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Angles in Polygons & Parallel LinesCambridge IGCSE Maths: Subtopic test

10 questions, 26 marks

Cambridge IGCSE Maths

Angles in Polygons & Parallel Lines

Total 26 marks

Name

Class

Date

  1. 1
    A road planner is measuring angles at a junction where three straight roads meet at a single point.
    (a)
    Three roads meet at a single junction point. Two of the angles between them measure 110°110° and 140°140°. Find the third angle at the junction.
    [1 mark]
    • A110°110°
    • B140°140°
    • C130°130°
    • D100°100°
    (b)
    On one of the roads, a lamppost stands where the road is straight. The angle on one side of the lamppost is 65°65°. Find the angle on the other side.
    [1 mark]
    • A180°180°
    • B65°65°
    • C25°25°
    • D115°115°
    (c)
    Two of the roads cross, forming an X shape. One angle formed is 72°72°. Find the angle vertically opposite it.
    [1 mark]
    • A18°18°
    • B108°108°
    • C72°72°
    • D36°36°

    Total for question 1: 3 marks

  2. 2
    A carpenter is fitting triangular and quadrilateral fence panels and needs to check the interior angles add up correctly.
    (a)
    A fence panel is triangular, with two known interior angles of 58°58° and 74°74°. Find the third angle, giving a geometric reason.
    [2 marks]
    (b)
    A quadrilateral fence panel has three known interior angles of 95°95°, 80°80° and 110°110°. Find the fourth angle, giving a geometric reason.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Two railway tracks run parallel to each other, crossed by a single straight sleeper acting as a transversal.
    (a)
    One angle formed between the transversal and the first track is 63°63°. The corresponding angle on the second track is labelled xx. Find xx, giving a geometric reason.
    [3 marks]
    (b)
    The 63°63° angle lies between the two tracks. A second angle, yy, is formed where the sleeper meets the second track, on the same side of the sleeper as the 63°63° angle and also between the two tracks, so that yy and the 63°63° angle are co-interior angles. Find yy, giving a geometric reason.
    [3 marks]

    Total for question 3: 6 marks

  4. 4
    An architect is designing a gazebo with a regular polygon base and needs to calculate related angle properties for the roof structure.
    (a)
    A regular polygon is used as the base of a decorative garden gazebo. The polygon has 9 sides. Calculate the sum of its interior angles, and hence find the size of one interior angle.
    [4 marks]
    (b)
    Find the size of one exterior angle of the same 9-sided regular polygon, and use it to verify your answer to part (a) using the relationship between interior and exterior angles.
    [4 marks]
    (c)
    An irregular polygon has interior angles xx, x+10°x+10°, x+20°x+20°, x+30°x+30° and x+40°x+40° (5 angles in total). Form and solve an equation to find xx, and hence state the largest interior angle.
    [5 marks]

    Total for question 4: 13 marks

End of questions