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One-sample t-testAQA A-Level Further Maths: Flashcards

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What is the test statistic for a one-sample $t$-test?

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What is the test statistic for a one-sample tt-test?
t=xˉ−μ0s/nt=\frac{\bar x-\mu_0}{s/\sqrt n}
How many degrees of freedom does a one-sample tt-test have?
ν=n−1\nu=n-1
When is a tt-test used instead of a zz-test?
When the population is normal, the variance is unknown and the sample is small, so ss replaces σ\sigma.
How does the tt-distribution differ from the normal?
It is symmetric but has heavier tails; it tends to the normal as ν\nu increases.
Formula for the unbiased estimate of variance?
s2=1n−1(∑x2−(∑x)2n)s^2=\frac{1}{n-1}\left(\sum x^2-\frac{(\sum x)^2}{n}\right)
What assumption is needed for the tt-test?
The population is normally distributed (and the sample is random).
Which table column is used for a two-tailed 5%5\% test?
The 2.5%2.5\% one-tail column.
What is the critical region?
The values of tt beyond the critical value(s), for which H0H_0 is rejected.
What is H1H_1 for a two-tailed test?
H1:μ≠μ0H_1:\mu\neq\mu_0
When is a one-tailed H1H_1 justified?
When the question gives the direction before the data are seen.
If tt is in the critical region, what do you do?
Reject H0H_0 and state the conclusion in context, e.g. 'evidence that the mean is lower'.
If tt is not in the critical region, what do you say?
Do not reject H0H_0: insufficient evidence at that level, not proof that H0H_0 is true.
Given a variance of 144144, what is ss?
s=144=12s=\sqrt{144}=12, then use sn\frac{s}{\sqrt n}.

Exam questions on One-sample t-test

  1. A café claims that the mean volume of its large coffees is 250250 ml. Volumes are normally distributed. A customer measures 99 randomly chosen large coffees and finds a sample mean of 243.4243.4 ml and an unbiased estimate of the population variance of 8181 ml2^2.
    A test is carried out at the 5%5\% significance level of H0:μ=250H_0:\mu=250 against H1:μ<250H_1:\mu<250. The critical value of tt is −1.860-1.860. State the conclusion of the test, in context.2 marks
  2. A gardener claims that a variety of sunflower grows to a mean height of 180180 cm. Heights are normally distributed. A random sample of 1010 plants has heights xx cm with ∑x=1840\sum x=1840 and ∑x2=339 136\sum x^2=339\,136.
    A test is carried out at the 5%5\% significance level of H0:μ=180H_0:\mu=180 against H1:μ≠180H_1:\mu\neq180. The critical values of tt are ±2.262\pm2.262. State the conclusion of the test, in context.2 marks
  3. An environment agency states that the mean nitrate concentration in a river is 2525 mg per litre. Concentrations are normally distributed. Residents suspect that the mean is higher, and the agency takes 66 random readings, in mg per litre: 27.4, 25.9, 28.1, 26.5, 29.0, 27.727.4,\ 25.9,\ 28.1,\ 26.5,\ 29.0,\ 27.7.
    Calculate the sample mean and an unbiased estimate of the population variance.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).