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Chirality and optical isomerismEdexcel A-Level Chemistry: Revision notes

Section 1

Chiral centres and optical isomers

A chiral centre (asymmetric carbon atom) is a carbon atom bonded to four different atoms or groups. A molecule with a single chiral centre exists as two forms called optical isomers, or enantiomers. This type of stereoisomerism is optical isomerism.

Examples: butan-2-ol, CH₃CH(OH)CH₂CH₃, has a chiral carbon (H, OH, CH₃, C₂H₅); lactic acid, CH₃CH(OH)COOH, has a chiral carbon (H, OH, CH₃, COOH). Propan-2-ol is not chiral because its central carbon has two identical CH₃ groups.

Key termschiral centreoptical isomerismenantiomers
Common mistake

Say 'four different groups', not 'four different atoms': the groups attached may be a mixture, such as H, OH, CH₃ and C₂H₅.

Section 2

Non-superimposable mirror images

The two enantiomers of a chiral molecule are non-superimposable mirror images, like left and right hands. They cannot be rotated to look identical.

On a diagram, show the chiral carbon with two bonds in the plane of the paper, one wedge (towards the viewer) and one hashed bond (away), then draw the mirror image across a vertical line.

Enantiomers have the same boiling point, density and chemical reactions with non-chiral reagents. They differ in how they rotate plane-polarised light, and in their reactions with other chiral molecules, such as enzymes in the body.

Key termsnon-superimposable
Exam tip

When drawing enantiomers, draw the mirror line, and check that the two drawings cannot be matched by rotating one of them.

Section 3

Optical activity

Plane-polarised light vibrates in a single plane. When it passes through a solution of a single enantiomer, the plane is rotated. This property is optical activity.

Optical activity is the ability of a single optical isomer to rotate the plane of plane-polarised monochromatic light (light of a single wavelength). It is measured with a polarimeter.

  • One enantiomer rotates the plane clockwise (+), and the other rotates it anticlockwise (−).
  • The two enantiomers rotate the plane by equal angles in opposite directions.
  • The size of rotation depends on concentration, path length, temperature and wavelength.
Key termsplane-polarised lightoptical activitypolarimeter

Section 4

Racemic mixtures

A racemic mixture (racemate) contains equal amounts of the two enantiomers. The rotations are equal and opposite, so they cancel and the mixture is not optically active (net rotation 0°).

If the amounts are unequal, the mixture is optically active, and the net rotation is proportional to the excess of one enantiomer. For example, a solution with 75% (+) and 25% (−) of an isomer that gives +6.0° when pure has rotation 0.75 × 6.0 − 0.25 × 6.0 = +3.0°.

A racemic mixture forms when a reaction creates a chiral centre from a planar reactant or intermediate, because attack from either side is equally likely.

Key termsracemic mixture
Common mistake

A racemic mixture is optically inactive even though every molecule in it is chiral. The rotations cancel.

Section 5

Optical activity as evidence for SN1 and SN2

Optical activity of the reactant and product shows how a halogenoalkane reacts with a nucleophile such as OH⁻.

  • SN1 (tertiary halogenoalkane, rate = k[RX]): the slow step forms a planar carbocation. The nucleophile attacks it from either side with equal probability, so a racemic mixture forms. A single optically active enantiomer therefore gives a product that is optically inactive.
  • SN2 (primary or secondary, rate = k[RX][Nu⁻]): the nucleophile attacks from the side opposite the leaving group in one step, so the configuration is inverted. A single optically active enantiomer therefore gives a single enantiomer of the product, which is optically active.

Combine this with the rate equation for the strongest evidence.

Key termsSN1SN2carbocation
Exam tip

Name the intermediate (planar carbocation) and say 'attack from either side equally likely, so racemic mixture' to earn the SN1 marks.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Chirality and optical isomerism

  1. A student examines four alcohols: propan-2-ol, butan-2-ol, 2-methylpropan-2-ol and pentan-3-ol. Only one of them exists as a pair of optical isomers.
    Explain why butan-2-ol shows optical isomerism.2 marks
  2. A polarimeter measures the rotation of plane-polarised monochromatic light by solutions of 2-chlorobutane. Sample P is a pure single enantiomer and rotates the plane of polarised light by +20°. Sample Q is the other enantiomer of 2-chlorobutane. Sample R is made by mixing equal amounts of P and Q, with all solutions at the same total concentration.
    Explain why Sample R shows no optical activity.2 marks
  3. Lactic acid, CH₃CH(OH)COOH, exists as two optical isomers. In a polarimeter, a solution of one pure enantiomer of lactic acid at a concentration of 0.10 mol dm⁻³ rotates plane-polarised monochromatic light by +6.0°. The other enantiomer rotates it by the same angle in the opposite direction. A student prepares a second solution, also with total concentration 0.10 mol dm⁻³, containing 75% of the (+) enantiomer and 25% of the (−) enantiomer by amount.
    Identify the chiral centre in lactic acid and explain why this molecule has two enantiomers. State how the two enantiomers differ in their effect on plane-polarised light.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).