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Variable forcesEdexcel International A Level Further Maths: Subtopic test

10 questions, 27 marks

Edexcel International A Level Further Maths

Variable forces

Total 27 marks

Name

Class

Date

  1. 1
    A particle PP of mass 22 kg moves in a straight line. At time tt seconds the resultant force on PP is (6t+4)(6t+4) N in the direction of motion. PP is at rest at the point OO when t=0t=0.
    (a)
    Find the acceleration of PP when t=2t=2.
    [1 mark]
    • A1616 m s−2^{-2}
    • B3232 m s−2^{-2}
    • C88 m s−2^{-2}
    • D33 m s−2^{-2}
    (b)
    Find the speed of PP when t=2t=2.
    [1 mark]
    • A1010 m s−1^{-1}
    • B1616 m s−1^{-1}
    • C2020 m s−1^{-1}
    • D88 m s−1^{-1}
    (c)
    Find the distance travelled by PP in the first 22 seconds.
    [2 marks]

    Total for question 1: 4 marks

  2. 2
    A particle PP of mass 0.50.5 kg moves along the positive xx-axis on a smooth horizontal surface, starting from the origin OO with speed 66 m s−1^{-1}. When PP is at displacement xx metres from OO, the only horizontal force on PP is a resistance of magnitude 2x2x N acting towards OO.
    (a)
    Which equation of motion applies to PP, with vv its speed at displacement xx?
    [1 mark]
    • Advdx=−4x\frac{dv}{dx}=-4x
    • Bvdvdx=−2xv\frac{dv}{dx}=-2x
    • Cvdvdx=−xv\frac{dv}{dx}=-x
    • Dvdvdx=−4xv\frac{dv}{dx}=-4x
    (b)
    Find the greatest distance of PP from OO.
    [1 mark]
    • A66 m
    • B33 m
    • C99 m
    • D323\sqrt2 m
    (c)
    Find the speed of PP when it is 22 m from OO.
    [2 marks]

    Total for question 2: 4 marks

  3. 3
    A particle PP of mass 33 kg moves in a straight line. At time tt seconds, PP has speed vv m s−1^{-1} and the only horizontal force acting on PP is a resistance of magnitude 6v6v N. When t=0t=0 the speed of PP is 88 m s−1^{-1}.
    (a)
    Show that v=8e−2tv=8e^{-2t}.
    [3 marks]
    (b)
    Find the distance travelled by PP while its speed falls from 88 m s−1^{-1} to 22 m s−1^{-1}.
    [4 marks]

    Total for question 3: 7 marks

  4. 4
    A spacecraft of mass mm moves directly away from the centre of the Earth. At distance xx from the centre of the Earth, the only force on the spacecraft is the gravitational attraction mgR2x2\frac{mgR^2}{x^2} towards the centre, where RR is the radius of the Earth and gg is the acceleration due to gravity at the Earth's surface. When x=2Rx=2R the spacecraft has speed uu, directed away from the Earth.
    (a)
    Show that, at distance xx from the centre of the Earth, the speed vv of the spacecraft satisfies v2=u2−gR+2gR2xv^2=u^2-gR+\frac{2gR^2}{x}.
    [6 marks]
    (b)
    Find the least value of uu, in terms of gg and RR, for which the spacecraft never returns to the Earth. Hence calculate this value in km s−1^{-1}, given that R=6.4×106R=6.4\times10^6 m and g=9.8g=9.8 m s−2^{-2}.
    [6 marks]

    Total for question 4: 12 marks

End of questions

Written by the Exaim team, led by Shaun Daswani (Head of Upper Secondary, Improve ME Institute; MSc Financial Mathematics, Imperial College London; BSc, UCL) and Jason Daswani (operational lead, Improve ME Institute; LSE).