Simple harmonic motion and its equationsEdexcel A-Level Physics: Flashcards
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State the condition for simple harmonic motion.
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- State the condition for simple harmonic motion.
- The resultant force (or acceleration) is proportional to the displacement from equilibrium and directed towards it.
- Write the defining equation of SHM in terms of acceleration.
- a = −ω²x.
- What does the minus sign in a = −ω²x mean?
- The acceleration is always in the opposite direction to the displacement, towards equilibrium.
- How are period, frequency and angular frequency related?
- T = 1/f = 2π/ω, so ω = 2πf.
- Give the equation for displacement in SHM, starting from maximum displacement.
- x = A cos ωt.
- Give the equations for velocity and acceleration in SHM.
- v = −Aω sin ωt and a = −Aω² cos ωt.
- What is the maximum speed in SHM and where does it occur?
- Aω, at the equilibrium position.
- What is the maximum acceleration in SHM and where does it occur?
- Aω², at maximum displacement (the ends of the motion).
- Give the period of a mass on a spring.
- T = 2π√(m/k).
- Give the period of a simple pendulum.
- T = 2π√(l/g), for small angles only.
- Does the period of a pendulum depend on the mass of the bob?
- No, only on the length and g.
- What setting should the calculator be in for SHM equations?
- Radians, because ωt is in radians.
Exam questions on Simple harmonic motion and its equations
- A trolley of mass 0.40 kg is attached to a horizontal spring of spring constant 25 N m⁻¹. The other end of the spring is fixed. The trolley is pulled 0.060 m from its equilibrium position along a frictionless track and released. It then oscillates with simple harmonic motion.Calculate the maximum speed of the trolley.2 marks
- A simple pendulum consists of a small dense bob on a light string. The distance from the pivot to the centre of the bob is 1.50 m. The bob is displaced through a small angle and released. The gravitational field strength is 9.81 N kg⁻¹.Calculate the period and the frequency of the pendulum.2 marks
- A loudspeaker cone vibrates with simple harmonic motion. Its displacement x from the equilibrium position is given by x = A cos ωt, where the amplitude A is 0.12 m and the frequency is 2.5 Hz. Time t = 0 is when the cone is at its maximum positive displacement.Calculate the angular frequency of the vibration and the displacement of the cone 0.050 s after t = 0.3 marks
Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).