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Hooke's law and elastic energyAQA A-Level Further Maths: Flashcards

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State Hooke's law for an elastic string.

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State Hooke's law for an elastic string.
T=λxlT=\frac{\lambda x}{l}, so tension is proportional to extension.
What does λ\lambda represent?
The modulus of elasticity of the string, in newtons.
What is the stiffness kk in terms of λ\lambda and ll?
k=λlk=\frac{\lambda}{l}, so T=kxT=kx.
State the elastic potential energy of a stretched string.
λx22l=12kx2\frac{\lambda x^2}{2l}=\frac12kx^2
Why is there a factor 12\frac12 in the elastic potential energy?
The tension rises from zero to TT, so the work done is the average tension times the extension.
What tension acts in a slack string?
None: it is zero.
A string with l=1.2l=1.2 m, λ=36\lambda=36 N is stretched to 1.5 m. Find TT.
36×0.31.2=9\frac{36\times0.3}{1.2}=9 N
What is the extension?
Stretched length minus natural length.
What is the condition for equilibrium of a particle hanging on a vertical string?
λxl=mg\frac{\lambda x}{l}=mg
Three energy forms in a conservation problem with a string?
Kinetic, gravitational potential and elastic potential energy.
Where is the speed greatest for a particle falling on a vertical string?
Where tension equals weight (resultant force zero), not at the lowest point.
What is the kinetic energy of a particle at the lowest point of its fall?
Zero: it is instantaneously at rest.

Exam questions on Hooke's law and elastic energy

  1. A light elastic string has natural length 1.2 m and modulus of elasticity 36 N. One end is fixed to a point AA on a smooth horizontal table and a particle PP of mass 0.5 kg is attached to the other end. PP is held on the table with the string stretched to a total length of 1.5 m.
    PP is released from rest. Find the speed of PP when the string reaches its natural length.2 marks
  2. A particle of mass 2 kg hangs in equilibrium at the end of a light elastic string. The other end of the string is fixed to a point OO. The natural length of the string is 0.5 m and its extension in equilibrium is 0.25 m. Take g=9.8 m s−2g=9.8\text{ m s}^{-2}.
    The particle is pulled down until the extension of the string is 0.6 m and is then released from rest. Find the speed of the particle at the instant the string becomes slack.2 marks
  3. A toy truck of mass 0.3 kg is attached to one end of a light elastic string of natural length 0.6 m and modulus of elasticity 24 N. The other end of the string is fixed to a point BB on a smooth horizontal floor. The truck is pulled along the floor until it is 1.0 m from BB, with the string straight, and is then released from rest.
    Find the tension in the string and the initial acceleration of the truck.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).