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Chemical control in plantsEdexcel A-Level Biology B: Revision notes

Section 1

Plant growth substances

Plants coordinate growth with chemicals called plant growth substances (plant hormones). They are made in small amounts, often in specific tissues, and move by diffusion, active transport or in the phloem to target cells that carry the right receptor. Their effect depends on concentration and on the tissue.

Three you must know are:

  • Auxins (e.g. IAA): cell elongation, apical dominance, root growth
  • Cytokinins: promote cell division, growth of lateral buds, delay leaf ageing
  • Gibberellins: germination and stem elongation
Key termsplant growth substancetarget cell

Section 2

Auxin and cell elongation

Auxin is made mainly in shoot tips and young leaves. It binds to receptors on the plasma membrane of target cells and activates proton pumps. H⁺ ions are pumped into the cell wall, so the wall becomes more acidic.

The low pH activates expansins, which loosen bonds between cellulose microfibrils. Water enters by osmosis and turgor pressure stretches the loosened wall, so the cell elongates.

Auxin also promotes root growth, but roots are far more sensitive: a concentration that stimulates stem elongation can inhibit root elongation. This is why rooting powders are dilute.

Key termsauxincell elongationexpansin
Exam tip

Link the steps: auxin, then H⁺ pumped into the wall, then low pH, then loosened microfibrils, then water uptake and stretching. Do not say auxin makes cells divide.

Section 3

Apical dominance and hormone interaction

In apical dominance auxin made in the apical bud suppresses the growth of lateral buds, so the plant grows tall with little branching. Removing the apical bud lowers auxin near the lateral buds and they grow.

Cytokinins promote lateral bud growth, so the two substances are antagonistic: auxin suppresses lateral buds and cytokinin promotes them. The balance between them decides whether a lateral bud grows. Applying auxin to a cut stump restores suppression, which shows auxin is the inhibitor.

Key termsapical dominanceantagonisticcytokinin
Common mistake

Do not write that auxin 'stops' the lateral buds growing for ever. It suppresses them while the auxin level is high and cytokinin is outweighed.

Section 4

Gibberellin and germination

In a germinating cereal grain the embryo releases gibberellin. It diffuses to the aleurone layer, which makes and releases amylase. Amylase hydrolyses stored starch in the endosperm to maltose, which is hydrolysed to glucose and used in respiration by the embryo for growth.

Core Practical 14 investigates this with a starch agar assay:

  • Place embryo-less grain halves on starch agar containing different concentrations of gibberellin (or cut wells filled with solutions)
  • Incubate, then flood with iodine solution
  • Starch is blue-black; a clear zone shows where amylase hydrolysed starch
  • Measure the zone diameter or area; use a 0 concentration control and keep temperature and incubation time constant
Key termsgibberellinamylasealeurone layerstarch agar assay
Exam tip

Calculate zone area as πr2\pi r^2 using the radius (half the diameter). Area, not diameter, is proportional to the amount of starch hydrolysed.

Section 5

Phytochrome: flowering and photomorphogenesis

Phytochrome is a light-sensitive pigment with two interconvertible forms. Pr absorbs red light (about 660 nm) and is converted to Pfr. Pfr absorbs far-red light (about 730 nm) and is converted back to Pr. In darkness Pfr slowly reverts to Pr. Pfr is the active form.

Flowering: plants respond to the length of the uninterrupted dark period. Short-day plants flower when nights are long and Pfr has fallen low. Long-day plants flower when nights are short and Pfr stays high. A red flash in a long night restores Pfr and can prevent short-day flowering; a far-red flash reverses it.

Photomorphogenesis is the effect of light on form and development. In light, Pfr inhibits stem elongation and promotes leaf expansion and chlorophyll formation. Seedlings in the dark are etiolated: long, pale and unexpanded.

Key termsphytochromePrPfrphotomorphogenesisshort-day plantlong-day plant
Common mistake

Do not say 'short-day plants need short days'. It is the length of the continuous night that matters, which is why a brief light flash in the night prevents flowering.

Must know

  • Plant growth substances: auxin, cytokinin, gibberellin
  • Auxin: cell elongation (acid growth), apical dominance, root growth
  • Cytokinin and auxin are antagonistic in apical dominance
  • Gibberellin: embryo to aleurone to amylase to starch hydrolysis
  • Core Practical 14: starch agar, iodine, clear zones
  • Phytochrome: Pr and Pfr interconvert; controls flowering and photomorphogenesis

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Chemical control in plants

  1. A maltster prepares barley for brewing by soaking the grains and letting them germinate. During germination the embryo releases gibberellin, which diffuses to the aleurone layer around the starch-rich endosperm. The aleurone cells then make and release amylase. The maltster stops germination by heating the grains once enough starch has been broken down.
    Explain how the production of amylase allows the barley embryo to grow.2 marks
  2. A gardener has three identical single-stemmed saplings of a shrub. On plant X she removes the apical bud. Plant Y is left intact. On plant Z she removes the apical bud and immediately applies a paste containing auxin to the cut surface. After two weeks plant X has produced many lateral shoots, whereas plants Y and Z have produced almost none.
    Explain why plant X produced many lateral shoots.2 marks
  3. A student investigates the effect of gibberellic acid on amylase production. She cuts barley grains in half and keeps only the halves without an embryo. She places five halves, cut face down, on each of four starch agar plates containing gibberellic acid at 0, 1, 10 and 100 mg dm⁻³. After 48 hours she removes the grain halves and floods each plate with iodine solution. The mean diameter of the clear zone around the grain halves is 0 mm, 6 mm, 12 mm and 14 mm respectively.
    Explain the appearance of the plates after they were flooded with iodine solution, including the plate that contained no gibberellic acid.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).