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Hyperbolic and trigonometric substitutionsEdexcel International A Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel International A Level Further Maths

Hyperbolic and trigonometric substitutions

Total 27 marks

Name

Class

Date

  1. 1
    A student evaluates integrals of the form ∫dxa2+x2\int\frac{dx}{a^2+x^2} and ∫dxx2±a2\int\frac{dx}{\sqrt{x^2\pm a^2}} using the standard results.
    (a)
    Find the exact value of ∫03dx9+x2\int_0^3\frac{dx}{9+x^2}.
    [1 mark]
    • Aπ4\frac\pi4
    • B3π4\frac{3\pi}{4}
    • Cπ12\frac\pi{12}
    • Dπ36\frac{\pi}{36}
    (b)
    Find ∫dxx2−4\int\frac{dx}{\sqrt{x^2-4}} for x>2x>2.
    [1 mark]
    • Aarsinh⁡x2+c\operatorname{arsinh}\frac x2+c
    • Barcosh⁡x2+c\operatorname{arcosh}\frac x2+c
    • Carcsin⁡x2+c\arcsin\frac x2+c
    • D12arcosh⁡x2+c\frac12\operatorname{arcosh}\frac x2+c
    (c)
    Find the exact value of ∫03dxx2+9\int_0^3\frac{dx}{\sqrt{x^2+9}} in terms of a natural logarithm.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    Let I=∫dxx2+6x+13I=\int\frac{dx}{\sqrt{x^2+6x+13}}.
    (a)
    Which expression is equal to x2+6x+13x^2+6x+13?
    [1 mark]
    • A(x+3)2+13(x+3)^2+13
    • B(x+3)2−4(x+3)^2-4
    • C(x+6)2−23(x+6)^2-23
    • D(x+3)2+4(x+3)^2+4
    (b)
    Find II.
    [1 mark]
    • Aarsinh⁡x+32+c\operatorname{arsinh}\frac{x+3}{2}+c
    • B12arsinh⁡(x+3)+c\frac12\operatorname{arsinh}(x+3)+c
    • Carcsin⁡x+32+c\arcsin\frac{x+3}{2}+c
    • D12arctan⁡x+32+c\frac12\arctan\frac{x+3}{2}+c
    (c)
    Hence find the exact value of ∫−31dxx2+6x+13\int_{-3}^{1}\frac{dx}{\sqrt{x^2+6x+13}}.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    Let I=∫02dx(x2+4)2I=\int_0^2\frac{dx}{\left(x^2+4\right)^2}.
    (a)
    Use the substitution x=2tan⁡θx=2\tan\theta to show that I=18∫0π/4cos⁡2θ dθI=\frac18\int_0^{\pi/4}\cos^2\theta\,d\theta.
    [3 marks]
    (b)
    Hence find the exact value of II.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    Some integrals involving quadratic surds can be found using a hyperbolic or a trigonometric substitution.
    (a)
    Use the substitution x=2sinh⁡ux=2\sinh u to find ∫x2x2+4 dx\int\frac{x^2}{\sqrt{x^2+4}}\,dx.
    [6 marks]
    (b)
    Use the substitution x=sin⁡θx=\sin\theta to find the exact value of ∫01/2x21−x2 dx\int_0^{1/2}\frac{x^2}{\sqrt{1-x^2}}\,dx.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).