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Trigonometric ratios in right-angled trianglesIB MYP Maths Standard: Revision notes

Section 1

Labelling the sides

In a right-angled triangle the hypotenuse is the longest side, opposite the right angle. The other two sides are named from the point of view of the angle θ\theta you are using: the opposite side is across from θ\theta and the adjacent side is next to θ\theta (not the hypotenuse). If you switch to the other acute angle, opposite and adjacent swap. The hypotenuse never changes.

Key termshypotenuseoppositeadjacent
Common mistake

Labelling opposite and adjacent from the wrong angle. Re-label every time you change angle.

Section 2

Sine, cosine and tangent

The three trigonometric ratios link an angle with two sides: sin⁡θ=oppositehypotenuse,cos⁡θ=adjacenthypotenuse,tan⁡θ=oppositeadjacent.\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}},\quad\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}},\quad\tan\theta=\frac{\text{opposite}}{\text{adjacent}}. The memory aid is SOH CAH TOA. To choose a ratio, mark the two sides involved (the one you know and the one you want, or the two you know) and pick the ratio that uses exactly those two sides.

Key termssinecosinetangent
Exam tip

Write 'O, A, H' on the sides before choosing the ratio.

Section 3

Finding an unknown side

Write the ratio, substitute the numbers, then solve. Example: the hypotenuse is 1010 cm and the angle is 30∘30^\circ. The side opposite is wanted, so use sine: sin⁡30∘=x10\sin30^\circ=\frac{x}{10} and x=10sin⁡30∘=5x=10\sin30^\circ=5 cm. If the unknown side is on the bottom of the fraction, divide instead: tan⁡25∘=60d\tan25^\circ=\frac{60}{d} gives d=60tan⁡25∘=128.7d=\frac{60}{\tan25^\circ}=128.7 m. Make sure your calculator is in degree mode.

Common mistake

Multiplying when the unknown is the denominator. For tan⁡25∘=60d\tan25^\circ=\frac{60}{d} you divide: d=60÷tan⁡25∘d=60\div\tan25^\circ.

Section 4

Finding an unknown angle

When you know two sides and want the angle, use the inverse function: sin⁡−1\sin^{-1}, cos⁡−1\cos^{-1} or tan⁡−1\tan^{-1} on your calculator. Example: opposite 77 and adjacent 99, so tan⁡θ=79\tan\theta=\frac{7}{9} and θ=tan⁡−1(79)=37.9∘\theta=\tan^{-1}\left(\frac79\right)=37.9^\circ. For the other acute angle in the same triangle use 90∘−37.9∘=52.1∘90^\circ-37.9^\circ=52.1^\circ. Round angles to 11 decimal place unless told otherwise.

Key termsinverse function

Section 5

Angles of elevation and depression

The angle of elevation is measured upwards from the horizontal to the line of sight. The angle of depression is measured downwards from the horizontal. The two angles are equal for the same line of sight, because they are alternate angles between parallel horizontal lines. So an observer on a cliff who sees a boat at a depression of 25∘25^\circ means that the boat sees the observer at an elevation of 25∘25^\circ.

Key termsangle of elevationangle of depression
Exam tip

Draw the horizontal first. Elevation and depression are always measured from a horizontal line, not a vertical one.

Section 6

Using trigonometry well

For each problem: draw a clear right-angled triangle, label the sides, choose the ratio, write the working, and check the answer makes sense (the hypotenuse is the longest side). Give lengths to 33 significant figures and angles to 11 decimal place unless told otherwise. If a measurement is rounded, a calculated answer is only approximate, so allow for that when you comment on accuracy.

Common mistake

Using Pythagoras when an angle is given, or a trigonometric ratio when two sides are known and the third is wanted. Use the tool that matches the information.

That's the notes covered.

Carry on to the next subtopic.

Exam questions on Trigonometric ratios in right-angled triangles

  1. A ladder 55 m long rests against a vertical wall on level ground. The foot of the ladder is 1.51.5 m from the wall.
    The foot of the ladder is moved so that it is 22 m from the wall. Find the new angle between the ladder and the ground.2 marks
  2. A hiker stands at the top of a vertical cliff that is 6060 m above the sea. She looks at a boat on the sea and measures the angle of depression of the boat as 25∘25^\circ.
    The boat sails 4040 m straight towards the cliff. Find the new angle of depression of the boat, to 11 decimal place.2 marks
  3. In triangle ABCABC, angle B=90∘B=90^\circ, AB=7.2AB=7.2 cm and AC=11.5AC=11.5 cm.
    Find the size of angle BACBAC, to 11 decimal place.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).