All revision notes topics

Number sequences and patternsIB MYP Maths Standard: Revision notes

Section 1

Sequences and describing patterns

A sequence is a list of numbers that follow a rule. Each number is a term. You can describe a rule in two ways:

  • Term-to-term rule: how to get from one term to the next, such as "add 4".
  • Position-to-term rule (the nnth term): how to get a term from its position nn, such as 4n+34n+3. To continue a sequence, look at the differences between neighbouring terms. For 7,11,15,197,11,15,19 the differences are all 44.
Key termssequencetermcommon difference
Exam tip

Write the differences between terms above the sequence. If they are all the same, the sequence is linear.

Section 2

Special sequences

Some sequences have names you should recognise.

  • Square numbers: 1,4,9,16,25,…1,4,9,16,25,\ldots (n2n^2).
  • Triangular numbers: 1,3,6,10,15,21,…1,3,6,10,15,21,\ldots. The differences are 2,3,4,5,6,…2,3,4,5,6,\ldots, so each term adds the next whole number: 11, 1+21+2, 1+2+31+2+3, and so on.
  • Cube numbers: 1,8,27,64,…1,8,27,64,\ldots (n3n^3).
  • Fibonacci-type: each term is the sum of the previous two. 1,1,2,3,5,8,13,…1,1,2,3,5,8,13,\ldots If the first two terms are different, such as 2,3,5,8,132,3,5,8,13, it is still Fibonacci-type.
Key termssquare numbertriangular numberFibonacci-type
Common mistake

Thinking 25 is triangular because it is a square number. Triangular numbers go 21, 28, 36, so 25 is not one of them.

Section 3

The nth term of a linear sequence

A sequence with a common difference dd has nnth term an+ban+b, where aa equals the common difference and bb is found from the first term: b=first term−ab=\text{first term}-a. Example: 7,11,15,197,11,15,19 has d=4d=4, so the rule starts 4n4n. 4(1)=44(1)=4 but the first term is 77, so add 33: the nnth term is 4n+34n+3. For a decreasing sequence dd is negative: 20,17,1420,17,14 has d=−3d=-3 and nnth term −3n+23-3n+23, which can be written 23−3n23-3n.

Key termsnth termlinear sequence
Exam tip

Check your rule by putting n=1n=1 and n=2n=2 in. You should get the first two terms.

Section 4

Using the nth term

Finding a term: substitute the position. For 4n+34n+3, the 50th term is 4(50)+3=2034(50)+3=203. Testing if a number is in the sequence: set the rule equal to the number and solve for nn. The number is a term only if nn is a positive whole number.

  • Is 150150 in 4n+34n+3? 4n+3=1504n+3=150 gives n=36.75n=36.75. Not whole, so no.
  • Is −40-40 in 23−3n23-3n? 23−3n=−4023-3n=-40 gives n=21n=21. Whole, so yes: it is the 21st term. First term above or below a value: solve the inequality, then round to the next whole number. 23−3n<023-3n<0 gives n>7.67n>7.67, so n=8n=8.
Key termsposition
Common mistake

Saying a number is in the sequence when nn is a decimal. The position must be a whole number.

Section 5

Generalising patterns from diagrams (criterion B)

Pattern questions often describe a diagram, such as tables pushed together in a row. To generalise the pattern:

  1. Count the value for the first few patterns and put them in a table: 4,6,84,6,8 seats for 1,2,31,2,3 tables.
  2. Find the common difference (22), so the rule starts 2n2n.
  3. Use the first term to find bb: 2(1)+b=42(1)+b=4 gives b=2b=2, so the rule is 2n+22n+2.
  4. Explain the rule using the diagram: each table adds a seat on the top and bottom (2n2n), and each end of the row adds one more (+2+2).
  5. Verify with a new case, counting directly: six tables give 6+6+2=146+6+2=14, and the rule gives 2(6)+2=142(6)+2=14.
Key termsgeneraliseverify
Exam tip

In criterion B answers, always do the three steps: describe the pattern, write the rule, then verify it.

Section 6

Solving problems with rules

Real situations can use the same rule. For the tables, 2n+22n+2 seats for nn tables. To seat 3131 people solve 2n+2≥312n+2\ge31: n≥14.5n\ge14.5, so use the next whole number, 1515 tables. Always round to a whole number that still meets the need, and state any assumption of the model, such as one person sitting at each free edge.

Key termsassumption
Common mistake

Rounding 14.514.5 tables down to 1414. Round up when you need at least the amount asked for.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Number sequences and patterns

  1. A sequence begins 7, 11, 15, 19, …7,\ 11,\ 15,\ 19,\ \ldots and continues in the same way.
    Show that 150150 is not a term in the sequence.2 marks
  2. The first five triangular numbers are 1, 3, 6, 10, 151,\ 3,\ 6,\ 10,\ 15.
    Find the 1010th triangular number.2 marks
  3. The first three terms of a sequence are 20, 17, 1420,\ 17,\ 14, and the sequence continues with the same common difference.
    Find an expression for the nnth term of the sequence.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).