₃COOH(aq) + NH₃(aq) ⇌ CH₃COO⁻(aq) + NH₄⁺(aq)

  • Pair 1: CH₃COOH (acid) and CH₃COO⁻ (base)
  • Pair 2: NH₄⁺ (acid) and NH₃ (base)

Every acid–base equilibrium contains two conjugate pairs. To identify them, find the species that has lost H⁺ and the one that has gained it.

Key termsconjugate acidconjugate base
Common mistake

Pair each acid with the base that differs from it by one H⁺, not with the other species on the same side of the equation.

Section 3

pH and hydrogen ion concentration

pH is a measure of acidity defined by

pH = −log₁₀[H⁺]

where [H⁺] is the hydrogen ion concentration in mol dm⁻³. Rearranging gives [H⁺] = 10−pH10^{-\mathrm{pH}}.

  • pH of 0.0100 mol dm⁻³ H⁺: −log₁₀(0.0100) = 2.00
  • [H⁺] for pH 3.40: 10−3.4010^{-3.40} = 4.0 × 10⁻⁴ mol dm⁻³

Each pH unit is a tenfold change in [H⁺]. A lower pH means a higher [H⁺]. Give pH to 2 decimal places.

Key termspHhydrogen ion concentration
Exam tip

Use the log and 10ˣ buttons on your calculator, and check that the answer is sensible: a more concentrated acid has a lower pH.

Section 4

Strong and weak acids

A strong acid is fully dissociated in aqueous solution. A weak acid is partially dissociated, so an equilibrium is set up.

  • Strong: HCl(aq) → H⁺(aq) + Cl⁻(aq)
  • Weak: CH₃COOH(aq) ⇌ H⁺(aq) + CH₃COO⁻(aq)

The degree of dissociation is the fraction of acid molecules that have dissociated. Strong and weak describe the degree of dissociation, not concentration.

For a strong monoprotic acid, [H⁺] equals the acid concentration, so pH = −log₁₀(concentration). For 0.0500 mol dm⁻³ HNO₃: pH = −log₁₀(0.0500) = 1.30.

Key termsstrong acidweak aciddegree of dissociation
Common mistake

Strong is not the same as concentrated. A dilute solution of a strong acid is still a strong acid.

Section 5

Analysing pH data

Equimolar acids (0.100 mol dm⁻³): HCl pH 1.00 gives [H⁺] = 0.100 (fully dissociated, strong); ethanoic acid pH 2.88 gives [H⁺] ≈ 1.3 × 10⁻³ (about 1% dissociated, weak).

Equimolar bases: NaOH (pH 13.00) is higher than NH₃ (pH 11.12), so ammonia produces fewer OH⁻ ions: a weak base.

Salts: NaCl, from a strong acid and a strong base, is neutral (pH 7). NH₄Cl, from a strong acid and a weak base, is acidic. CH₃COONa, from a weak acid and a strong base, is alkaline.

Dilution: diluting a solution by 10, 100 and 1000 times raises the pH of a strong acid by exactly 1, 2 and 3 units, because [H⁺] falls in proportion. A weak acid pH rises by less than this, because the equilibrium shifts right and a greater proportion of the acid dissociates.

Key termsequimolardilution
Exam tip

When analysing data, convert each pH to [H⁺] and compare it with the acid concentration.

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Exam questions on Bronsted-Lowry acids and bases and pH

  1. A student mixes aqueous ethanoic acid with aqueous ammonia: CH₃COOH(aq) + NH₃(aq) ⇌ CH₃COO⁻(aq) + NH₄⁺(aq).
    Identify the two conjugate acid–base pairs in this equilibrium, stating which species in each pair is the acid and which is the base.2 marks
  2. A school technician prepares solutions of strong monoprotic acids for a practical. All measurements are made at 298 K.
    The technician dilutes 25.0 cm³ of 0.200 mol dm⁻³ hydrochloric acid to a final volume of 500 cm³. Calculate the pH of the diluted solution.2 marks
  3. A student has equimolar 0.100 mol dm⁻³ solutions of nitric acid, a strong acid, and methanoic acid, a weak acid. At 298 K the pH of the nitric acid is 1.00 and the pH of the methanoic acid is 2.38.
    Use the pH values to show that nitric acid is a strong acid and methanoic acid is a weak acid.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).