Arrhenius equation and activation energy Quiz
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5 questions, one answer each
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1. The gradient of a graph of ln k against 1/T is −5.0 × 10³ K. What is the activation energy? (R = 8.31 J K⁻¹ mol⁻¹)
- A. 0.60 kJ mol⁻¹
- B. 41.6 kJ mol⁻¹
- C. −41.6 kJ mol⁻¹
- D. 60 kJ mol⁻¹
2. A student plots ln k against T (in °C). Why will this not give a straight line from which Eₐ can be found?
- A. Because ln k is not a valid quantity
- B. Because the Arrhenius equation needs 1/T with T in kelvin
- C. Because R is not a constant
- D. Because k does not depend on temperature
3. Which change makes the line of ln k against 1/T less steep?
- A. Raising the temperature
- B. Adding a catalyst
- C. Increasing the concentration
- D. Using a larger volume
4. In a clock-type experiment, which graph gives Eₐ?
- A. t against T
- B. 1/t against 1/T
- C. ln(1/t) against 1/T
- D. ln t against T
5. What does the intercept on the vertical axis of ln k against 1/T represent?
- A. Eₐ
- B. ln A
- C. −Eₐ/R
- D. R