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Probability basics and sample spacesIB MYP Maths Standard: Revision notes

Section 1

The probability scale

Probability measures how likely an event is. It is a number from 00 to 11, written as a fraction, decimal or percentage.

  • 00: impossible (for example, rolling a 7 on a normal die)
  • 12\frac{1}{2}: even chance
  • 11: certain The closer to 11, the more likely the event. A probability can never be less than 00 or greater than 11.
Key termsprobabilityimpossiblecertain
Common mistake

Giving a probability greater than 11 or negative. Check that your answer is between 00 and 11.

Section 2

Equally likely outcomes

When all outcomes are equally likely (a fair die, a fair coin, a counter taken at random): P(event)=number of favourable outcomestotal number of outcomes.P(\text{event})=\frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}. Worked example: a bag has 5 red, 3 blue and 2 green counters. P(blue)=310P(\text{blue})=\frac{3}{10}, because 3 of the 10 counters are blue. Simplify fractions where possible.

Key termsequally likelyfavourable outcome
Exam tip

The total is every outcome, not only the ones of another colour. Compare the favourable outcomes with the whole bag.

Section 3

Sample spaces

The sample space is the list of all possible outcomes. List outcomes systematically so none are missed, or use a table (a sample space diagram) for two events. Two four-sided spinners give 4×4=164\times4=16 outcomes: (1,1),(1,2),…,(4,4)(1,1),(1,2),\dots,(4,4). The total is 55 for (1,4)(1,4), (2,3)(2,3), (3,2)(3,2), (4,1)(4,1), so P(total 5)=416=14P(\text{total }5)=\frac{4}{16}=\frac{1}{4}. A coin and a three-section spinner give H1,H2,H3,T1,T2,T3H1,H2,H3,T1,T2,T3: 2×3=62\times3=6 outcomes. For two dice there are 6×6=366\times6=36 outcomes.

Key termssample spaceoutcomesample space diagram
Common mistake

Leaving out outcomes such as (1,4)(1,4) and (4,1)(4,1). These are different outcomes, so list both.

Section 4

The probability of an event not happening

Either an event happens or it does not, so the probabilities add to 11: P(not A)=1−P(A).P(\text{not }A)=1-P(A). Example: P(red)=510P(\text{red})=\frac{5}{10}, so P(not red)=1−510=12P(\text{not red})=1-\frac{5}{10}=\frac{1}{2}. This is often quicker than counting all the other outcomes.

Key termscomplement

Section 5

Mutually exclusive events

Events are mutually exclusive if they cannot happen at the same time. For mutually exclusive events AA and BB: P(A or B)=P(A)+P(B).P(A\text{ or }B)=P(A)+P(B). Example: a counter cannot be both red and green, so P(red or green)=510+210=710P(\text{red or green})=\frac{5}{10}+\frac{2}{10}=\frac{7}{10}. If the events can both happen (for example 'an odd number' and 'a prime number' on a die), you cannot simply add. If a list of mutually exclusive events covers every outcome, their probabilities add to 11.

Key termsmutually exclusive
Common mistake

Adding probabilities for events that overlap. Only add when the events cannot happen together.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Probability basics and sample spaces

  1. A bag at a school fair in Nairobi holds 5 red counters, 3 blue counters and 2 green counters. One counter is taken from the bag at random.
    Find the probability that the counter is red or green. Give a reason why you can add probabilities.2 marks
  2. Two fair four-sided spinners, each numbered 1 to 4, are spun and the two scores are added together.
    Find the probability that the total is at least 7.2 marks
  3. A fair coin is flipped and a fair spinner with three equal sections numbered 1, 2 and 3 is spun.
    List the sample space. Find the probability of getting heads and an odd number.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).