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4.8 Binomial distributionIB Maths: Applications and Interpretation SL: Revision notes

Section 1

When the binomial model applies

A binomial distribution models the number of successes in a fixed number of trials. It is appropriate when: there is a fixed number nn of trials; each trial has only two outcomes, success and failure; the probability of success pp is the same each time; and the trials are independent. Examples: the number of correct guesses on a multiple-choice quiz, free throws scored, or defective bulbs in a box. We write X∼B(n,p)X\sim\mathrm{B}(n,p).

Key termsbinomial distributiontrialsuccessindependent
Common mistake

Using the binomial model when items are drawn without replacement from a small group: the probability changes, so the trials are not independent.

Section 2

Defining the variable

State the distribution clearly, with nn and pp from the context. A quiz of 12 questions guessed at random with four options each gives X∼B(12,0.25)X\sim\mathrm{B}(12,0.25). 'Success' is whatever you are counting, even if it is bad news, such as a defective bulb with p=0.04p=0.04. The probability of exactly xx successes is P(X=x)=(nx)px(1−p)n−x,P(X=x)=\binom{n}{x}p^x(1-p)^{n-x}, but in examinations you should find binomial probabilities using technology.

Key termssuccess probability
Exam tip

Write 'Let XX be the number of ...' and X∼B(n,p)X\sim\mathrm{B}(n,p) before using the GDC: it earns the method mark even if the final value is wrong.

Section 3

Finding probabilities with the GDC

Use binomial pdf for P(X=x)P(X=x) and binomial cdf for P(X≤x)P(X\leq x). Enter nn, pp and xx. For X∼B(12,0.25)X\sim\mathrm{B}(12,0.25), P(X=3)=0.258P(X=3)=0.258. Convert other inequalities into 'less than or equal':

  • P(X≥k)=1−P(X≤k−1)P(X\geq k)=1-P(X\leq k-1)
  • P(a≤X≤b)=P(X≤b)−P(X≤a−1)P(a\leq X\leq b)=P(X\leq b)-P(X\leq a-1)
  • P(X<k)=P(X≤k−1)P(X<k)=P(X\leq k-1) Example: S∼B(15,0.35)S\sim\mathrm{B}(15,0.35), P(S≥8)=1−P(S≤7)=0.113P(S\geq8)=1-P(S\leq7)=0.113. To find the smallest kk with P(X≤k)>0.9P(X\leq k)>0.9, use a table of cumulative values and look for where it first passes 0.90.9.
Key termsbinomial pdfbinomial cdf
Common mistake

Using 1−P(X≤k)1-P(X\leq k) for P(X≥k)P(X\geq k): that leaves out kk itself. Use 1−P(X≤k−1)1-P(X\leq k-1).

Section 4

Mean and variance

For X∼B(n,p)X\sim\mathrm{B}(n,p): E(X)=np,Var(X)=np(1−p).\mathrm{E}(X)=np,\qquad\mathrm{Var}(X)=np(1-p). For B(8,0.7)\mathrm{B}(8,0.7), the mean is 5.65.6 and the variance is 1.681.68. The mean is the expected number of occurrences from SL 4.5: with nn trials each with probability pp, you expect npnp successes. A formal proof of these results is not required.

Key termsmeanvariance
Exam tip

The mean need not be a whole number: it is a long-run average.

Section 5

Worked example and exam approach

A factory's bulbs are defective with probability 0.040.04, in boxes of 25. Let D∼B(25,0.04)D\sim\mathrm{B}(25,0.04). Then P(D=0)=0.9625=0.360P(D=0)=0.96^{25}=0.360 and P(D≥2)=1−P(D≤1)=0.264P(D\geq2)=1-P(D\leq1)=0.264. Interpret in context: about 26% of boxes contain two or more defective bulbs. In a question, follow the sequence: define the variable, state B(n,p)\mathrm{B}(n,p), rewrite the probability in terms of P(X=x)P(X=x) or P(X≤x)P(X\leq x), use the GDC, and give the answer to 3 s.f. Where the question asks about the model, name two conditions: fixed number of independent trials, constant probability of success.

Key termsmodel
Exam tip

Keep unrounded GDC values for later parts; round only the final answer.

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Exam questions on 4.8 Binomial distribution

  1. A multiple-choice quiz has 12 questions, each with four options of which exactly one is correct. A student guesses every answer at random. Let XX be the number of questions answered correctly.
    Use your GDC to find the probability that the student answers exactly 3 questions correctly.2 marks
  2. A basketball player scores a free throw with probability 0.7, independently each time. She takes 8 free throws. Let YY be the number of free throws she scores.
    Find the mean and the variance of YY.2 marks
  3. A factory makes light bulbs. Each bulb is defective with probability 0.04, independently of the others. A box contains 25 bulbs. Let DD be the number of defective bulbs in a box.
    (i) Write down the distribution of DD. (ii) State two conditions that must hold for this model to be appropriate.3 marks
See the full worksheet

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).