Titration Calculations

Titration Calculations Quiz

Spec 3.6.4 · Oxford AQA IGCSE Chemistry: Quiz

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  1. 1. Which equation links moles, concentration and volume in a titration calculation?

    • A. n = c ÷ V
    • B. n = c × V
    • C. c = n × V
    • D. V = n × c
  2. 2. Before using n = c × V with a volume measured in cm³, what must you do?

    • A. Multiply the volume by 1000
    • B. Divide the volume by 1000 to convert it to dm³
    • C. Divide the concentration by 1000
    • D. Nothing — the equation works directly with cm³
  3. 3. 25.0 cm³ of 0.200 mol/dm³ hydrochloric acid exactly neutralises 20.0 cm³ of sodium hydroxide solution (1:1 reaction). What is the concentration of the sodium hydroxide?

    • A. 0.16 mol/dm³
    • B. 0.20 mol/dm³
    • C. 0.25 mol/dm³
    • D. 0.32 mol/dm³
  4. 4. How would you convert a concentration of 0.05 mol/dm³ sodium hydroxide (Mr = 40) into g/dm³?

    • A. 0.05 ÷ 40 = 0.00125 g/dm³
    • B. 0.05 × 40 = 2 g/dm³
    • C. 40 ÷ 0.05 = 800 g/dm³
    • D. 0.05 + 40 = 40.05 g/dm³
  5. 5. In a titration using sulfuric acid and sodium hydroxide (H2SO4 + 2NaOH → Na2SO4 + 2H2O), a student mistakenly uses a 1:1 mole ratio instead of 1:2. What effect would this have on their calculated concentration of sulfuric acid?

    • A. No effect, as the ratio does not matter for this calculation
    • B. The calculated concentration of acid would be twice the correct value
    • C. The calculated concentration of acid would be half the correct value
    • D. The calculation would be impossible to complete

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