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Organic synthesis and reaction pathwaysEdexcel A-Level Chemistry: Revision notes

Section 1

Deducing formulae from data

Combustion analysis: burn a known mass of compound; CO₂ gives the carbon and H₂O gives the hydrogen; oxygen is found by difference.

Worked example: 0.230 g of a compound of C, H and O gives 0.440 g CO₂ and 0.270 g H₂O.

  • n(C) = 0.440 ÷ 44.0 = 0.0100 mol (0.120 g)
  • n(H) = 2 × 0.270 ÷ 18.0 = 0.0300 mol (0.030 g)
  • mass of O = 0.230 − 0.150 = 0.080 g, n(O) = 0.00500 mol
  • ratio C : H : O = 2 : 6 : 1, so the empirical formula is C₂H₆O

The molecular formula is a whole-number multiple of the empirical formula; it is found from the molecular ion peak (m/z 46 gives C₂H₆O). The same approach works from elemental percentage composition (divide each % by Aᵣ).

Key termsempirical formulamolecular formula

Section 2

Using reactions and spectra to find structure

Characteristic reactions: alkene – bromine water decolourised; carboxylic acid – effervescence with sodium carbonate/hydrogencarbonate; carbonyl – orange precipitate with 2,4-dinitrophenylhydrazine; aldehyde – silver mirror (Tollens') or brick-red precipitate (Fehling's); primary/secondary alcohol or aldehyde – orange to green with acidified dichromate(VI); halogenoalkane – warm with NaOH, acidify with HNO₃, add AgNO₃.

Mass spectrum: the molecular ion peak gives Mᵣ; fragments suggest groups.

Infrared: O–H (alcohol) about 3230–3550 cm⁻¹, O–H (acid) 2500–3300 cm⁻¹ (very broad), C=O 1680–1750 cm⁻¹, N–H 3300–3500 cm⁻¹.

¹H NMR: the number of peaks shows the number of proton environments; the area ratio gives the number of H in each; splitting follows the n + 1 rule.

Key termsmolecular ionproton environment
Exam tip

State what each piece of data shows, then combine them: formula first, then functional groups, then the carbon skeleton from NMR.

Section 3

Planning reaction schemes

Work backwards from the target and choose reactions that you know. Useful steps:

  • alkene + HBr → bromoalkane; alkane + Br₂ (UV) → bromoalkane
  • bromoalkane + NaOH(aq), heat → alcohol; + KCN in ethanol, reflux → nitrile (one carbon longer); + excess NH₃ in ethanol → amine
  • nitrile + dilute acid, reflux → carboxylic acid; nitrile + LiAlH₄ in dry ether → amine
  • primary alcohol + acidified dichromate(VI) → aldehyde (distil) or carboxylic acid (reflux); secondary alcohol → ketone
  • alcohol + concentrated H₃PO₄ or H₂SO₄ → alkene
  • benzene + HNO₃/H₂SO₄ → nitrobenzene; nitrobenzene + Sn/HCl → phenylamine

For each step give reagents, conditions and the type of reaction. Count carbon atoms: only cyanide or a Grignard reagent adds carbon atoms to the chain.

Key termsreaction scheme

Section 4

Lengthening the carbon chain: Grignard reagents

A bromoalkane reacts with magnesium turnings in dry ether to form a Grignard reagent:

CH₃CH₂Br + Mg → CH₃CH₂MgBr

The carbon bonded to magnesium is δ–, so the reagent is a strong nucleophile and a strong base. It reacts violently with water, forming an alkane, so everything must be anhydrous.

  • With CO₂ (solid), then dilute acid: a carboxylic acid with one more carbon, e.g. CH₃CH₂COOH.
  • With methanal, then dilute acid: a primary alcohol.
  • With another aldehyde: a secondary alcohol, e.g. CH₃CH₂MgBr + CH₃CHO gives butan-2-ol.
  • With a ketone: a tertiary alcohol, e.g. CH₃CH₂MgBr + propanone gives 2-methylbutan-2-ol.

The nucleophilic carbon attacks the δ+ carbonyl carbon; the acid then protonates the intermediate.

Key termsGrignard reagentanhydrous
Common mistake

The Grignard reagent is a nucleophile through its carbon atom. Do not use aqueous or protic solvents, or the reagent is destroyed.

Section 5

Practical techniques

  • Reflux: heating with a condenser upright so volatile liquids return to the flask and the reaction can run for a long time.
  • Distillation: separates liquids with different boiling temperatures; collect the fraction at the boiling temperature of the product.
  • Steam distillation: separates a volatile, water-immiscible compound (e.g. phenylamine) from a mixture at below 100 °C, so it does not decompose.
  • Solvent extraction: shake with an immiscible solvent in a separating funnel; the organic layer is separated.
  • Washing: with sodium hydrogencarbonate solution to remove acidic impurities, then water.
  • Drying: an anhydrous salt such as sodium sulfate or magnesium sulfate removes water from a liquid.
  • Recrystallisation: dissolve in the minimum hot solvent, cool slowly, filter under reduced pressure, wash, dry.
  • Purity: a pure solid has a sharp melting temperature matching data; a pure liquid has a sharp boiling temperature.
Key termsrefluxrecrystallisationsteam distillation

Section 6

Choosing procedures and controlling risk

A hazard is the potential to cause harm; risk is the chance of harm given how the hazard is used. Use hazard data to select a procedure and to justify control measures.

  • Toxic reagents (e.g. cyanide): fume cupboard, gloves, keep away from acid.
  • Flammable solvents (e.g. ether): water bath or electric heater, no naked flames, small quantities.
  • Corrosive acids: goggles and gloves, add slowly with cooling.
  • Water-reactive reagents (Grignard reagents, LiAlH₄): dry apparatus and solvents.

Justify a choice of route by comparing hazards, yield, number of steps and cost.

Key termshazardrisk

Section 7

Core practicals: analysing unknowns and preparing aspirin

Core practical 15 (unknowns): identify inorganic ions with tests (carbonate with acid giving CO₂; halides with AgNO₃ then ammonia; sulfate with barium chloride; cations with sodium hydroxide and ammonia) and organic compounds with the tests above (bromine water, 2,4-DNPH, Tollens', acidified dichromate(VI), sodium hydrogencarbonate). Record observations, not conclusions.

Core practical 16 (aspirin): warm salicylic acid with excess ethanoic anhydride and a few drops of concentrated phosphoric(V) acid in a water bath; add cold water to hydrolyse excess anhydride and precipitate crude aspirin; filter under reduced pressure; recrystallise from the minimum hot solvent; dry and take the melting temperature.

% yield = actual mass ÷ theoretical mass × 100. Example: 2.76 g salicylic acid (0.0200 mol) gives 3.60 g aspirin theoretically.

Key termspercentage yieldcore practical

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Exam questions on Organic synthesis and reaction pathways

  1. An organic liquid X contains only carbon, hydrogen and oxygen. Complete combustion of 0.296 g of X gives 0.704 g of carbon dioxide and 0.360 g of water. The mass spectrum of X has its molecular ion peak at m/z = 74. The infrared spectrum of X has a broad absorption at about 3300 cm⁻¹ and no absorption near 1700 cm⁻¹. Relative atomic masses: H = 1.0, C = 12.0, O = 16.0.
    The ¹H NMR spectrum of X has two singlets with relative peak areas 9 : 1, and X is not oxidised by warm acidified potassium dichromate(VI). Deduce the structural formula of X and explain how the data support your answer.2 marks
  2. Grignard reagents are made by reacting a bromoalkane with magnesium. Ethylmagnesium bromide, CH₃CH₂MgBr, is made from bromoethane and is then used to lengthen carbon chains.
    CH₃CH₂MgBr reacts with propanone, and dilute acid is then added. Give the structural formula of the organic product and explain why the Grignard reagent attacks the carbonyl carbon.2 marks
  3. Chemists often need to lengthen a carbon chain by one carbon atom. Butanoic acid can be made from propan-1-ol by a route using a nitrile or by a route using a Grignard reagent. Hazard data: potassium cyanide is toxic if swallowed or in contact with skin and releases toxic hydrogen cyanide gas with acids; diethyl ether is extremely flammable (flash point −45 °C) and can form explosive peroxides; Grignard reagents react violently with water.
    Suggest a three-step route from propan-1-ol to butanoic acid using a nitrile. Give the reagents and conditions for each step.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).