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Roots of complex numbersEdexcel International A Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel International A Level Further Maths

Roots of complex numbers

Total 27 marks

Name

Class

Date

  1. 1
    Consider the equation z3=8z^3=8.
    (a)
    What is the modulus of each root of the equation?
    [1 mark]
    • A88
    • B83\frac83
    • C222\sqrt2
    • D22
    (b)
    Which of the following is the complete set of roots of the equation?
    [1 mark]
    • A2,  2e2πi/3,  2e−2πi/32,\;2e^{2\pi i/3},\;2e^{-2\pi i/3}
    • B2,  2eiπ/3,  2e2πi/32,\;2e^{i\pi/3},\;2e^{2\pi i/3}
    • C2eiπ/3,  −2,  2e−iπ/32e^{i\pi/3},\;-2,\;2e^{-i\pi/3}
    • D8,  8e2πi/3,  8e4πi/38,\;8e^{2\pi i/3},\;8e^{4\pi i/3}
    (c)
    Find the non-real roots of the equation in the form a+iba+ib, giving aa and bb as exact values.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    The complex number w=−8+83 iw=-8+8\sqrt3\,i and the equation z4=wz^4=w.
    (a)
    Which gives the modulus and the principal argument of ww?
    [1 mark]
    • A1616 and −π3-\dfrac\pi3
    • B1616 and π3\dfrac\pi3
    • C1616 and 2π3\dfrac{2\pi}{3}
    • D44 and 2π3\dfrac{2\pi}{3}
    (b)
    What is the angle between the arguments of adjacent roots of z4=wz^4=w?
    [1 mark]
    • Aπ4\dfrac\pi4
    • Bπ2\dfrac\pi2
    • C2π3\dfrac{2\pi}{3}
    • Dπ6\dfrac\pi6
    (c)
    Find the four roots of z4=wz^4=w in the form reiθre^{i\theta}, where −π<θ≤π-\pi<\theta\le\pi.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Consider the equation z3=−27iz^3=-27i.
    (a)
    Solve the equation, giving the roots in the form reiθre^{i\theta}, where −π<θ≤π-\pi<\theta\le\pi.
    [3 marks]
    (b)
    Hence solve (w+2)3=−27i(w+2)^3=-27i, giving each root in the form a+iba+ib with exact values of aa and bb.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Consider the equation z5=1z^5=1.
    (a)
    Find the roots of the equation in the form eiθe^{i\theta}, where −π<θ≤π-\pi<\theta\le\pi, and hence show that cos⁡2π5+cos⁡4π5=−12\cos\frac{2\pi}{5}+\cos\frac{4\pi}{5}=-\frac12.
    [6 marks]
    (b)
    Use the roots of z5=1z^5=1 to show that the roots of (w+1)5=w5(w+1)^5=w^5 are w=−12−i2cot⁡kπ5w=-\frac12-\frac i2\cot\frac{k\pi}{5} for k=1,2,3,4k=1,2,3,4.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).