Isomerism: structural and E/ZEdexcel A-Level Chemistry: Revision notes
Section 1
Structural isomerism
Structural isomers have the same molecular formula but different structural formulae, because their atoms are bonded together in a different order. They often differ in physical properties and sometimes in chemical properties.
There are three types you must know: chain, position and functional group isomerism. To find all the isomers of a formula, work systematically: first the longest chain, then shorter main chains with one branch placed in every different position, then two branches.
Section 2
Chain, position and functional group isomers
- Chain isomers have different carbon skeletons (straight or branched), e.g. butane and 2-methylpropane; but-1-ene and 2-methylpropene.
- Position isomers have the same carbon skeleton and the same functional group, but the group is in a different position, e.g. propan-1-ol and propan-2-ol; 1-bromobutane and 2-bromobutane.
- Functional group isomers have different functional groups, e.g. but-1-ene (alkene) and cyclobutane (cycloalkane); propan-1-ol (alcohol) and methoxyethane (ether).
Two molecules that look different when drawn may be the same compound: rotating about single bonds changes nothing, so check by naming each.
Counting the same molecule twice. Bending a chain on paper does not make a new isomer; name each structure to be sure.
Section 3
Worked examples: counting isomers
C₅H₁₂ (3 isomers): pentane; 2-methylbutane; 2,2-dimethylpropane. (3-methylbutane is 2-methylbutane numbered the wrong way.)
C₄H₉Br (4 isomers): 1-bromobutane; 2-bromobutane; 1-bromo-2-methylpropane; 2-bromo-2-methylpropane.
C₅H₁₀ alkenes (6 including E/Z): pent-1-ene; (E)-pent-2-ene; (Z)-pent-2-ene; 2-methylbut-1-ene; 3-methylbut-1-ene; 2-methylbut-2-ene.
Section 4
Stereoisomerism and E/Z isomerism
Stereoisomers have the same structural formula but a different arrangement of atoms in space. E/Z isomerism is a type of stereoisomerism that occurs in alkenes.
The C=C double bond contains a π bond, which prevents rotation, so groups attached to the carbon atoms are fixed on one side or the other of the bond.
A molecule shows E/Z isomerism only if each carbon atom of the C=C is bonded to two different atoms or groups.
- But-2-ene, CH₃CH=CHCH₃: yes (H and CH₃ on each carbon).
- But-1-ene, CH₂=CHCH₂CH₃: no (two H on one carbon).
- 2-methylpropene, (CH₃)₂C=CH₂: no.
Saying the double bond is 'strong' as the reason for E/Z isomerism. The reason is that it cannot rotate.
Section 5
Labelling E and Z; cis-trans
On each carbon of the C=C, decide which attached group has the higher priority: the group whose first atom has the higher atomic number (Cahn–Ingold–Prelog rules). If the first atoms are the same, compare the next atoms along.
- Z (from German zusammen, together): the two higher-priority groups are on the same side.
- E (from entgegen, opposite): the two higher-priority groups are on opposite sides.
For example, in CH₃CH=CHCH₂CH₃ the methyl group and the ethyl group are the higher-priority groups (CH₃ beats H; CH₂CH₃ beats H); when they are on the same side the isomer is (Z)-pent-2-ene.
Where two substituents on the double bond are the same, as in but-2-ene (a CH₃ and H on each carbon), the older terms cis (same groups on the same side) and trans (opposite sides) are also used: cis is Z and trans is E.
Z = 'zame zide'. If the high-priority groups are together it is Z.
Must know
- Structural isomers: same molecular formula, different structural formulae (chain, position, functional group).
- E/Z isomerism needs restricted rotation about C=C and two different groups on each carbon of it.
- Z: higher-priority groups on the same side; E: opposite sides.
- C₅H₁₂ has 3 isomers; C₄H₉Br has 4; C₄H₈ has four alkene isomers.
That's the notes covered.
Carry on to the next subtopic.
Exam questions on Isomerism: structural and E/Z
- A chemist is cataloguing the isomers of the alkane C₅H₁₂ and of the haloalkane C₄H₉Br.Give the IUPAC names of the two branched isomers of C₅H₁₂.2 marks
- A student is studying alkenes with the molecular formulae C₄H₈ and C₅H₁₀, and how the arrangement of groups around the carbon-carbon double bond affects their properties.Explain what causes E/Z isomerism and state the condition on the groups attached to the C=C bond for a molecule to show it.2 marks
- Alkenes with the molecular formula C₅H₁₀ are used as models to study isomerism. Ignore cyclic compounds in this question.Give the structural formula and name of each unbranched alkene with molecular formula C₅H₁₀. State which one shows E/Z isomerism, with a reason.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).