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Induction for divisibility and matrix powersAQA A-Level Further Maths: Flashcards

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How do you write the inductive hypothesis for divisibility by $d$?

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How do you write the inductive hypothesis for divisibility by dd?
f(k)=dmf(k)=dm for some integer mm.
What must the final line of the inductive step show?
f(k+1)=d×(an integer expression)f(k+1)=d\times(\text{an integer expression}).
What are the two usual methods for the step?
Show f(k+1)−f(k)f(k+1)-f(k) is a multiple of dd, or substitute the hypothesis into f(k+1)f(k+1).
Simplify 5k+1−5k5^{k+1}-5^k.
4×5k4\times5^k
Simplify 7k+1−7k7^{k+1}-7^k.
6×7k6\times7^k
Why is k(k+1)k(k+1) always even?
One of two consecutive integers is even.
Find g(k+1)−g(k)g(k+1)-g(k) for g(n)=n3+11ng(n)=n^3+11n.
3k2+3k+123k^2+3k+12
How do you obtain Mk+1\mathbf{M}^{k+1} in an inductive proof?
Mk+1=MkM\mathbf{M}^{k+1}=\mathbf{M}^k\mathbf{M}, with Mk\mathbf{M}^k replaced by the assumed formula.
M=(1101)\mathbf{M}=\begin{pmatrix}1&1\\ 0&1\end{pmatrix}: what is Mn\mathbf{M}^n?
(1n01)\begin{pmatrix}1&n\\ 0&1\end{pmatrix}
(2003)n=\begin{pmatrix}2&0\\ 0&3\end{pmatrix}^n=?
(2n003n)\begin{pmatrix}2^n&0\\ 0&3^n\end{pmatrix}
Why calculate M2\mathbf{M}^2 and M3\mathbf{M}^3 before proving?
To spot the pattern or check the given formula for small nn.
Write a full conclusion for a divisibility proof.
True for n=1n=1; if true for n=kn=k then true for n=k+1n=k+1; so true for all positive integers nn by induction.

Exam questions on Induction for divisibility and matrix powers

  1. Let f(n)=5n+3f(n)=5^n+3 for positive integers nn. It is to be proved by induction that f(n)f(n) is divisible by 44 for all nn.
    Assuming that f(k)f(k) is divisible by 44, show that f(k+1)f(k+1) is divisible by 44.2 marks
  2. The matrix M=(1201)\mathbf{M}=\begin{pmatrix}1&2\\ 0&1\end{pmatrix} satisfies Mn=(12n01)\mathbf{M}^n=\begin{pmatrix}1&2n\\ 0&1\end{pmatrix} for every positive integer nn.
    Find the smallest positive integer nn for which the top-right entry of Mn\mathbf{M}^n is greater than 10001000.2 marks
  3. Let A=(3−22−1)\mathbf{A}=\begin{pmatrix}3&-2\\ 2&-1\end{pmatrix}. A student conjectures that An=(1+2n−2n2n1−2n)\mathbf{A}^n=\begin{pmatrix}1+2n&-2n\\ 2n&1-2n\end{pmatrix} for all positive integers nn.
    Calculate A2\mathbf{A}^2 and A3\mathbf{A}^3, and show that the conjecture is correct for n=2n=2 and n=3n=3.3 marks
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Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).