Viscous drag and Stokes' lawEdexcel A-Level Physics: Flashcards
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State Stokes' law.
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- State Stokes' law.
- F = 6πηrv, the viscous drag on a small sphere of radius r moving at speed v through a fluid of viscosity η.
- Give three conditions for Stokes' law to apply.
- A small sphere, moving at low speed, with laminar flow.
- What is the unit of viscosity?
- Pa s (equivalent to N s m⁻²).
- What is laminar flow?
- Smooth flow in which layers of fluid slide past each other without mixing or eddies.
- What happens to the drag if the flow becomes turbulent?
- It is larger than 6πηrv, so Stokes' law no longer applies.
- What forces act on a ball falling at terminal velocity?
- Weight down; upthrust and viscous drag up. W = U + F, so the resultant force is zero.
- Why does a falling ball reach a terminal velocity?
- Drag increases with speed until weight = upthrust + drag, so acceleration stops.
- How does the viscosity of a liquid change with temperature?
- It decreases as the temperature rises.
- Why do balls fall faster in a hotter oil?
- The oil is less viscous, so a higher speed is needed before drag + upthrust = weight.
- In the falling-ball method, why are timing marks placed well below the surface?
- So that the ball has reached its terminal velocity and moves at constant speed between the marks.
- How is the radius of a ball bearing measured in the core practical?
- Measure the diameter with a micrometer at several places, take the mean and halve it.
- Give an expression for viscosity from terminal velocity.
- η = 2r²(ρ_s − ρ_f)g / (9v), from W − U = 6πηrv.
Exam questions on Viscous drag and Stokes' law
- A steel ball bearing of radius 1.5 mm moves slowly through glycerol of viscosity 1.4 Pa s. The flow around the ball is laminar.The ball is released from rest in a deep tank of glycerol. Explain why it eventually falls at a constant speed.2 marks
- A student drops identical steel balls through a tall column of oil and measures the terminal velocity. At 20 °C the terminal velocity is 0.048 m s⁻¹ and at 50 °C it is 0.31 m s⁻¹. Assume that the density of the oil is the same at both temperatures and that Stokes' law applies.Explain why the balls reach a higher terminal velocity in the oil at 50 °C.2 marks
- A steel ball of radius 2.0 mm and density 7800 kg m⁻³ falls at its terminal velocity of 0.085 m s⁻¹ through an oil of density 920 kg m⁻³. The flow is laminar. Take g = 9.81 N kg⁻¹. The volume of a sphere is 4πr³/3.Calculate the weight of the ball minus the upthrust on the ball.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).